# Roll n fair dice

# Challenge

This is a simple randomness challenge: Given a non-negative integer $n$, and positive integer $m$, simulate rolling and summing the results of $n$ fair dice, each of which have $m$ sides numbered $1$ through $m$.

Here is a basic ungolfed example in Python:

```
from random import randint
def roll(n, m):
return sum([randint(1, m) for i in range(n)])
```

Try it online! (Also includes a basic visualization of the resulting distribution)

This is code golf, so shortest code wins!

[Python 3], 61 bytes …

2y ago

[Ruby], 28 bytes -> …

1y ago

[Python 3], 59 bytes …

1y ago

[C (gcc)], 48 43 bytes …

1y ago

Japt `-mx`, 3 bytes Takes ` …

2y ago

Vyxal `ṪR`, 3 bytes ``` (⁰ …

2y ago

[Jelly], 4 bytes X}€S …

2y ago

J, 10 7 bytes ```J +/>:?#/ …

12mo ago

Ruby, 27 24 bytes ->n,m{ …

1y ago

## 9 answers

# Python 3, 61 bytes

```
lambda n,m:sum(randint(1,m)for i in[0]*n)
from random import*
```

This is not an interesting answer as it is just a copy of your code. I tried to do it with choices but it's 1 byte longer : Try it online!

#### 0 comment threads

# Jelly, 4 bytes

```
X}€S
```

## How it works

```
X}€S - Main link. Takes n on the left, m on the right
€ - Over each element of 1 through n:
} - With m as its argument:
X - Yield a random integer from 1 to m
S - Sum
```

#### 0 comment threads

#
Vyxal `ṪR`

, 3 bytes

```
(⁰℅
```

```
( # N times...
℅ # Generate a random integer between one and...
⁰ # First argument
```

#### 0 comment threads

#
C (gcc), ~~48~~ 43 bytes

```
s;r(n,m){s+=rand()%m+1;return--n?r(n,m):s;}
```

Previous 48 bytes version using loop:

`i,s;r(n,m){for(;i<n;i++)s+=rand()%m+1;return s;}`

#### 0 comment threads

#
Ruby, ~~27~~ 24 bytes

`->n,m{eval'-~rand(m)'*n}`

If we change the order of `n, m`

parameters to `m, n`

then following 23 bytes version work, but only in ruby 2.7 (it does not work in 3.x - bug or feature?):

```
->{eval'-~rand(_1)'*_2}
```

#### 0 comment threads

#
J, ~~10~~ 7 bytes

```
+/>:?#/
```

```
+/>:?#/
#/ : Inserts dyadic # into an array n m
Creates n copies of m
? : Roll from 0..y
>: : Increment
+/ : Sum reduce
```

-3 bytes thanks to torres.

## 0 comment threads