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Sandbox Compute the determinant

posted 3y ago by Moshi‭  ·  edited 3y ago by Moshi‭

Article code-golf math
#4: Post edited by user avatar Moshi‭ · 2021-08-22T19:33:04Z (over 3 years ago)
  • ## Challenge
  • A simple challenge: Given a two-dimensional matrix (an array of arrays) of real numbers, compute the determinant.
  • The determinant of a matrix is a mathematical construct used in many applications, such as solving polynomial equations, identifying the invertibility of the matrix, and finding the scaling factor under a matrix transformation. For more information about it, see [this Wikipedia entry](https://en.wikipedia.org/wiki/Determinant).
  • There are a couple of different ways to compute the determinant, and it is up to you how you implement it.
  • For instance, you may compute it using the [Laplace expansion](https://en.wikipedia.org/wiki/Laplace_expansion), a recursive algorithm which goes
  • 1. Pick a row or column.
  • 2. Start with a sum of zero.
  • 3. For each entry of the row/column:
  • 1. Create a new matrix with the row **and** column of the entry removed. This new matrix is a square matrix of size one less that the original.
  • 2. Compute the determinant of that smaller matrix.
  • 3. Multiply that determinant by the entry.
  • 4. If the row index plus the column index is even[^1], add it to the sum, otherwise, subtract it.
  • 4. The final sum is the determinant.
  • As an example, here is an ungolfed implementation along the first column.
  • ```javascript
  • function laplaceDet(matrix) {
  • if (matrix.length === 1) return matrix[0][0];
  • let sum = 0;
  • for (let rowIndex = 0; rowIndex < matrix.length; ++rowIndex) {
  • let minorMatrix = matrix.filter((_, index) => index !== rowIndex)
  • .map(row => row.slice(1));
  • sum += ((-1) ** rowIndex) * matrix[rowIndex][0] * laplaceDet(minorMatrix);
  • }
  • return sum;
  • }
  • ```
  • [Try it online!](https://tio.run/##VVFRT4MwEH5uf8X5ZBmFgNucBtmTL5qoDz4SYggrswbaBTqdMfvt81rG2BpSet939/W761fxXXRlKzcmUHolDodqq0ojtYK62NRFKR6FYU1hWrnz4I8SWcExDGuh1uYT0jSF2INWmG2roOeyKMcvoZTUwkC3bSCFKKGk0i0wC7X650mtxM7hY/QAF9oJ@P7AududXCOVbl9cHpYfCypZG9Ey9sFB9unpsj/BFRo8qaAGgdMKm2LDkLPJ@Au7WpaCxZ6HXom17afAWIDtTSajBkyGNgfIdovo@chGk1ZsT8lxQKia0P2h1KozYERnOmwioyTLYg5RzimBLOIQ53h0aDjncNPjwZTDLJwPFEaLnsDSYHaqQJ0LqfPgQhqFOUx7bsYBL7rtgwWHOw73eU5zSt2jjX5BV71v9yIW17UIa71mz@9vr2GHLau1rH6ZTfLAh2sIlrj55@NxnGcH8Q8 "JavaScript (Node.js) – Try It Online")
  • This is <a class="badge is-tag" href="/categories/49/tags/4274">code-golf</a>, so the program with the lowest byte-count wins!
  • ## Test cases
  • <p>$$
  • \begin{aligned}
  • \det\begin{bmatrix}1&0\\0&1\end{bmatrix}&=1 \\
  • \det\begin{bmatrix}1&2\\3&4\end{bmatrix}&=-2 \\
  • \det\begin{bmatrix}3&7\\1&-4\end{bmatrix}&=-19 \\
  • \det\begin{bmatrix}1&0&0\\0&1&0\\0&0&1\end{bmatrix}&=1 \\
  • \det\begin{bmatrix}1&2&3\\4&5&6\\7&8&9\end{bmatrix}&=0
  • \end{aligned}
  • $$</p>
  • In text form,
  • ```
  • [[1,0],[0,1]] -> 1
  • [[1.5,2],[-3,4.5]] -> 12.75
  • [[3,7],[1,-4]] -> -19
  • [[1,0,0],[0,1,0],[0,0,1]] -> 1
  • [[1,2,3],[4,5,6],[7,8,9]] -> 0
  • ```
  • ## Questions
  • - Anything else I missed?
