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Comments on Convert integer to English

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Convert integer to English

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Given a non-negative integer up to $999\,999\,999$, write it in English.

The input number can be in any form other than English (though you'll typically want to use the native integer type of your language).

The numbers must be formatted as follows:

  • Two-digit numbers must be written with dashes where applicable e.g. twenty-five, not twenty five.

  • powers of ten start with “one”, e.g. one hundred, not just hundred.

  • The tens/ones part, if not zero, must be separated from the hundreds part with and, e.g. two hundred and five, not two hundred five.

  • The above rules are applied also to the factors of thousand and million.

  • moreover the global tens/ones part has to be separated by and whenever anything larger is present, even if the hundreds part is missing.

  • Adjacent words must be separated by a single space, or a single dash without space where applicable.

  • Leading and/or trailing spaces are not allowed. However, if the result is printed, a single trailing newline (not preceded by any spaces) is allowed.

Ungolfed reference implementation

Test cases:

        0 zero
        1 one
        4 four
       10 ten
       16 sixteen
       42 forty-two
      125 one hundred and twenty-five
     1024 one thousand and twenty-four
     1100 one thousand one hundred
    12345 twelve thousand three hundred and forty-five
  1000000 one million
  1000001 one million and one
  7023000 seven million twenty-three thousand
 11012021 eleven million twelve thousand and twenty-one
999999999 nine hundred and ninety-nine million nine hundred and ninety-nine thousand nine hundred and ninety-nine
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LaTeX (2 comments)
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Python 3, 596 589 585 482 468 467 429 bytes

def f(x):
	s="";i="r fif six seven eigh nine";a=f"zero one two three four five six seven eight nine ten eleven twelve thir fou{i} twen thir fo{i}".split();t=1000;c=t*t
	if x>=c:s=f(x//c)+" million";x%=c
	if x>=t:s+=" "*(s>"")+f(x//t)+" thousand";x%=t
	if s*x:s+=" "
	n=x>99
	if n:s+=a[x//100]+" hundred";x%=100
	if s*x:s+=" "*n+"and "
	return x<20 and s+a[x]*(not(x<1)*s)+"teen"*(x>12)or s+a[x//10+18]+"ty"+("-"+a[x%10])*(x%10>0)

Try it online!

Golfed 7 bytes thanks to @celtschk's advice. Golfed a massive 103 bytes thanks to @Moshi's advice. Golfed another 14 bytes thanks to @Moshi's advice. Golfed 38 bytes thanks to @celtschk's advice.

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