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A number adder, not a death adder

+3
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Create a program P1 which takes as input a base 10 number N1 (the numbers for the variables are important). Given N1, P1 will print a program P2. P2 will take as input a base 10 number N2 and output N1+N2.

P1 and P2 have to be in the same language.

If your language doesn't have STDIN, for P1 and P2 you may specify a placeholder in your answer where the "input" would be.

The person who creates the shortest scoring program wins. Have fun, everyone!

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Are [functions](https://tio.run/##y0osSyxOLsosKNHNy09J/Z9m@z/P1i61LDFHIwHIUKnOq9XOS9D8n5yfV5yfk6qXk5@... (2 comments)

9 answers

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Japt, 4 bytes

P1 is:

+"+U

Try it

Which outputs P2, where N1 is the input from P1:

N1+U

Try it

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Vyxal , 3 bytes

?\?

Try it Online!

Outputs N1?, which when run with the same flag as P1, will add the two inputs together.

Try it Online!

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+2
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Haskell, 64 bytes

main=do a<-getLine;putStr$"main=getLine>>=print.("++a++"+).read"

Try it online!

Run both programs

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+1
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C (gcc), 87 bytes

P1:

i;main(){scanf("%d",&i);printf("i;main(){scanf(\"%%d\",&i);printf(\"%%d\",%d+i);}",i);}

Try it online!

Generated P2 for input 10:

i;main(){scanf("%d",&i);printf("%d",10+i);}

Try it online!

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+1
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Ahead, 10 bytes

IO"@O+I"W@

This prints N1I+0@.

Try it online!

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+1
−0

Python 3, 58 39 bytes

P1:

print(f"print(int(input())+{input()})")

Try it online!

P2 (given I inputted 10, 30 22 bytes):

print(int(input())+10)

Try it online!

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39 bytes (1 comment)
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Rockstar, 40 bytes

listen to N
say "listen to N
say N-0+"+N

Which outputs P2, where X is the input from P1:

listen to N
say N-0+X

Try it here (Code will need to be pasted in)

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PHP, 58 28 bytes

P1:

<?="<?=\$argv[1]+$argv[1];";

Try it online!

Golfed 30 bytes thanks to @Shaggy's advice.

P2 (given I inputted 10):

<?=$argv[1]+10;

Try it online!

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28 bytes (1 comment)
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Lua, 51 bytes

P1:

print("print(tonumber(io.read())+"..io.read()..")")

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P2 (given I inputted 10, 29 bytes):

print(tonumber(io.read())+10)

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