Code Golf

#5: Post edited by

General Sebast1an‭ · 2021-08-11T14:16:15Z (over 2 years ago)

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# [C (clang)], 59 bytes
c;f(int a,(*b)(int,int)){for(c=a;a>1;)c=b(--a,c);return c;}
[Try it online!][TIO-ks7earpp]
This program written by [**@Hakerh400**](https://codegolf.codidact.com/users/53579) in the comments basically how the other answers before this post existed actually did it, by a reduction sort of method. I'd like to thank them for making such program and the amount of bytes it literally shaved compared to the program below.
---------
# [C (clang)], <s>142</s> 103 bytes
i,j;f(a,b){if(b==42){j=1;}for(i=1;i<=a;i++){if(b==43){j+=i;}if(b==42){j*=i;}if(b==94){j^=i;}}return j;}
[Try it online!][TIO-ks7e7ke0]
I wanted to try to make something similar to [this](https://codegolf.codidact.com/posts/283268/283277#answer-283277), but with whatever Python has that C doesn't, I couldn't do so.
Instead, I chose to make a function. It works differently from the others, but it's all I could do.
Ungolfed form of the function with comments:
```c
int f(int num, char operator){ // Assign a function with 2 parameters: a number and character for operations
int x, result = 0; // Assign 2 integers: the succeeding number and the base
if(operator == '*' || operator == '/'){result = 1;} // Check if the character resembles multiplication or division; if so, set base as 1
for(x = 1; x <= num; x++){ // Start a loop to prompt the calculation that satisfies the challenge
if(operator == 43){result += x;} // Addition
if(operator == 42){result *= x;} // Multiplication
if(operator == 94){result ^= x;} // XOR
}
return result; // Return the result
}
```
[C (clang)]: http://clang.llvm.org/
[TIO-ks7e7ke0]: https://tio.run/##TYtBDoIwFAXXcAqCwbRSjSgb86lHISmF6idYTIEEQnr2Wl2ouzeTeXIvO6FvboNadlPdRMUw1tgf7leHrAVFBKvoiopUnOcnurY8A6t6Q9APLLgATNNvcPZByhHs32H340vuuXyzNc04GR21YN0CD4GazHQNg0EKrUicYCJjtp3ZdqEQBk@DevzomCkys4V6a112LF8 "C (clang) – Try It Online"
[TIO-ks7earpp]: https://tio.run/##fc7RCoIwFAbge5/iYAQ7NqMCr5Y@SnC2uRJ0hikI4rOviXVT6sXgsI//nF/FqiR7d7vCqrLTOVxfrS7q4yNzShhW2BaIs0jiNHL/EAdTN0ylJCg7C1SpZHFMXKFo8rZrLCgxOtKaEQeJA3x@CQ4gBYxB1ZV/FM3U@8W/dJspqKiwrMchAHg2vodh4V5DyMGwMwfwBxHFAiZbOCV9n/XkKk5JX3cZL1uYLOO89cS/Nro3 "C (clang) – Try It Online"

