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Given an positive integer $n$, return the least positive integer $k$ such that the $k$th partial sum of the harmonic series is greater than or equal to $n$. For example, if $n = 2$, then $k = 4$, b...
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code-golf
#3: Post edited
by
General Sebast1an
·
2021-08-12T19:02:56Z (about 3 years ago)
Partial Sums of Harmonic Series
- Given an positive integer $n$, return the least positive integer $k$ such that the $k$th partial sum of the [harmonic series](https://en.wikipedia.org/wiki/Harmonic_series_(mathematics)) is greater than or equal to $n$. For example, if $n = 2$, then $k = 4$, because $1 + \frac{1}{2} + \frac{1}{3} + \frac{1}{4} = \frac{25}{12} > 2$.
- # More Input/Output Examples
- ```
- Input -> Output
- 1 -> 1
- 3 -> 11
- 4 -> 31
- ```
This is code-golf, so shortest code wins.
- Given an positive integer $n$, return the least positive integer $k$ such that the $k$th partial sum of the [harmonic series](https://en.wikipedia.org/wiki/Harmonic_series_(mathematics)) is greater than or equal to $n$. For example, if $n = 2$, then $k = 4$, because $1 + \frac{1}{2} + \frac{1}{3} + \frac{1}{4} = \frac{25}{12} > 2$.
- # More Input/Output Examples
- ```
- Input -> Output
- 1 -> 1
- 3 -> 11
- 4 -> 31
- ```
- This is <a class="badge is-tag">code-golf</a>, so shortest code wins.
#2: Post edited
by
Quintec
·
2021-01-29T12:59:38Z (almost 4 years ago)
Given an positive integer $n$, return an integer $k$ such that the $k$th partial sum of the [harmonic series](https://en.wikipedia.org/wiki/Harmonic_series_(mathematics)) is greater than or equal to $n$. For example, if $n = 2$, then $k = 4$, because $1 + \frac{1}{2} + \frac{1}{3} + \frac{1}{4} = \frac{25}{12} > 2$.- # More Input/Output Examples
- ```
- Input -> Output
- 1 -> 1
- 3 -> 11
- 4 -> 31
- ```
- This is code-golf, so shortest code wins.
- Given an positive integer $n$, return the least positive integer $k$ such that the $k$th partial sum of the [harmonic series](https://en.wikipedia.org/wiki/Harmonic_series_(mathematics)) is greater than or equal to $n$. For example, if $n = 2$, then $k = 4$, because $1 + \frac{1}{2} + \frac{1}{3} + \frac{1}{4} = \frac{25}{12} > 2$.
- # More Input/Output Examples
- ```
- Input -> Output
- 1 -> 1
- 3 -> 11
- 4 -> 31
- ```
- This is code-golf, so shortest code wins.
#1: Initial revision
by
Quintec
·
2020-11-15T17:41:34Z (almost 4 years ago)
Partial Sums of Harmonic Series
Given an positive integer $n$, return an integer $k$ such that the $k$th partial sum of the [harmonic series](https://en.wikipedia.org/wiki/Harmonic_series_(mathematics)) is greater than or equal to $n$. For example, if $n = 2$, then $k = 4$, because $1 + \frac{1}{2} + \frac{1}{3} + \frac{1}{4} = \frac{25}{12} > 2$.
# More Input/Output Examples
```
Input -> Output
1 -> 1
3 -> 11
4 -> 31
```
This is code-golf, so shortest code wins.