Challenges

# Golf me a polygonal loader

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Given three positive integers as input, animate an ascii-art polygonal loading symbol on the screen.

## Intro

Using the first input $n$, Take one the following regular polygons:

                           * * *
*     *
* * *    *       *
*     *   *       *
*    * * *  *       *  *       *
* *   *   *   *     *    *     *
* * *  * * *    * * *      * * *


And draw it with the correct side length $l$.

Given load length $d$ lesser than it's perimeter, create it's loading animation as follows:

• Start at any one of the topmost corners, and draw the bounding line till it's length is $d$.
• Then, shift the position by 1 clockwise and do the next step.

For example, $n=3,l=3,d=4$ would result in the following steps:

  *                        *       *       *
*  →    *  →   *    →  *    →  * *  →  * *  → . . .
* *   * * *    * * *   * *     *           *


## Further details(important):

• You are guaranteed that $n∊(3,4,6,8)$
• You are guaranteed that $l≥3.$
• You are guaranteed that $d<l×n.$
• There must be a delay of at least 0.1 s between each step. You can have a delay of up to 10 seconds.
• Your language is allowed to output a list of steps infinitely if and only if it cannot clear the screen or do something similar.
• If so, there must be at least 2 newlines between each step.
• This is not graphical-output.

## Scoring

This is code-golf. Shortest answer in each language wins.

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# JavaScript (Browser), 670 bytes

for(_="=1,w=):=0,w(=f(||(.joinw?q-w?q=-w(a,b=>A(L*5,a),g.innerText=N=L=D=T,I=,c,d)a-d?I,b(d,cd+1c,A=)I(a,(x,y)[...y,b(x)],[](U=_(Kf=({value:a})a==[a|]+[]&&aKQnFlZdOtQ-N|F-L|Z-D|O-T&&(B=Q,e=F,H=Z,V=O,K&=(V>0&V<61&[3,4,6,8].includes(B)&e>1&e<101&H>0&H<=B*(e-1)K&&(N=Q,L=F,D=Z,T=O,X=N-4&&L,Y,WE=N==3,M=1)R=requestAnimationFrame,N?(s=' ')x=X,y=Y,q=W,E,m=M,I(D,i(s[y][x]='*',m++-Lm=2,N<4?w<0?1:w?(q=-1q-1N<6?w?(q,qN<8?w::q:q?q+ww:q:qx+=q*(?2:1y+=w,iX=x,Y=y,W=q,E=w,M=m))s.map(aa)\\n(''T-60?setTimeout(_R(U1e3/T-16R(U)))()";G=/[-]/.exec(_);)with(_.split(G))_=join(shift());eval(_)
`

Try it online!

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