# [C (clang)], 59 bytes
c;f(int a,(*b)(int,int)){for(c=a;a>1;)c=b(--a,c);return c;}
[Try it online!][TIO-ks7earpp]
This program written by [**@Hakerh400**](https://codegolf.codidact.com/users/53579) in the comments is basically how the other answers before this post existed actually did it, by a reduction sort of method. I'd like to thank them for making such program and the amount of bytes it literally shaved compared to the program below.
---------
# [C (clang)], <s>142</s> 103 bytes
i,j;f(a,b){if(b==42){j=1;}for(i=1;i<=a;i++){if(b==43){j+=i;}if(b==42){j*=i;}if(b==94){j^=i;}}return j;}
[Try it online!][TIO-ks7e7ke0]
I wanted to try to make something similar to [this](https://codegolf.codidact.com/posts/283268/283277#answer-283277), but with whatever Python has that C doesn't, I couldn't do so.
Instead, I chose to make a function. It works differently from the others, but it's all I could do.
Ungolfed form of the function with comments:
```c
int f(int num, char operator){ // Assign a function with 2 parameters: a number and character for operations
int x, result = 0; // Assign 2 integers: the succeeding number and the base
if(operator == '*' || operator == '/'){result = 1;} // Check if the character resembles multiplication or division; if so, set base as 1
for(x = 1; x <= num; x++){ // Start a loop to prompt the calculation that satisfies the challenge
if(operator == 43){result += x;} // Addition
if(operator == 42){result *= x;} // Multiplication
if(operator == 94){result ^= x;} // XOR
}
return result; // Return the result
}
```
[C (clang)]: http://clang.llvm.org/
[TIO-ks7e7ke0]: https://tio.run/##TYtBDoIwFAXXcAqCwbRSjSgb86lHISmF6idYTIEEQnr2Wl2ouzeTeXIvO6FvboNadlPdRMUw1tgf7leHrAVFBKvoiopUnOcnurY8A6t6Q9APLLgATNNvcPZByhHs32H340vuuXyzNc04GR21YN0CD4GazHQNg0EKrUicYCJjtp3ZdqEQBk@DevzomCkys4V6a112LF8 "C (clang) – Try It Online"
[TIO-ks7earpp]: https://tio.run/##fc7RCoIwFAbge5/iYAQ7NqMCr5Y@SnC2uRJ0hikI4rOviXVT6sXgsI//nF/FqiR7d7vCqrLTOVxfrS7q4yNzShhW2BaIs0jiNHL/EAdTN0ylJCg7C1SpZHFMXKFo8rZrLCgxOtKaEQeJA3x@CQ4gBYxB1ZV/FM3U@8W/dJspqKiwrMchAHg2vodh4V5DyMGwMwfwBxHFAiZbOCV9n/XkKk5JX3cZL1uYLOO89cS/Nro3 "C (clang) – Try It Online"

#4: Post edited by

General Sebast1an‭ · 2021-08-11T12:02:14Z (over 2 years ago)

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~~# [C (clang)], 142 bytes~~
i,j;f(a,b){if(b==42||b==47){j=1;}for(i=1;i<=a;i++){if(b==43){j+=i;}if(b==45){j-=i;}if(b==42){j*=i;}if(b==47){j/=i;}if(b==94){j^=i;}}return j;}
~~[Try it online!][TIO-ks75bste]~~
I wanted to try to make something similar to [this](https://codegolf.codidact.com/posts/283268/283277#answer-283277), but with whatever Python has that C doesn't, I couldn't do so.
~~Instead, I chose to make a function that implements 5 operations. It works differently from the others, but it's all I could do.~~
Ungolfed form of the function with comments:
```c
int f(int num, char operator){ // Assign a function with 2 parameters: a number and character for operations
int x, result = 0; // Assign 2 integers: the succeeding number and the base
if(operator == '*' || operator == '/'){result = 1;} // Check if the character resembles multiplication or division; if so, set base as 1
for(x = 1; x <= num; x++){ // Start a loop to prompt the calculation that satisfies the challenge
if(operator == 43){result += x;} // Addition
~~if(operator == 45){result -= x;} // Subtraction~~
if(operator == 42){result *= x;} // Multiplication
~~if(operator == 47){result /= x;} // Division~~
if(operator == 94){result ^= x;} // XOR
}
return result; // Return the result
}
```
**Question**: Should I delete the division part? It seems useless.
[C (clang)]: http://clang.llvm.org/
[TIO-ks75bste]: https://tio.run/##TczhCoIwFAXg3/UUYihbzkorIuZ6FGFOV1dsxVJQdM9uM6L8dc93OFwRioqr67gCJaomL5zkVefw2NwuI5CSSsRJhnuQKGPsEA/DdE64L1lEjXxoBDZAwjiFIPjt9nYQMKDm66N1OHNsvZ55erj9@3ywTicbXdSNVk5JzdjROweFWtwvFy/BlUSuB55wid8Sv8N0uXhqUPWndolELemwbc0Y7dI3 "C (clang) – Try It Online"

