# Challenge
Make a program that takes input of 3 non-negative integers: a result and 2 other values that once calculated results to the 3rd value.
- The program must figure out how to get the 2 first numbers to equivalence itself with the 3rd. It could be either addition, subtraction, multiplication, integer division, modulo and exponentiation.
- You can't change the places of the 2 variables when building the equation, meaning you can't get some value by intertwining in the methods excluding addition and multiplication.
- The returning value is the operator that makes the equation true (it's best to use some distinguishable character to separate it from the other methods).
- Use whatever characters you want to use to determine the method that makes the equation truthy.
- If multiple operators make the equation truthy, then output them in any order.
- What makes it true? If an equation exists within the 2 numbers that results to the value of the 3rd.
- What to return when it's false? Something but not nothing (whitespaces and newlines aren't allowed as such output).
- This is <a class="badge is-tag">code-golf</a> so the shortest program wins!
# Test Cases
```none
# Input (#, #, #)
// Output (+-*/%^ or .)
2 3 5
+
7 3 2
/
9 8 4
.
1 2 2
*
2 2 4
+ * ^
14 6 8
-
5 0 2
.
0 0 1
^
8 4 0
%
0 0 0
+ - *
```