  • [^1]: Note that it doesn't matter if it is 1-indexed or 0-indexed, as 1+1 and 0+0 are both the same parity.
  • ## Challenge
  • A simple challenge: Given a two-dimensional matrix (an array of arrays) of real numbers, compute the determinant.
  • The determinant of a matrix is a mathematical construct used in many applications, such as solving polynomial equations, identifying the invertibility of the matrix, and finding the scaling factor under a matrix transformation. For more information about it, see [this Wikipedia entry](https://en.wikipedia.org/wiki/Determinant).
  • There are a couple of different ways to compute the determinant, and it is up to you how you implement it.
  • For instance, you may compute it using the [Laplace expansion](https://en.wikipedia.org/wiki/Laplace_expansion), a recursive algorithm which goes
  • 1. Pick a row or column.
  • 2. Start with a sum of zero.
  • 3. For each entry of the row/column:
  • 1. Create a new matrix with the row **and** column of the entry removed. This new matrix is a square matrix of size one less that the original.
  • 2. Compute the determinant of that smaller matrix.
  • 3. Multiply that determinant by the entry.
  • 4. If the row index plus the column index is even[^1], add it to the sum, otherwise, subtract it.
  • 4. The final sum is the determinant.
  • As an example, here is an ungolfed implementation along the first column.
  • ```javascript
  • function laplaceDet(matrix) {
  • if (matrix.length === 1) return matrix[0][0];
  • let sum = 0;
  • for (let rowIndex = 0; rowIndex < matrix.length; ++rowIndex) {
  • let minorMatrix = matrix.filter((_, index) => index !== rowIndex)
  • .map(row => row.slice(1));
  • sum += ((-1) ** rowIndex) * matrix[rowIndex][0] * laplaceDet(minorMatrix);
  • }
  • return sum;
  • }
  • ```
  • [Try it online!](https://tio.run/##VVFRT4MwEH5uf8X5ZBmFgNucBtmTL5qoDz4SYggrswbaBTqdMfvt81rG2BpSet939/W761fxXXRlKzcmUHolDodqq0ojtYK62NRFKR6FYU1hWrnz4I8SWcExDGuh1uYT0jSF2INWmG2roOeyKMcvoZTUwkC3bSCFKKGk0i0wC7X650mtxM7hY/QAF9oJ@P7AududXCOVbl9cHpYfCypZG9Ey9sFB9unpsj/BFRo8qaAGgdMKm2LDkLPJ@Au7WpaCxZ6HXom17afAWIDtTSajBkyGNgfIdovo@chGk1ZsT8lxQKia0P2h1KozYERnOmwioyTLYg5RzimBLOIQ53h0aDjncNPjwZTDLJwPFEaLnsDSYHaqQJ0LqfPgQhqFOUx7bsYBL7rtgwWHOw73eU5zSt2jjX5BV71v9yIW17UIa71mz@9vr2GHLau1rH6ZTfLAh2sIlrj55@NxnGcH8Q8 "JavaScript (Node.js) – Try It Online")
  • This is <a class="badge is-tag" href="/categories/49/tags/4274">code-golf</a>, so the program with the lowest byte-count wins!