# [C (clang)], 59 bytes
c;f(int a,(*b)(int,int)){for(c=a;a>1;)c=b(--a,c);return c;}
[Try it online!][TIO-ks7earpp]
This program written by [**@Hakerh400**](https://codegolf.codidact.com/users/53579) in the comments basically how the other answers before this post existed actually did it, by a reduction sort of method. I'd like to thank them for making such program and the amount of bytes it literally shaved compared to the program below.
---------
# [C (clang)], <s>142</s> 103 bytes

i,j;f(a,b){if(b==42){j=1;}for(i=1;i<=a;i++){if(b==43){j+=i;}if(b==42){j*=i;}if(b==94){j^=i;}}return j;}
[Try it online!][TIO-ks7e7ke0]
I wanted to try to make something similar to [this](https://codegolf.codidact.com/posts/283268/283277#answer-283277), but with whatever Python has that C doesn't, I couldn't do so.
Instead, I chose to make a function. It works differently from the others, but it's all I could do.
Ungolfed form of the function with comments:
```c
int f(int num, char operator){ // Assign a function with 2 parameters: a number and character for operations
int x, result = 0; // Assign 2 integers: the succeeding number and the base
if(operator == '*' || operator == '/'){result = 1;} // Check if the character resembles multiplication or division; if so, set base as 1
for(x = 1; x <= num; x++){ // Start a loop to prompt the calculation that satisfies the challenge
if(operator == 43){result += x;} // Addition
if(operator == 42){result *= x;} // Multiplication
if(operator == 94){result ^= x;} // XOR
}
return result; // Return the result
}
```
[C (clang)]: http://clang.llvm.org/
[TIO-ks7e7ke0]: https://tio.run/##TYtBDoIwFAXXcAqCwbRSjSgb86lHISmF6idYTIEEQnr2Wl2ouzeTeXIvO6FvboNadlPdRMUw1tgf7leHrAVFBKvoiopUnOcnurY8A6t6Q9APLLgATNNvcPZByhHs32H340vuuXyzNc04GR21YN0CD4GazHQNg0EKrUicYCJjtp3ZdqEQBk@DevzomCkys4V6a112LF8 "C (clang) – Try It Online"
[TIO-ks7earpp]: https://tio.run/##fc7RCoIwFAbge5/iYAQ7NqMCr5Y@SnC2uRJ0hikI4rOviXVT6sXgsI//nF/FqiR7d7vCqrLTOVxfrS7q4yNzShhW2BaIs0jiNHL/EAdTN0ylJCg7C1SpZHFMXKFo8rZrLCgxOtKaEQeJA3x@CQ4gBYxB1ZV/FM3U@8W/dJspqKiwrMchAHg2vodh4V5DyMGwMwfwBxHFAiZbOCV9n/XkKk5JX3cZL1uYLOO89cS/Nro3 "C (clang) – Try It Online"

#3: Post edited by

General Sebast1an‭ · 2021-08-11T07:18:53Z (over 2 years ago)

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# [C (clang)], 142 bytes
i,j;f(a,b){if(b==42||b==47){j=1;}for(i=1;i<=a;i++){if(b==43){j+=i;}if(b==45){j-=i;}if(b==42){j*=i;}if(b==47){j/=i;}if(b==94){j^=i;}}return j;}
[Try it online!][TIO-ks75bste]
I wanted to try to make something similar to [this](https://codegolf.codidact.com/posts/283268/283277#answer-283277), but with whatever Python has that C doesn't, I couldn't do so.
Instead, I chose to make a function that implements 5 operations. It works differently from the others, but it's all I could do.
Ungolfed form of the function with comments:
```c
int f(int num, char operator){ // Assign a function with 2 parameters: a number and character for operations
int x, result = 0; // Assign 2 integers: the succeeding number and the base
if(operator == '*' || operator == '/'){result = 1;} // Check if the character resembles multiplication or division; if so, set base as 1
for(x = 1; x <= num; x++){ // Start a loop to prompt the calculation that satisfies the challenge
if(operator == 43){result += x;} // Addition
if(operator == 45){result -= x;} // Subtraction
if(operator == 42){result *= x;} // Multiplication
if(operator == 47){result /= x;} // Division
if(operator == 94){result ^= x;} // XOR
}
return result; // Return the result
}
```
[C (clang)]: http://clang.llvm.org/
[TIO-ks75bste]: https://tio.run/##TczhCoIwFAXg3/UUYihbzkorIuZ6FGFOV1dsxVJQdM9uM6L8dc93OFwRioqr67gCJaomL5zkVefw2NwuI5CSSsRJhnuQKGPsEA/DdE64L1lEjXxoBDZAwjiFIPjt9nYQMKDm66N1OHNsvZ55erj9@3ywTicbXdSNVk5JzdjROweFWtwvFy/BlUSuB55wid8Sv8N0uXhqUPWndolELemwbc0Y7dI3 "C (clang) – Try It Online"

