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Comments on Are they abundant, deficient or perfect?

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Are they abundant, deficient or perfect?

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Abundant numbers are numbers which are less than their proper divisor sum. For example $18$ is abundant as $1 + 2 + 3 + 6 + 9 = 21 > 18$

Deficient numbers are numbers which are greater than their proper divisor sum. For example, $15$ is deficient as $1 + 3 + 5 = 9 < 15$

Perfect numbers are numbers wich are equal to their proper divisor sum. For example, $6$ is perfect as $1 + 2 + 3 = 6$.

You should take a positive integer $x \ge 12$ and output three lists. The lists should contain, in any order, the abundant numbers less than or equal to $x$, the deficient numbers less than or equal to $x$ and the perfect numbers less than or equal to $x$.

For example, if $x = 15$, the output could look like

[[12], [6], [1, 2, 3, 4, 5, 7, 8, 9, 10, 11, 13, 14, 15]]

This is code golf, so the shortest code in bytes wins

Test cases

49 -> [[12, 18, 20, 24, 30, 36, 40, 42, 48], [6, 28], [1, 2, 3, 4, 5, 7, 8, 9, 10, 11, 13, 14, 15, 16, 17, 19, 21, 22, 23, 25, 26, 27, 29, 31, 32, 33, 34, 35, 37, 38, 39, 41, 43, 44, 45, 46, 47, 49]]
32 -> [[12, 18, 20, 24, 30], [6, 28], [1, 2, 3, 4, 5, 7, 8, 9, 10, 11, 13, 14, 15, 16, 17, 19, 21, 22, 23, 25, 26, 27, 29, 31, 32]]
16 -> [[12], [6], [1, 2, 3, 4, 5, 7, 8, 9, 10, 11, 13, 14, 15, 16]]
29 -> [[12, 18, 20, 24], [6, 28], [1, 2, 3, 4, 5, 7, 8, 9, 10, 11, 13, 14, 15, 16, 17, 19, 21, 22, 23, 25, 26, 27, 29]]
23 -> [[12, 18, 20], [6], [1, 2, 3, 4, 5, 7, 8, 9, 10, 11, 13, 14, 15, 16, 17, 19, 21, 22, 23]]
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General comments (6 comments)
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Python 3, 235 185 141 118 bytes

a=[[],[],[]]
n=1;exec("d=sum(i for i in range(1,n)if n%i<1)-n;a[[[1,2][d<0],0][d>0]]+=n,;n+=1;"*int(input()))
print(a)

Try it online!

Golfed 50 bytes by @caird coinheringaahing. Golfed 44 bytes by @bastolki. Golfed another 23 bytes by @bastolki.

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[141 bytes](https://tio.run/##TY2xCsMgFEVn/QqXgI@4SLvUxvxIyaDGtA/aFzFm6NfbWCh0OdwDB256l8dKp1q9vU3X0OA... (2 comments)
General comments (1 comment)
General comments
caird coinheringaahing‭ wrote over 3 years ago · edited over 3 years ago