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Comments on Looping counter

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Looping counter

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Looping counter

Create an infinite loop that outputs lines of asterisks, with each line containing one more asterisk. Instead of the asterisk, any printable, non-whitespace character can be used. However all lines need to use the same character.

The beginning of the output looks like this:

*
**
***
****
*****
******
*******
********
*********
**********
***********
************

An ungolfed Python implementation:

from itertools import count

for i in count(1):
    print('*'*i)
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posted over 2 years ago
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celtschk‭
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Output line 0. Input for starting line (1 comment)
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Haskell, 35 bytes

main=mapM putStrLn$iterate('*':)"*"

Attempt This Online!

55 -> 39, with orthoplex's idea.

39 -> 35 from orthoplex.

posted over 2 years ago
2y ago
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Razetime‭
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Neat solution, but that import is quite expensive. Maybe try something like ```haskell x="*":map('*... (3 comments)
Neat solution, but that import is quite expensive. Maybe try something like ```haskell x="*":map('*...
orthoplex‭ wrote over 2 years ago
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Neat solution, but that import is quite expensive. Maybe try something like

x="*":map('*':)x
main=mapM putStrLn x
Razetime‭ wrote over 2 years ago
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Good idea! I've used a similar idea in my edit.

orthoplex‭ wrote over 2 years ago
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oh sweet, we have a 35 then ^^

main=mapM putStrLn$iterate('*':)"*"