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Challenges

Comments on 99 Shortened Bottles of Beer

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99 Shortened Bottles of Beer

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Disclaimer

This challenge also exists in CGCC, but if you want to compete here (too), then hop in!

Challenge

Recreate "99 Bottles of Beer on the Wall", using the least bytes possible.

Lyrics:

99 bottles of beer on the wall, 99 bottles of beer.
Take one down and pass it around, 98 bottles of beer on the wall.

98 bottles of beer on the wall, 98 bottles of beer.
Take one down and pass it around, 97 bottles of beer on the wall.

97 bottles of beer on the wall, 97 bottles of beer.
Take one down and pass it around, 96 bottles of beer on the wall.

96 bottles of beer on the wall, 96 bottles of beer.
Take one down and pass it around, 95 bottles of beer on the wall.

95 bottles of beer on the wall, 95 bottles of beer.
Take one down and pass it around, 94 bottles of beer on the wall.

....

3 bottles of beer on the wall, 3 bottles of beer.
Take one down and pass it around, 2 bottles of beer on the wall.

2 bottles of beer on the wall, 2 bottles of beer.
Take one down and pass it around, 1 bottle of beer on the wall.

1 bottle of beer on the wall, 1 bottle of beer.
Go to the store and buy some more, 99 bottles of beer on the wall.

Rules

  • 0-byte answers aren't allowed. Although 1-byte answers are allowed while still abiding to not using loopholes, they won't be very interesting (unless you DO make it interesting).
  • Use any form of output in the program. Yes, the whole thing must be outputted up until you reach $n=1$.
  • Built-in functions and/or code for this specific challenge is pretty much allowed, only if you explain (even a little) how the code works (or not if you can't at all).
  • Shortest program of each language used is the winner.
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2 comment threads

Are leading or trailing newlines permitted? (2 comments)
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C (gcc), 232 bytes

f(n,w,p){printf("%i bottle%s of beer%s%s",n,"s"+(n<2)," on the wall"+w,p);}main(i){for(i=99;i;){f(i,0,", ");f(i,12,".\n");printf(i>1?"Take one down and pass it around, ":"Go to the store and buy some more, ");f(--i?:99,0,".\n\n");}}

Try it online!

Main golfing techniques:

  • The repetitive part has been put into a function

  • conditional strings are sometimes implemented using pointer arithmetic, using the fact that C strings are zero terminated character arrays

  • The code uses the implicit int rule

  • I'm passing a pointer through an int argument which then in turn is interpreted as a pointer by printf (not portable and definitely not clean; allows me to use the implicit int rule for that argument)

  • The gcc extension condition?:value (give condition unless that is zero, in which case give value) is used to save one character

  • The printf function is declared implicitly (which isn't guaranteed to work by any C standard, but works just fine in practice by any compiler that allows implicit declarations), saving the 18 characters that would otherwise be needed for #include<stdio.h> (including the mandatory line break following that directive)

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1 comment thread

Nice one (3 comments)
Nice one
Lundin‭ wrote over 2 years ago

Seems we were working on this simultaneously in C but you beat me with 12 :) Completely different solutions, I went bananas on the printf format string instead.

Lundin‭ wrote over 2 years ago · edited over 2 years ago

I'm realizing that your neat "s"+(n<2) trick would have shaved down my own solution quite a bit, but I'll refrain from shamelessly stealing it :) I have lots of stuff like %.*s i-1?8:7,w (print 7 characters of the string w otherwise 8) which didn't turn out too compact.

celtschk‭ wrote over 2 years ago

Actually I started with a loop containing a single printf statement (but no width specifications; just a lot of %1$s style stuff), but then found that putting the singular/plural logic into a separate function saves more space because I essentially repeated the same logic for i-1 as I couldn't decrement i in between the arguments. The "s"+(n<2) was in there from the very beginning, though.