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Challenges

Abbreviate everything

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Challenge

Make a program that takes input of a string and abbreviate it.

  • All letters of an abbreviation are capitalized, so keep that in mind.
  • Whitespace, numbers and non-English characters are ignored.
  • If the inputted string is a paragraph (2+ sentences), the abbreviation will be split by spaces ( ) where ., ? or ! are, while commas (,) are ignored in this splitting scenario.
  • Words that are connected by hyphens (-) will result to only one letter.
  • The only non-alphabetical characters to remain in the result are colons (:) and semicolons (;).
  • This is code-golf, so shortest program in each language wins.

Test Cases

// Input
# Output

Hello, World!
HW

Can you make me a sandwich?
CYMMAS

hyper-neutrino
H

Too long; didn't read
TL;DR

I studied, don't worry. I will pass.
ISDW IWP

What???!?!
W

Get me 99 bottles of beer, bro!
GMBOBB
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3 answers

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Haskell, 139 138 bytes

import Data.Char
f(a:b)|d a=toUpper a:f(dropWhile(\a->e a"-'"||d a)b)|e a":;"=a:c|e a".?!"=' ':c|0<1=c where c=f b;d=isLetter;e=elem
f a=a

Try it online!

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JavaScript (Node.js), 91 68 65 bytes

s=>s.toUpperCase().match(/(?<=^| )[A-Z]|:|;|(?<=[.?!]) /g).join``

Assumes that the original text is properly formatted (has a space after punctuation). It converts the string to uppercase, then matches the following:

  • A letter at the beginning of the string or preceded by a space
  • : or ;
  • A space preceded by ., ?, or !

Try it online!

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Python 3, 142 bytes

def f(s):
	m=1;r=""
	for c in s.upper():
		if'@'<c<'['or'-'==c:r+=c*m;m=0
		if c in":; ":r+=c*(c!=' ');m=1
		if c in".?!":r+=' ';m=1
	return r

Try it online!

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