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Python 3, 75 bytes lambda a:[[i,k]for i in r(l(a))for k in r(l(a[0]))if a[i][k]] r=range;l=len Try it online!
Answer
#1: Initial revision
by
celtschk
·
2021-10-01T11:34:44Z (about 3 years ago)
# [Python 3], 75 bytes
<!-- language-all: lang-python -->
lambda a:[[i,k]for i in r(l(a))for k in r(l(a[0]))if a[i][k]]
r=range;l=len
[Try it online!][TIO-ku8afsm0]
[Python 3]: https://docs.python.org/3/
[TIO-ku8afsm0]: https://tio.run/##TY0xDsMgDEV3TmFlAomBqFuqnIR6oC20KJREQIcqytoD9Ii9CE2IEtUerO9n/z@80r33h2yghVN26nG@KlCNlJZ3aPoAFqyHQB1VjC2627UUyJg1oKRF2SGS0Ablb/roWqd9Tjqmi4o6zs6SwFxS1lzwurRA5P9L5PsUKy4UCVlCN68le/dtykXQ8enSnGHoRlgBQ7A@UVON23qC7/sD4/owVYzkHw "Python 3 – Try It Online"