  • ## Test cases
  • <p>$$
  • \begin{aligned}
  • \det\begin{bmatrix}1&0\\0&1\end{bmatrix}&=1 \\
  • \det\begin{bmatrix}1.5&2\\-3&4.5\end{bmatrix}&=12.75 \\
  • \det\begin{bmatrix}3&7\\1&-4\end{bmatrix}&=-19 \\
  • \det\begin{bmatrix}1&0&0\\0&1&0\\0&0&1\end{bmatrix}&=1 \\
  • \det\begin{bmatrix}1&2&3\\4&5&6\\7&8&9\end{bmatrix}&=0
  • \end{aligned}
  • $$</p>
  • In text form,
  • ```
  • [[1,0],[0,1]] -> 1
  • [[1.5,2],[-3,4.5]] -> 12.75
  • [[3,7],[1,-4]] -> -19
  • [[1,0,0],[0,1,0],[0,0,1]] -> 1
  • [[1,2,3],[4,5,6],[7,8,9]] -> 0
  • ```
  • ## Questions
  • - Anything else I missed?
  • [^1]: Note that it doesn't matter if it is 1-indexed or 0-indexed, as 1+1 and 0+0 are both the same parity.
#3: Post edited by user avatar Moshi‭ · 2021-08-22T19:23:23Z (over 3 years ago)
  • ## Challenge
  • A simple challenge: Given a two-dimensional matrix (an array of arrays) of integers, compute the determinant.
  • The determinant of a matrix is a mathematical construct used in many applications, such as solving polynomial equations, identifying the invertibility of the matrix, and finding the scaling factor under a matrix transformation. For more information about it, see [this Wikipedia entry](https://en.wikipedia.org/wiki/Determinant).
  • There are a couple of different ways to compute the determinant, and it is up to you how you implement it.
  • For instance, you may compute it using the [Laplace expansion](https://en.wikipedia.org/wiki/Laplace_expansion), a recursive algorithm which goes
  • 1. Pick a row or column.
  • 2. Start with a sum of zero.
  • 3. For each entry of the row/column:
  • 1. Create a new matrix with the row **and** column of the entry removed. This new matrix is a square matrix of size one less that the original.
  • 2. Compute the determinant of that smaller matrix.
  • 3. Multiply that determinant by the entry.
  • 4. If the row index plus the column index is even[^1], add it to the sum, otherwise, subtract it.
  • 4. The final sum is the determinant.
  • As an example, here is an ungolfed implementation along the first column.
  • ```javascript
  • function laplaceDet(matrix) {
  • if (matrix.length === 1) return matrix[0][0];
  • let sum = 0;
  • for (let rowIndex = 0; rowIndex < matrix.length; ++rowIndex) {
  • let minorMatrix = matrix.filter((_, index) => index !== rowIndex)
  • .map(row => row.slice(1));
  • sum += ((-1) ** rowIndex) * matrix[rowIndex][0] * laplaceDet(minorMatrix);
  • }
  • return sum;
  • }
  • ```
  • [Try it online!](https://tio.run/##XVHRToMwFH2mX3F9soxCwE2nQfbkiybqg4@EGMLKrCntUjqdMfv22VIYTNLQe8@5PT339rP8KttKsa0OhVzT47HeiUozKYCXW15W9IFq3JRasb0Pv8hjNfRpxKnY6A/IsgwSHxTVOyXAcXlcmJUi5HGqod01kEGcIq@WCrCFlPx@FGu67/Axu4cz7RSCYOC62zu5hgmpnrs6c7w/UDOuqcL4nQBz5dnKRXBhDJ5UjIYHpy9qyi02nC02W9RyVlGc@L7x6lnbQQYYh6a92WzUgNnQ5gDZbg06Hdlo0oodkNcPyKim6HCspGg1aNrq1jSRIy/PEwJxQZAHeUwgKUzYo1cOnRNYDKiJlw41fLiYFMdnKtPkvyqBueMWBK4J3LhkSeCWwF1RoAKh7r1GqyBrZ7l7DItLTiMuN/jp7fUlak23YsPqH2yLfAjgEsKV@QXTyXScb2fwBw "JavaScript (Node.js) – Try It Online")
  • This is <a class="badge is-tag" href="/categories/49/tags/4274">code-golf</a>, so the program with the lowest byte-count wins!
