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Python 3, 34 bytes f=lambda x:[f(y)for y in range(x)] Try it online! -9 bytes thanks to Moshi Unfortunately, I cannot use Python sets, because sets are unhashable and thus cannot be put int...
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#2: Post edited
by
hyper-neutrino
·
2021-07-26T14:11:44Z (over 3 years ago)
# [Python 3], 43 bytes- <!-- language-all: lang-python -->
f=lambda x:x and[f(y)for y in range(x)]or[][Try it online!][TIO-ko0e8puq]- [Python 3]: https://docs.python.org/3/
[TIO-ko0e8puq]: https://tio.run/##K6gsycjPM/7/P802JzE3KSVRocKqQiExLyU6TaNSMy2/SKFSITNPoSgxLz1Vo0IzNr8oOvY/SDgTIWxooGnFxVlQlJlXopGmkamp@R8A "Python 3 – Try It Online"- Unfortunately, I cannot use Python sets, because sets are unhashable and thus cannot be put into sets.
- # [Python 3], 34 bytes
- <!-- language-all: lang-python -->
- f=lambda x:[f(y)for y in range(x)]
- [Try it online!][TIO-krkpki3w]
- [Python 3]: https://docs.python.org/3/
- [TIO-krkpki3w]: https://tio.run/##K6gsycjPM/7/P802JzE3KSVRocIqOk2jUjMtv0ihUiEzT6EoMS89VaNCM/Y/SCgTIWRooGnFxVlQlJlXopGmkamp@R8A "Python 3 – Try It Online"
- -9 bytes thanks to Moshi
- Unfortunately, I cannot use Python sets, because sets are unhashable and thus cannot be put into sets.
#1: Initial revision
by
hyper-neutrino
·
2021-04-27T19:00:04Z (over 3 years ago)
# [Python 3], 43 bytes
<!-- language-all: lang-python -->
f=lambda x:x and[f(y)for y in range(x)]or[]
[Try it online!][TIO-ko0e8puq]
[Python 3]: https://docs.python.org/3/
[TIO-ko0e8puq]: https://tio.run/##K6gsycjPM/7/P802JzE3KSVRocKqQiExLyU6TaNSMy2/SKFSITNPoSgxLz1Vo0IzNr8oOvY/SDgTIWxooGnFxVlQlJlXopGmkamp@R8A "Python 3 – Try It Online"
Unfortunately, I cannot use Python sets, because sets are unhashable and thus cannot be put into sets.