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Challenges

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Challenges Evaluate a single variable polynomial equation

Challenge Given a list of n numbers and x, compute $a + bx^1 + cx^{2} + ... + zx^{n-1}$, where a is the first value in the list, b is the second, etc. n is at most 256 and at least 0. The input va...

20 answers  ·  posted 4y ago by moony‭  ·  last activity 3y ago by south‭

Question code-golf math
#4: Post edited by user avatar user‭ · 2021-08-17T22:15:23Z (about 3 years ago)
Use [] because it wasn't clear where the list ended and where x was
Evaluate a single variable polynomial equation
  • # Challenge
  • Given a list of n numbers and x, compute $a + bx^1 + cx^{2} + ... + zx^{n-1}$, where a is the first value in the list, b is the second, etc. n is at most 256 and at least 0. The input value(s) can be any 32-bit float
  • Input can be in any format of choice, as long as it is a list of numbers and x. (And this'll likely stay this way, even if input rules change over time)
  • # Test inputs
  • `1.0`, `182` -> `1`<br/>
  • `1.0, 2.0`, `4` -> `9`<br/>
  • `2.5, 2.0`, `0.5` -> `3.5`<br/>
  • `1.0, 2.0, 3.0, 4.0`, `1.5` -> `24.25`<br/>
  • # Example ungolfed program (Rust)
  • ```rust
  • // dbg! is a logging function, prints the expression and it's output.
  • // Good for seeing what's happening
  • // Test setup
  • pub fn main() {
  • let inp: &[f32] = &[1.0, 2.0, 3.0, 4.0];
  • let x: f32 = 1.5;
  • dbg!(evaluate_polynomial(inp, x)); // take inputs, print result
  • }
  • // Actual challenge answer function
  • pub fn evaluate_polynomial(inp: &[f32], x: f32) -> f32 {
  • let mut accum: f32 = 0.0;
  • for (idx, val) in inp.iter().enumerate() {
  • // x.pow(idx) * val
  • accum += dbg!(x.powf(idx as f32) * val);
  • }
  • return accum;
  • }
  • ```
  • # Challenge
  • Given a list of n numbers and x, compute $a + bx^1 + cx^{2} + ... + zx^{n-1}$, where a is the first value in the list, b is the second, etc. n is at most 256 and at least 0. The input value(s) can be any 32-bit float
  • Input can be in any format of choice, as long as it is a list of numbers and x. (And this'll likely stay this way, even if input rules change over time)
  • # Test inputs
  • `[1.0]`, `182` -> `1`<br/>
  • `[1.0, 2.0]`, `4` -> `9`<br/>
  • `[2.5, 2.0]`, `0.5` -> `3.5`<br/>
  • `[1.0, 2.0, 3.0, 4.0]`, `1.5` -> `24.25`<br/>
  • # Example ungolfed program (Rust)
  • ```rust
  • // dbg! is a logging function, prints the expression and it's output.
  • // Good for seeing what's happening
  • // Test setup
  • pub fn main() {
  • let inp: &[f32] = &[1.0, 2.0, 3.0, 4.0];
  • let x: f32 = 1.5;
  • dbg!(evaluate_polynomial(inp, x)); // take inputs, print result
  • }
  • // Actual challenge answer function
  • pub fn evaluate_polynomial(inp: &[f32], x: f32) -> f32 {
  • let mut accum: f32 = 0.0;
  • for (idx, val) in inp.iter().enumerate() {
  • // x.pow(idx) * val
  • accum += dbg!(x.powf(idx as f32) * val);
  • }
  • return accum;
  • }
  • ```
#3: Post edited by user avatar moony‭ · 2020-11-15T07:02:51Z (almost 4 years ago)
  • # Challenge
  • Given a list of n numbers and x, compute $a + bx^1 + cx^{2} + ... + zx^{n-1}$, where a is the first value in the list, b is the second, etc. n is at most 256 and at least 0. The input value(s) can be any 32-bit float
  • Input can be in any format of choice, as long as it is a list of numbers and x. (And this'll likely stay this way, even if input rules change over time)
  • # Test inputs
  • `1.0`, `182` -> `1`<br/>
  • `1.0, 2.0`, `4` -> `9`<br/>
  • `2.5, 2.0`, `0.5` -> `3.5`<br/>
  • `1.0, 2.0, 3.0, 4.0`, `1.5` -> `24.25<br/>
  • # Example ungolfed program (Rust)
  • ```rust
  • // dbg! is a logging function, prints the expression and it's output.
  • // Good for seeing what's happening
  • // Test setup
  • pub fn main() {
  • let inp: &[f32] = &[1.0, 2.0, 3.0, 4.0];
  • let x: f32 = 1.5;
  • dbg!(evaluate_polynomial(inp, x)); // take inputs, print result
  • }
  • // Actual challenge answer function
  • pub fn evaluate_polynomial(inp: &[f32], x: f32) -> f32 {
  • let mut accum: f32 = 0.0;
  • for (idx, val) in inp.iter().enumerate() {
  • // x.pow(idx) * val
  • accum += dbg!(x.powf(idx as f32) * val);
  • }
  • return accum;
  • }
  • ```
  • # Challenge
  • Given a list of n numbers and x, compute $a + bx^1 + cx^{2} + ... + zx^{n-1}$, where a is the first value in the list, b is the second, etc. n is at most 256 and at least 0. The input value(s) can be any 32-bit float
  • Input can be in any format of choice, as long as it is a list of numbers and x. (And this'll likely stay this way, even if input rules change over time)
  • # Test inputs
  • `1.0`, `182` -> `1`<br/>
  • `1.0, 2.0`, `4` -> `9`<br/>
  • `2.5, 2.0`, `0.5` -> `3.5`<br/>
  • `1.0, 2.0, 3.0, 4.0`, `1.5` -> `24.25`<br/>
  • # Example ungolfed program (Rust)
  • ```rust
  • // dbg! is a logging function, prints the expression and it's output.
  • // Good for seeing what's happening
  • // Test setup
  • pub fn main() {
  • let inp: &[f32] = &[1.0, 2.0, 3.0, 4.0];
  • let x: f32 = 1.5;
  • dbg!(evaluate_polynomial(inp, x)); // take inputs, print result
  • }
  • // Actual challenge answer function
  • pub fn evaluate_polynomial(inp: &[f32], x: f32) -> f32 {
  • let mut accum: f32 = 0.0;
  • for (idx, val) in inp.iter().enumerate() {
  • // x.pow(idx) * val
  • accum += dbg!(x.powf(idx as f32) * val);
  • }
  • return accum;
  • }
  • ```
#2: Post edited by user avatar xnor‭ · 2020-11-13T23:10:23Z (almost 4 years ago)
  • # Challenge
  • Given a list of n numbers and x, compute $a + bx^1 + cx^{2} + zx^{n-1}$, where a is the first value in the list, b is the second, etc. n is at most 256 and at least 0. The input value(s) can be any 32-bit float
  • Input can be in any format of choice, as long as it is a list of numbers and x. (And this'll likely stay this way, even if input rules change over time)
  • # Test inputs
  • `1.0`, `182` -> `1`<br/>
  • `1.0, 2.0`, `4` -> `9`<br/>
  • `2.5, 2.0`, `0.5` -> `3.5`<br/>
  • `1.0, 2.0, 3.0, 4.0`, `1.5` -> `24.25<br/>
  • # Example ungolfed program (Rust)
  • ```rust
  • // dbg! is a logging function, prints the expression and it's output.
  • // Good for seeing what's happening
  • // Test setup
  • pub fn main() {
  • let inp: &[f32] = &[1.0, 2.0, 3.0, 4.0];
  • let x: f32 = 1.5;
  • dbg!(evaluate_polynomial(inp, x)); // take inputs, print result
  • }
  • // Actual challenge answer function
  • pub fn evaluate_polynomial(inp: &[f32], x: f32) -> f32 {
  • let mut accum: f32 = 0.0;
  • for (idx, val) in inp.iter().enumerate() {
  • // x.pow(idx) * val
  • accum += dbg!(x.powf(idx as f32) * val);
  • }
  • return accum;
  • }
  • ```
  • # Challenge
  • Given a list of n numbers and x, compute $a + bx^1 + cx^{2} + ... + zx^{n-1}$, where a is the first value in the list, b is the second, etc. n is at most 256 and at least 0. The input value(s) can be any 32-bit float
  • Input can be in any format of choice, as long as it is a list of numbers and x. (And this'll likely stay this way, even if input rules change over time)
  • # Test inputs
  • `1.0`, `182` -> `1`<br/>
  • `1.0, 2.0`, `4` -> `9`<br/>
  • `2.5, 2.0`, `0.5` -> `3.5`<br/>
  • `1.0, 2.0, 3.0, 4.0`, `1.5` -> `24.25<br/>
  • # Example ungolfed program (Rust)
  • ```rust
  • // dbg! is a logging function, prints the expression and it's output.
  • // Good for seeing what's happening
  • // Test setup
  • pub fn main() {
  • let inp: &[f32] = &[1.0, 2.0, 3.0, 4.0];
  • let x: f32 = 1.5;
  • dbg!(evaluate_polynomial(inp, x)); // take inputs, print result
  • }
  • // Actual challenge answer function
  • pub fn evaluate_polynomial(inp: &[f32], x: f32) -> f32 {
  • let mut accum: f32 = 0.0;
  • for (idx, val) in inp.iter().enumerate() {
  • // x.pow(idx) * val
  • accum += dbg!(x.powf(idx as f32) * val);
  • }
  • return accum;
  • }
  • ```
#1: Initial revision by user avatar moony‭ · 2020-11-13T22:53:25Z (almost 4 years ago)
Evaluate a single variable polynomial equation
# Challenge