  • ## Test cases
  • <p>$$
  • \begin{aligned}
  • \det\begin{bmatrix}1&0\\0&1\end{bmatrix}&=1 \\
  • \det\begin{bmatrix}1&2\\3&4\end{bmatrix}&=-2 \\
  • \det\begin{bmatrix}3&7\\1&-4\end{bmatrix}&=-19 \\
  • \det\begin{bmatrix}1&0&0\\0&1&0\\0&0&1\end{bmatrix}&=1 \\
  • \det\begin{bmatrix}1&2&3\\4&5&6\\7&8&9\end{bmatrix}&=0
  • \end{aligned}
  • $$</p>
  • In text form,
  • ```
  • [[1,0],[0,1]] -> 1
  • [[1,2],[3,4]] -> -2
  • [[3,7],[1,-4]] -> -19
  • [[1,0,0],[0,1,0],[0,0,1]] -> 1
  • [[1,2,3],[4,5,6],[7,8,9]] -> 0
  • ```
  • ## Questions
  • - Are there any alternative inputs that should be allowed?
  • - Should I expand it to all real numbers, not just integers?
  • - Anything else I missed?
  • [^1]: Note that it doesn't matter if it is 1-indexed or 0-indexed, as 1+1 and 0+0 are both the same parity.
  • ## Challenge
  • A simple challenge: Given a two-dimensional matrix (an array of arrays) of real numbers, compute the determinant.
  • The determinant of a matrix is a mathematical construct used in many applications, such as solving polynomial equations, identifying the invertibility of the matrix, and finding the scaling factor under a matrix transformation. For more information about it, see [this Wikipedia entry](https://en.wikipedia.org/wiki/Determinant).
  • There are a couple of different ways to compute the determinant, and it is up to you how you implement it.
  • For instance, you may compute it using the [Laplace expansion](https://en.wikipedia.org/wiki/Laplace_expansion), a recursive algorithm which goes
  • 1. Pick a row or column.
  • 2. Start with a sum of zero.
  • 3. For each entry of the row/column:
  • 1. Create a new matrix with the row **and** column of the entry removed. This new matrix is a square matrix of size one less that the original.
  • 2. Compute the determinant of that smaller matrix.
  • 3. Multiply that determinant by the entry.
  • 4. If the row index plus the column index is even[^1], add it to the sum, otherwise, subtract it.
  • 4. The final sum is the determinant.
  • As an example, here is an ungolfed implementation along the first column.
  • ```javascript
  • function laplaceDet(matrix) {
  • if (matrix.length === 1) return matrix[0][0];
  • let sum = 0;
  • for (let rowIndex = 0; rowIndex < matrix.length; ++rowIndex) {
  • let minorMatrix = matrix.filter((_, index) => index !== rowIndex)
  • .map(row => row.slice(1));
  • sum += ((-1) ** rowIndex) * matrix[rowIndex][0] * laplaceDet(minorMatrix);
  • }
  • return sum;
  • }
  • ```
  • [Try it online!](https://tio.run/##VVFRT4MwEH5uf8X5ZBmFgNucBtmTL5qoDz4SYggrswbaBTqdMfvt81rG2BpSet939/W761fxXXRlKzcmUHolDodqq0ojtYK62NRFKR6FYU1hWrnz4I8SWcExDGuh1uYT0jSF2INWmG2roOeyKMcvoZTUwkC3bSCFKKGk0i0wC7X650mtxM7hY/QAF9oJ@P7AududXCOVbl9cHpYfCypZG9Ey9sFB9unpsj/BFRo8qaAGgdMKm2LDkLPJ@Au7WpaCxZ6HXom17afAWIDtTSajBkyGNgfIdovo@chGk1ZsT8lxQKia0P2h1KozYERnOmwioyTLYg5RzimBLOIQ53h0aDjncNPjwZTDLJwPFEaLnsDSYHaqQJ0LqfPgQhqFOUx7bsYBL7rtgwWHOw73eU5zSt2jjX5BV71v9yIW17UIa71mz@9vr2GHLau1rH6ZTfLAh2sIlrj55@NxnGcH8Q8 "JavaScript (Node.js) – Try It Online")
  • This is <a class="badge is-tag" href="/categories/49/tags/4274">code-golf</a>, so the program with the lowest byte-count wins!
