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This suggested edit was approved and applied to the post over 3 years ago by Quintec‭.

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Evaluate a single variable polynomial equation
  • # Challenge
  • Given a list of n numbers and x, compute $a + bx^1 + cx^{2} + ... + zx^{n-1}$, where a is the first value in the list, b is the second, etc. n is at most 256 and at least 0. The input value(s) can be any 32-bit float
  • Input can be in any format of choice, as long as it is a list of numbers and x. (And this'll likely stay this way, even if input rules change over time)
  • # Test inputs
  • `1.0`, `182` -> `1`<br/>
  • `1.0, 2.0`, `4` -> `9`<br/>
  • `2.5, 2.0`, `0.5` -> `3.5`<br/>
  • `1.0, 2.0, 3.0, 4.0`, `1.5` -> `24.25`<br/>
  • # Example ungolfed program (Rust)
  • ```rust
  • // dbg! is a logging function, prints the expression and it's output.
  • // Good for seeing what's happening
  • // Test setup
  • pub fn main() {
  • let inp: &[f32] = &[1.0, 2.0, 3.0, 4.0];
  • let x: f32 = 1.5;
  • dbg!(evaluate_polynomial(inp, x)); // take inputs, print result
  • }
  • // Actual challenge answer function
  • pub fn evaluate_polynomial(inp: &[f32], x: f32) -> f32 {
  • let mut accum: f32 = 0.0;
  • for (idx, val) in inp.iter().enumerate() {
  • // x.pow(idx) * val
  • accum += dbg!(x.powf(idx as f32) * val);
  • }
  • return accum;
  • }
  • ```
  • # Challenge
  • Given a list of n numbers and x, compute $a + bx^1 + cx^{2} + ... + zx^{n-1}$, where a is the first value in the list, b is the second, etc. n is at most 256 and at least 0. The input value(s) can be any 32-bit float
  • Input can be in any format of choice, as long as it is a list of numbers and x. (And this'll likely stay this way, even if input rules change over time)
  • # Test inputs
  • `[1.0]`, `182` -> `1`<br/>
  • `[1.0, 2.0]`, `4` -> `9`<br/>
  • `[2.5, 2.0]`, `0.5` -> `3.5`<br/>
  • `[1.0, 2.0, 3.0, 4.0]`, `1.5` -> `24.25`<br/>
  • # Example ungolfed program (Rust)
  • ```rust
  • // dbg! is a logging function, prints the expression and it's output.
  • // Good for seeing what's happening
  • // Test setup
  • pub fn main() {
  • let inp: &[f32] = &[1.0, 2.0, 3.0, 4.0];
  • let x: f32 = 1.5;
  • dbg!(evaluate_polynomial(inp, x)); // take inputs, print result
  • }
  • // Actual challenge answer function
  • pub fn evaluate_polynomial(inp: &[f32], x: f32) -> f32 {
  • let mut accum: f32 = 0.0;
  • for (idx, val) in inp.iter().enumerate() {
  • // x.pow(idx) * val
  • accum += dbg!(x.powf(idx as f32) * val);
  • }
  • return accum;
  • }
  • ```

Suggested over 3 years ago by user‭