Given a list of n numbers and x, compute $a + bx^1 + cx^{2} +  zx^{n-1}$, where a is the first value in the list, b is the second, etc. n is at most 256 and at least 0. The input value(s) can be any 32-bit float

Input can be in any format of choice, as long as it is a list of numbers and x. (And this'll likely stay this way, even if input rules change over time)
# Test inputs
`1.0`, `182` -> `1`<br/>
`1.0, 2.0`, `4` -> `9`<br/>
`2.5, 2.0`, `0.5` -> `3.5`<br/>
`1.0, 2.0, 3.0, 4.0`, `1.5` -> `24.25<br/>

# Example ungolfed program (Rust)
```rust
// dbg! is a logging function, prints the expression and it's output.
// Good for seeing what's happening

// Test setup
pub fn main() {
    let inp: &[f32] = &[1.0, 2.0, 3.0, 4.0];
    let x: f32 = 1.5;
    dbg!(evaluate_polynomial(inp, x)); // take inputs, print result	
}

// Actual challenge answer function
pub fn evaluate_polynomial(inp: &[f32], x: f32) -> f32 {
    let mut accum: f32 = 0.0;

    for (idx, val) in inp.iter().enumerate() {
        // x.pow(idx) * val
        accum += dbg!(x.powf(idx as f32) * val);
    }

    return accum;
}
```