  • ## Test cases
  • <p>$$
  • \begin{aligned}
  • \det\begin{bmatrix}1&0\\0&1\end{bmatrix}&=1 \\
  • \det\begin{bmatrix}1&2\\3&4\end{bmatrix}&=-2 \\
  • \det\begin{bmatrix}3&7\\1&-4\end{bmatrix}&=-19 \\
  • \det\begin{bmatrix}1&0&0\\0&1&0\\0&0&1\end{bmatrix}&=1 \\
  • \det\begin{bmatrix}1&2&3\\4&5&6\\7&8&9\end{bmatrix}&=0
  • \end{aligned}
  • $$</p>
  • In text form,
  • ```
  • [[1,0],[0,1]] -> 1
  • [[1.5,2],[-3,4.5]] -> 12.75
  • [[3,7],[1,-4]] -> -19
  • [[1,0,0],[0,1,0],[0,0,1]] -> 1
  • [[1,2,3],[4,5,6],[7,8,9]] -> 0
  • ```
  • ## Questions
  • - Anything else I missed?
  • [^1]: Note that it doesn't matter if it is 1-indexed or 0-indexed, as 1+1 and 0+0 are both the same parity.
#2: Post edited by user avatar Moshi‭ · 2021-08-19T22:40:16Z (over 3 years ago)
  • ## Challenge
  • A simple challenge: Given a two-dimensional matrix (an array of arrays) of integers, compute the determinant.
  • There are a couple of different ways to compute the determinant, and it is up to you how you implement it. As an example, here is an ungolfed implementation using the [Laplace expansion](https://en.wikipedia.org/wiki/Determinant#Laplace_expansion) along the first column.
  • ```javascript
  • function laplaceDet(matrix) {
  • if (matrix.length === 1) return matrix[0][0];
  • let sum = 0;
  • for (let rowIndex = 0; rowIndex < matrix.length; ++rowIndex) {
  • let minorMatrix = matrix.filter((_, index) => index !== rowIndex)
  • .map(row => row.slice(1));
  • sum += ((-1) ** rowIndex) * matrix[rowIndex][0] * laplaceDet(minorMatrix);
  • }
  • return sum;
  • }
  • ```
  • [Try it online!](https://tio.run/##XVHRToMwFH2mX3F9soxCwE2nQfbkiybqg4@EGMLKrCntUjqdMfv22VIYTNLQe8@5PT339rP8KttKsa0OhVzT47HeiUozKYCXW15W9IFq3JRasb0Pv8hjNfRpxKnY6A/IsgwSHxTVOyXAcXlcmJUi5HGqod01kEGcIq@WCrCFlPx@FGu67/Axu4cz7RSCYOC62zu5hgmpnrs6c7w/UDOuqcL4nQBz5dnKRXBhDJ5UjIYHpy9qyi02nC02W9RyVlGc@L7x6lnbQQYYh6a92WzUgNnQ5gDZbg06Hdlo0oodkNcPyKim6HCspGg1aNrq1jSRIy/PEwJxQZAHeUwgKUzYo1cOnRNYDKiJlw41fLiYFMdnKtPkvyqBueMWBK4J3LhkSeCWwF1RoAKh7r1GqyBrZ7l7DItLTiMuN/jp7fUlak23YsPqH2yLfAjgEsKV@QXTyXScb2fwBw "JavaScript (Node.js) – Try It Online")
  • This is <a class="badge is-tag" href="/categories/49/tags/4274">code-golf</a>, so the program with the lowest byte-count wins!