# [C (clang)], 142 bytes
i,j;f(a,b){if(b==42||b==47){j=1;}for(i=1;i<=a;i++){if(b==43){j+=i;}if(b==45){j-=i;}if(b==42){j*=i;}if(b==47){j/=i;}if(b==94){j^=i;}}return j;}
[Try it online!][TIO-ks75bste]
I wanted to try to make something similar to [this](https://codegolf.codidact.com/posts/283268/283277#answer-283277), but with whatever Python has that C doesn't, I couldn't do so.
Instead, I chose to make a function that implements 5 operations. It works differently from the others, but it's all I could do.
Ungolfed form of the function with comments:
```c
int f(int num, char operator){ // Assign a function with 2 parameters: a number and character for operations
int x, result = 0; // Assign 2 integers: the succeeding number and the base
if(operator == '*' || operator == '/'){result = 1;} // Check if the character resembles multiplication or division; if so, set base as 1
for(x = 1; x <= num; x++){ // Start a loop to prompt the calculation that satisfies the challenge
if(operator == 43){result += x;} // Addition
if(operator == 45){result -= x;} // Subtraction
if(operator == 42){result *= x;} // Multiplication
if(operator == 47){result /= x;} // Division
if(operator == 94){result ^= x;} // XOR
}
return result; // Return the result
}
```
**Question**: Should I delete the division part? It seems useless.
[C (clang)]: http://clang.llvm.org/
[TIO-ks75bste]: https://tio.run/##TczhCoIwFAXg3/UUYihbzkorIuZ6FGFOV1dsxVJQdM9uM6L8dc93OFwRioqr67gCJaomL5zkVefw2NwuI5CSSsRJhnuQKGPsEA/DdE64L1lEjXxoBDZAwjiFIPjt9nYQMKDm66N1OHNsvZ55erj9@3ywTicbXdSNVk5JzdjROweFWtwvFy/BlUSuB55wid8Sv8N0uXhqUPWndolELemwbc0Y7dI3 "C (clang) – Try It Online"

#2: Post edited by

General Sebast1an‭ · 2021-08-11T07:17:06Z (over 2 years ago)

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# [C (clang)], 142 bytes
i,j;f(a,b){if(b==42||b==47){j=1;}for(i=1;i<=a;i++){if(b==43){j+=i;}if(b==45){j-=i;}if(b==42){j*=i;}if(b==47){j/=i;}if(b==94){j^=i;}}return j;}
[Try it online!][TIO-ks75bste]
I wanted to try to make something similar to [this](https://codegolf.codidact.com/posts/283268/283277#answer-283277), but with whatever Python has that C doesn't, I couldn't do so.
Instead, I chose to make a function that implements 5 operations. It works differently from the others, but it's all I could do.
Ungolfed form of the function with comments:
```c
int f(int num, char operator){ // Assign a function with 2 parameters: a number and character for operations
int x, result = 0; // Assign 2 integers: the succeeding number and the base
if(operator == '*' || operator == '/'){result = 1;} // Check if the character resembles multiplication or division; if so, set base as 1
for(x = 1; x <= num; x++){ // Start a loop to prompt the calculation that satisfies the challenge
~~if(b==43){result+=x;} // Addition~~
~~if(b==45){result-=x;} // Subtraction~~
~~if(b==42){result*=x;} // Multiplication~~
~~if(b==47){result/=x;} // Division~~
~~if(b==94){result^=x;} // XOR~~
}
return result; // Return the result
}
```
[C (clang)]: http://clang.llvm.org/
[TIO-ks75bste]: https://tio.run/##TczhCoIwFAXg3/UUYihbzkorIuZ6FGFOV1dsxVJQdM9uM6L8dc93OFwRioqr67gCJaomL5zkVefw2NwuI5CSSsRJhnuQKGPsEA/DdE64L1lEjXxoBDZAwjiFIPjt9nYQMKDm66N1OHNsvZ55erj9@3ywTicbXdSNVk5JzdjROweFWtwvFy/BlUSuB55wid8Sv8N0uXhqUPWndolELemwbc0Y7dI3 "C (clang) – Try It Online"

