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Python 3, 191 bytes lambda p:[c for c in chain(*[C(p,r)for r in range(len(p)+1)])if all(all(i==(sum(p.values())/2>=sum(p[n]for n in d))for d in C(c,len(c)-i))for i in[0,1])] from itertools imp...

posted 3y ago by Moshi‭  ·  edited 3y ago by Moshi‭

Answer
#2: Post edited by user avatar Moshi‭ · 2021-10-04T23:08:57Z (about 3 years ago)
Added explanation
  • # [Python 3], 191 bytes
  • ```python
  • lambda p:[c for c in chain(*[C(p,r)for r in range(len(p)+1)])if all(all(i==(sum(p.values())/2>=sum(p[n]for n in d))for d in C(c,len(c)-i))for i in[0,1])]
  • from itertools import*;C=combinations
  • ```
  • [Try it online!][TIO-kud95h9i]
  • [Python 3]: https://docs.python.org/3/
  • [TIO-kud95h9i]: https://tio.run/##lVBBTsMwEDw3r1jlUrsEaAqpUFC4RLwi5OA6SbtSYlu2WwmhXnkAT@QjIZuKkiJx4GBrZ3Z2djXm1e@0uuub7KVvRbepBJi0kNBoCxJQgdwJVGxR5MxElhNtibZCbWvW1ooZfhXzkmMDom0ZPcwy5vYdMzcH0e5rxzi/XT1lI1WokjwUeVR89KuozpmMyE3yazzRONDFMopLXgaN1R2gr63XunWAndHWLx7zTOpug0p41Mr1vnbeQQZFMHs7RsMXKqF0mMIqOcEDElhGED53QjoC8Z@d5aUF9UZVnExU8erXorPqfqJ6GOptXaEf6vXFQLz@78DPHdNrk8lAcgzKIKAIKRAKdwwmDWbGovKMEP8G88/3j3kEzYk907z/Ag "Python 3 – Try It Online"
  • # [Python 3], 191 bytes
  • ```python
  • lambda p:[c for c in chain(*[C(p,r)for r in range(len(p)+1)])if all(all(i==(sum(p.values())/2>=sum(p[n]for n in d))for d in C(c,len(c)-i))for i in[0,1])]
  • from itertools import*;C=combinations
  • ```
  • [Try it online!][TIO-kud95h9i]
  • Yay for quadruple nested list compressions...
  • ## Explanation
  • First we take the powerset:
  • ```
  • lambda p:[c for c in chain(*[C(p,r)for r in range(len(p)+1)])
  • ```
  • Then we filter.
  • ```python
  • if all(all(i==(sum(p.values())/2>=sum(p[n]for n in d))for d in C(c,len(c)-i))
  • for i in[0,1])]
  • from itertools import*;C=combinations # Imports and aliases
  • ```
  • There's a neat little trick: we want to have the set sum greater than `s/2` (the average), while having the `n-1` sized subsets' sums less than or equal to `s/2`. By realizing that the full set is equal to the `n` sized subset, we can combine both of them:
  • ```text
  • n subset > s/2 and n-1 subset <= s/2
  • ```
  • is equivalent to
  • ```text
  • (n subset <= s/2) == 0 and (n-1 subset <= s/2) == 1
  • ```
  • is equivalent to
  • ```text
  • (n-i subset <= s/2) == i) for i in [0,1]
  • ```
  • [Python 3]: https://docs.python.org/3/
  • [TIO-kud95h9i]: https://tio.run/##lVBBTsMwEDw3r1jlUrsEaAqpUFC4RLwi5OA6SbtSYlu2WwmhXnkAT@QjIZuKkiJx4GBrZ3Z2djXm1e@0uuub7KVvRbepBJi0kNBoCxJQgdwJVGxR5MxElhNtibZCbWvW1ooZfhXzkmMDom0ZPcwy5vYdMzcH0e5rxzi/XT1lI1WokjwUeVR89KuozpmMyE3yazzRONDFMopLXgaN1R2gr63XunWAndHWLx7zTOpug0p41Mr1vnbeQQZFMHs7RsMXKqF0mMIqOcEDElhGED53QjoC8Z@d5aUF9UZVnExU8erXorPqfqJ6GOptXaEf6vXFQLz@78DPHdNrk8lAcgzKIKAIKRAKdwwmDWbGovKMEP8G88/3j3kEzYk907z/Ag "Python 3 – Try It Online"
#1: Initial revision by user avatar Moshi‭ · 2021-10-04T22:57:41Z (about 3 years ago)
# [Python 3], 191 bytes

```python
lambda p:[c for c in chain(*[C(p,r)for r in range(len(p)+1)])if all(all(i==(sum(p.values())/2>=sum(p[n]for n in d))for d in C(c,len(c)-i))for i in[0,1])]
from itertools import*;C=combinations
```

[Try it online!][TIO-kud95h9i]

[Python 3]: https://docs.python.org/3/
[TIO-kud95h9i]: https://tio.run/##lVBBTsMwEDw3r1jlUrsEaAqpUFC4RLwi5OA6SbtSYlu2WwmhXnkAT@QjIZuKkiJx4GBrZ3Z2djXm1e@0uuub7KVvRbepBJi0kNBoCxJQgdwJVGxR5MxElhNtibZCbWvW1ooZfhXzkmMDom0ZPcwy5vYdMzcH0e5rxzi/XT1lI1WokjwUeVR89KuozpmMyE3yazzRONDFMopLXgaN1R2gr63XunWAndHWLx7zTOpug0p41Mr1vnbeQQZFMHs7RsMXKqF0mMIqOcEDElhGED53QjoC8Z@d5aUF9UZVnExU8erXorPqfqJ6GOptXaEf6vXFQLz@78DPHdNrk8lAcgzKIKAIKRAKdwwmDWbGovKMEP8G88/3j3kEzYk907z/Ag "Python 3 – Try It Online"