  • ## Test cases
  • <p>$$
  • \begin{aligned}
  • \det\begin{bmatrix}1&0\\0&1\end{bmatrix}&=1 \\
  • \det\begin{bmatrix}1&2\\3&4\end{bmatrix}&=-2 \\
  • \det\begin{bmatrix}3&7\\1&-4\end{bmatrix}&=-19 \\
  • \det\begin{bmatrix}1&0&0\\0&1&0\\0&0&1\end{bmatrix}&=1 \\
  • \det\begin{bmatrix}1&2&3\\4&5&6\\7&8&9\end{bmatrix}&=0
  • \end{aligned}
  • $$</p>
  • ## Questions
  • - Are there any alternative inputs that should be allowed?
  • - Should I expand it to all real numbers, not just integers?
  • - Anything else I missed?
  • ## Challenge
  • A simple challenge: Given a two-dimensional matrix (an array of arrays) of integers, compute the determinant.
  • The determinant of a matrix is a mathematical construct used in many applications, such as solving polynomial equations, identifying the invertibility of the matrix, and finding the scaling factor under a matrix transformation. For more information about it, see [this Wikipedia entry](https://en.wikipedia.org/wiki/Determinant).
  • There are a couple of different ways to compute the determinant, and it is up to you how you implement it.
  • For instance, you may compute it using the [Laplace expansion](https://en.wikipedia.org/wiki/Laplace_expansion), a recursive algorithm which goes
  • 1. Pick a row or column.
  • 2. Start with a sum of zero.
  • 3. For each entry of the row/column:
  • 1. Create a new matrix with the row **and** column of the entry removed. This new matrix is a square matrix of size one less that the original.
  • 2. Compute the determinant of that smaller matrix.
  • 3. Multiply that determinant by the entry.
  • 4. If the row index plus the column index is even[^1], add it to the sum, otherwise, subtract it.
  • 4. The final sum is the determinant.
  • As an example, here is an ungolfed implementation along the first column.
  • ```javascript
  • function laplaceDet(matrix) {
  • if (matrix.length === 1) return matrix[0][0];
  • let sum = 0;
  • for (let rowIndex = 0; rowIndex < matrix.length; ++rowIndex) {
  • let minorMatrix = matrix.filter((_, index) => index !== rowIndex)
  • .map(row => row.slice(1));
  • sum += ((-1) ** rowIndex) * matrix[rowIndex][0] * laplaceDet(minorMatrix);
  • }
  • return sum;
  • }
  • ```
  • [Try it online!](https://tio.run/##XVHRToMwFH2mX3F9soxCwE2nQfbkiybqg4@EGMLKrCntUjqdMfv22VIYTNLQe8@5PT339rP8KttKsa0OhVzT47HeiUozKYCXW15W9IFq3JRasb0Pv8hjNfRpxKnY6A/IsgwSHxTVOyXAcXlcmJUi5HGqod01kEGcIq@WCrCFlPx@FGu67/Axu4cz7RSCYOC62zu5hgmpnrs6c7w/UDOuqcL4nQBz5dnKRXBhDJ5UjIYHpy9qyi02nC02W9RyVlGc@L7x6lnbQQYYh6a92WzUgNnQ5gDZbg06Hdlo0oodkNcPyKim6HCspGg1aNrq1jSRIy/PEwJxQZAHeUwgKUzYo1cOnRNYDKiJlw41fLiYFMdnKtPkvyqBueMWBK4J3LhkSeCWwF1RoAKh7r1GqyBrZ7l7DItLTiMuN/jp7fUlak23YsPqH2yLfAjgEsKV@QXTyXScb2fwBw "JavaScript (Node.js) – Try It Online")
  • This is <a class="badge is-tag" href="/categories/49/tags/4274">code-golf</a>, so the program with the lowest byte-count wins!
