Comments on Coat of Many Colours
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Coat of Many Colours
Challenge
Given a list of unique colour names as input, sort them in the order that they first appear in Joseph's Amazing Technicolour Dreamcoat.
Example
Input: green, blue, red, brown
Output: red, green, brown, blue
The full list of colours, in order, is:
1. red
2. yellow
3. green
4. brown
5. scarlet
6. black
7. ochre
8. peach
9. ruby
10. olive
11. violet
12. fawn
13. lilac
14. gold
15. chocolate
16. mauve
17. cream
18. crimson
19. silver
20. rose
21. azure
22. lemon
23. russet
24. grey
25. purple
26. white
27. pink
28. orange
29. blue
Or as an array of strings:
["red","yellow","green","brown","scarlet","black","ochre","peach","ruby","olive","violet","fawn","lilac","gold","chocolate","mauve","cream","crimson","silver","rose","azure","lemon","russet","grey","purple","white","pink","orange","blue"]
Rules
- You may take input by any reasonable, convenient means (e.g., an array of strings, a delimited string, individual strings), but please specify your input method in your answer.
- You may do the same for your output.
- The input will only ever contain colours from the above list.
- Your solution should be able to handle empty inputs.
- You may choose whether all words in the input are consistently uppercase, lowercase or title case but your output's casing must match your input's.
- This is code-golf so lowest byte count in each language wins.
- As always, standard loopholes are forbidden.
Test cases
Input: []
Output: []
Input: ["green", "blue", "red", "brown"]
Output: ["red", "green", "brown", "blue"]
Input: ["gold", "grey", "green"]
Output: ["green", "gold", "grey"]
Input: ["ruby","yellow","red","grey"]
Output: ["red", "yellow", "ruby", "grey"]
Input: ["gold", "green", "fawn", "white", "azure", "rose", "black", "purple", "orange", "silver", "ruby", "blue", "lilac", "crimson", "pink", "cream", "lemon", "russet", "grey", "olive", "violet", "mauve", "chocolate", "yellow", "peach", "brown", "ochre", "scarlet", "red"]
Output: ["red", "yellow", "green", "brown", "scarlet", "black", "ochre", "peach", "ruby", "olive", "violet", "fawn", "lilac", "gold", "chocolate", "mauve", "cream", "crimson", "silver", "rose", "azure", "lemon", "russet", "grey", "purple", "white", "pink", "orange", "blue"]
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Post
C (gcc), 301 bytes
Function taking in an array of null-terminated strings and the array's length.
#include <string.h>
#include <stdlib.h>
char*s="edellowreenrowncarletlackchreachubyliveioletawnilacoldhocolateauvereamrimsonilverosezuremonussetreyurplehiteinkrangelue";int g(const void*a,const void*b){return strstr(s,*(char**)a+1)-strstr(s,*(char**)b+1);}void f(char**a,int l){qsort(a,l,sizeof*a,g);}
I shamelessly stole the idea of removing the first two characters from user's solution. Note: My original solution had a bug where the wn from fawn matched the own from brown and broke the order. This updated solution only removes the first character, making rown and awn distinct.
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