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Challenges

Comments on Word Set Square

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Word Set Square

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Challenge

Given a string, e.g. Hello, do the following:

Mirror it:

Hello -> HelloolleH

and create a right triangle using it as the sides:

H         
ee        
l l       
l  l      
o   o     
o    o    
l     l   
l      l  
e       e 
HelloolleH

Which looks sort of like a set square.

That's it!

Scoring

This is code-golf. Shortest answer in each language wins.

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Python 3, 196 195 145 102 91 89 87 79 bytes

x=input();x+=x[::-1];i=-1
for c in x[:-1]:print(c*(i>-1)+" "*i+c);i+=1
print(x)

Try it online!

Golfed 50 bytes thanks to @celtschk's advice. Golfed another 43 bytes thanks to @celtschk's advice. Golfed another 11 bytes thanks to @celtschk's advice. Golfed another 2 bytes thanks to @celtschk's advice. Golfed 2 bytes thanks to @Moshi's advice. Golfed another 8 bytes thanks to @Moshi's advice.

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4 comment threads

Sub 80 (1 comment)
bool(i) -> (i>0) (1 comment)
Further golfing opportunity (5 comments)
You can save quite a few bytes here. First, you can replace `print(" ",end='')` with `print(end=" ... (1 comment)
You can save quite a few bytes here. First, you can replace `print(" ",end='')` with `print(end=" ...
celtschk‭ wrote about 3 years ago · edited about 3 years ago

You can save quite a few bytes here.

First, you can replace print(" ",end='') with print(end=" "), saving 3 bytes. But then, you can replace the whole j loop with print(end=" "*(k-2)). Then you can merge the two print statements into one: print(x[i],end=" "*(k-2)). Since now the if controls only one statement, you can put it right after the if i^0:. Furthermore, i^0 is the same as i.

Next, at the place it is used, k is always the same as i+1, therefore you can replace k-2 with i-1 and get rid of k.

You can shorten the first part, too, as the initial part of x is the same as s and never changed, and the only access to s past the end is when still x==s. Therefore you can read directly into x and ditch s.

Applying all those gets you down to 145 bytes