  • ## Test cases
  • <p>$$
  • \begin{aligned}
  • \det\begin{bmatrix}1&0\\0&1\end{bmatrix}&=1 \\
  • \det\begin{bmatrix}1&2\\3&4\end{bmatrix}&=-2 \\
  • \det\begin{bmatrix}3&7\\1&-4\end{bmatrix}&=-19 \\
  • \det\begin{bmatrix}1&0&0\\0&1&0\\0&0&1\end{bmatrix}&=1 \\
  • \det\begin{bmatrix}1&2&3\\4&5&6\\7&8&9\end{bmatrix}&=0
  • \end{aligned}
  • $$</p>
  • In text form,
  • ```
  • [[1,0],[0,1]] -> 1
  • [[1,2],[3,4]] -> -2
  • [[3,7],[1,-4]] -> -19
  • [[1,0,0],[0,1,0],[0,0,1]] -> 1
  • [[1,2,3],[4,5,6],[7,8,9]] -> 0
  • ```
  • ## Questions
  • - Are there any alternative inputs that should be allowed?
  • - Should I expand it to all real numbers, not just integers?
  • - Anything else I missed?
  • [^1]: Note that it doesn't matter if it is 1-indexed or 0-indexed, as 1+1 and 0+0 are both the same parity.
#1: Initial revision by user avatar Moshi‭ · 2021-08-15T02:51:00Z (over 3 years ago)
Compute the determinant
## Challenge

A simple challenge: Given a two-dimensional matrix (an array of arrays) of integers, compute the determinant.

There are a couple of different ways to compute the determinant, and it is up to you how you implement it. As an example, here is an ungolfed implementation using the [Laplace expansion](https://en.wikipedia.org/wiki/Determinant#Laplace_expansion) along the first column.

```javascript
function laplaceDet(matrix) {
	if (matrix.length === 1) return matrix[0][0];

	let sum = 0;
	for (let rowIndex = 0; rowIndex < matrix.length; ++rowIndex) {
		let minorMatrix = matrix.filter((_, index) => index !== rowIndex)
			          .map(row => row.slice(1));
		sum += ((-1) ** rowIndex) * matrix[rowIndex][0] * laplaceDet(minorMatrix);
	}
	return sum;
}
```

[Try it online!](https://tio.run/##XVHRToMwFH2mX3F9soxCwE2nQfbkiybqg4@EGMLKrCntUjqdMfv22VIYTNLQe8@5PT339rP8KttKsa0OhVzT47HeiUozKYCXW15W9IFq3JRasb0Pv8hjNfRpxKnY6A/IsgwSHxTVOyXAcXlcmJUi5HGqod01kEGcIq@WCrCFlPx@FGu67/Axu4cz7RSCYOC62zu5hgmpnrs6c7w/UDOuqcL4nQBz5dnKRXBhDJ5UjIYHpy9qyi02nC02W9RyVlGc@L7x6lnbQQYYh6a92WzUgNnQ5gDZbg06Hdlo0oodkNcPyKim6HCspGg1aNrq1jSRIy/PEwJxQZAHeUwgKUzYo1cOnRNYDKiJlw41fLiYFMdnKtPkvyqBueMWBK4J3LhkSeCWwF1RoAKh7r1GqyBrZ7l7DItLTiMuN/jp7fUlak23YsPqH2yLfAjgEsKV@QXTyXScb2fwBw "JavaScript (Node.js) – Try It Online")


This is <a class="badge is-tag" href="/categories/49/tags/4274">code-golf</a>, so the program with the lowest byte-count wins!

## Test cases

<p>$$
\begin{aligned}
\det\begin{bmatrix}1&0\\0&1\end{bmatrix}&=1 \\
\det\begin{bmatrix}1&2\\3&4\end{bmatrix}&=-2 \\
\det\begin{bmatrix}3&7\\1&-4\end{bmatrix}&=-19 \\
\det\begin{bmatrix}1&0&0\\0&1&0\\0&0&1\end{bmatrix}&=1 \\
\det\begin{bmatrix}1&2&3\\4&5&6\\7&8&9\end{bmatrix}&=0
\end{aligned}
$$</p>

## Questions

 - Are there any alternative inputs that should be allowed?
 - Should I expand it to all real numbers, not just integers?
 - Anything else I missed?