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J, 4 3 distinct, 6 bytes -:_-:_ Half of _ -: _ which is asks if infinity matches infinity. Thanks to @xash in the APL farm discord for saving the 3 unique bytes and orthoplex for catching my bl...
Answer
#3: Post edited
by
south
·
2022-02-10T22:50:25Z (over 2 years ago)
# [J](https://jsoftware.com/#/), ~~4~~ 3 distinct, ~~4~~ 5 bytes- ```J
%#_ _- ```
~~Half (`-:`) of the sign (`*`) of infinity (`_`).~~Reciprocal of the number of items in the given vector (2 infinities). This might be the winner for J.
- # [J](https://jsoftware.com/#/), ~~4~~ 3 distinct, 6 bytes
- ```J
- -:_-:_
- ```
- Half of `_ -: _` which is asks if infinity matches infinity. Thanks to @xash in the APL farm discord for saving the 3 unique bytes and orthoplex for catching my blunder.
#2: Post edited
by
south
·
2022-02-10T16:40:07Z (over 2 years ago)
# [J](https://jsoftware.com/#/), 4 distinct, 4 bytes- ```J
-:*_- ```
[Try it online!](https://tio.run/##y/r/PzU5I19B10or/v9/AA)Half (`-:`) of the sign (`*`) of infinity (`_`).
- # [J](https://jsoftware.com/#/), ~~4~~ 3 distinct, ~~4~~ 5 bytes
- ```J
- %#_ _
- ```
- ~~Half (`-:`) of the sign (`*`) of infinity (`_`).~~
- Reciprocal of the number of items in the given vector (2 infinities). This might be the winner for J.
#1: Initial revision
by
south
·
2022-02-10T04:14:23Z (over 2 years ago)
# [J](https://jsoftware.com/#/), 4 distinct, 4 bytes ```J -:*_ ``` [Try it online!](https://tio.run/##y/r/PzU5I19B10or/v9/AA) Half (`-:`) of the sign (`*`) of infinity (`_`).