# [C (clang)], 142 bytes
i,j;f(a,b){if(b==42||b==47){j=1;}for(i=1;i<=a;i++){if(b==43){j+=i;}if(b==45){j-=i;}if(b==42){j*=i;}if(b==47){j/=i;}if(b==94){j^=i;}}return j;}
[Try it online!][TIO-ks75bste]
I wanted to try to make something similar to [this](https://codegolf.codidact.com/posts/283268/283277#answer-283277), but with whatever Python has that C doesn't, I couldn't do so.
Instead, I chose to make a function that implements 5 operations. It works differently from the others, but it's all I could do.
Ungolfed form of the function with comments:
```c
int f(int num, char operator){ // Assign a function with 2 parameters: a number and character for operations
int x, result = 0; // Assign 2 integers: the succeeding number and the base
if(operator == '*' || operator == '/'){result = 1;} // Check if the character resembles multiplication or division; if so, set base as 1
for(x = 1; x <= num; x++){ // Start a loop to prompt the calculation that satisfies the challenge
if(operator == 43){result += x;} // Addition
if(operator == 45){result -= x;} // Subtraction
if(operator == 42){result *= x;} // Multiplication
if(operator == 47){result /= x;} // Division
if(operator == 94){result ^= x;} // XOR
}
return result; // Return the result
}
```
[C (clang)]: http://clang.llvm.org/
[TIO-ks75bste]: https://tio.run/##TczhCoIwFAXg3/UUYihbzkorIuZ6FGFOV1dsxVJQdM9uM6L8dc93OFwRioqr67gCJaomL5zkVefw2NwuI5CSSsRJhnuQKGPsEA/DdE64L1lEjXxoBDZAwjiFIPjt9nYQMKDm66N1OHNsvZ55erj9@3ywTicbXdSNVk5JzdjROweFWtwvFy/BlUSuB55wid8Sv8N0uXhqUPWndolELemwbc0Y7dI3 "C (clang) – Try It Online"

#1: Initial revision by

General Sebast1an‭ · 2021-08-11T07:15:59Z (over 2 years ago)

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# [C (clang)], 142 bytes

<!-- language-all: lang-c -->

    i,j;f(a,b){if(b==42||b==47){j=1;}for(i=1;i<=a;i++){if(b==43){j+=i;}if(b==45){j-=i;}if(b==42){j*=i;}if(b==47){j/=i;}if(b==94){j^=i;}}return j;}

[Try it online!][TIO-ks75bste]

I wanted to try to make something similar to [this](https://codegolf.codidact.com/posts/283268/283277#answer-283277), but with whatever Python has that C doesn't, I couldn't do so.

Instead, I chose to make a function that implements 5 operations. It works differently from the others, but it's all I could do.

Ungolfed form of the function with comments:

```c
int f(int num, char operator){ // Assign a function with 2 parameters: a number and character for operations
	int x, result = 0; // Assign 2 integers: the succeeding number and the base
	if(operator == '*' || operator == '/'){result = 1;} // Check if the character resembles multiplication or division; if so, set base as 1
	for(x = 1; x <= num; x++){ // Start a loop to prompt the calculation that satisfies the challenge
		if(b==43){result+=x;} // Addition
		if(b==45){result-=x;} // Subtraction
		if(b==42){result*=x;} // Multiplication
		if(b==47){result/=x;} // Division
		if(b==94){result^=x;} // XOR
	}
	return result; // Return the result
}
```

[C (clang)]: http://clang.llvm.org/
[TIO-ks75bste]: https://tio.run/##TczhCoIwFAXg3/UUYihbzkorIuZ6FGFOV1dsxVJQdM9uM6L8dc93OFwRioqr67gCJaomL5zkVefw2NwuI5CSSsRJhnuQKGPsEA/DdE64L1lEjXxoBDZAwjiFIPjt9nYQMKDm66N1OHNsvZ55erj9@3ywTicbXdSNVk5JzdjROweFWtwvFy/BlUSuB55wid8Sv8N0uXhqUPWndolELemwbc0Y7dI3 "C (clang) – Try It Online"

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