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Challenges

Stairs? Stairs! Stairs.

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Challenge

  • Make a program that takes input of an integer that's $n > 1$ and print out a staircase using a specific character for stair basing (hashes (#) for demonstration; you can use spaces, but not tabs or other whitespace characters), slashes (/), and underscores (_).
  • The basis of the staircase is having the hashes as to act like the stair supporters, in other words, bricks. The bottom stair starts with a slash then as we go higher, an underscore at the spot right next and above the
  • Shortest program in each language wins!

Test Cases

n = 2
 _/
/##

n = 3
   _/
 _/##
/####

n = 6
         _/
       _/##
     _/####
   _/######
 _/########
/##########
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6 answers

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Python 3, 64 bytes

def f(n):
	for i in range(n):print(('  '*(n-i)+'_/'+'##'*i)[3:])

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+2
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Haskell, 78 bytes

(!)0.(*2)
i!n|i<n=(drop 3$(n-i)#' '++"_/"++i#'#'):(i+2)!n|0<1=[]
(#)=replicate

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+1
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Stax, 8 bytes

Ç▐GcΦ≡◘¶

Run and debug it

Uses spaces as the staircase fill.

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+1
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Vyxal jṀ, 11 bytes

ƛd‛_/$꘍⁰d↳Ḣ

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ƛ           # Map 0...n to...
  ‛_/       # '_/'
     $꘍     # And append...
 d          # Double
            # (Implicit input)
     $꘍     # Spaces
         ↳  # Pad to length...
        d   # Double
       ⁰    # Initial input
          Ḣ # Cut of the first character 
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+1
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JavaScript (Node.js), 91 bytes

(n)=>[...Array(n)].map((_,i)=>console.log(('  '.repeat(n-i)+'_/'+'##'.repeat(i)).slice(3)))

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Directly using a for loop is less expensive (1 comment)
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Japt -R, 13 bytes

Uses = in place of #.

Æ"_/"+Xç¥ÃoÅù

Try it

Æ"_/"+Xç¥ÃoÅù     :Implicit input of integer U
Æ                 :Map each X in the range [0,U)
 "_/"             :  Literal string
     +            :  Append
      Xç          :    X times repeat
        ¥         :      "=="
         Ã        :End map
          o       :Modify last element
           Å      :  Slice off first character
            ù     :Left pad each with spaces to the length of the longest
                  :Implicit output joined with newlines
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