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Challenges Find n Niven Numbers

Python, 98 bytes from itertools import* f=lambda n:[*islice(filter(lambda k:k%sum(map(int,str(k)))==0,count(1)),n)] itertools.count() generates integer numbers starting from 1, filter() fil...

posted 2y ago by __blackjack__‭  ·  edited 2y ago by __blackjack__‭

Answer
#3: Post edited by user avatar __blackjack__‭ · 2022-08-24T15:04:03Z (about 2 years ago)
`list()` replaced by `[*…]`
  • # Python, 101 bytes
  • ```python
  • from itertools import*
  • f=lambda n:list(islice(filter(lambda k:k%sum(map(int,str(k)))==0,count(1)),n))
  • ```
  • * `itertools.count()` generates integer numbers starting from 1,
  • * `filter()` filters out the Niven numbers,
  • * `itertools.islice()` limits the result to `n` items,
  • * and `list()` collects the numbers in a list.
  • # Python, 98 bytes
  • ```python
  • from itertools import*
  • f=lambda n:[*islice(filter(lambda k:k%sum(map(int,str(k)))==0,count(1)),n)]
  • ```
  • * `itertools.count()` generates integer numbers starting from 1,
  • * `filter()` filters out the Niven numbers,
  • * `itertools.islice()` limits the result to `n` items,
  • * and `[*...]` collects the numbers in a list.
#2: Post edited by user avatar __blackjack__‭ · 2022-08-23T21:31:57Z (over 2 years ago)
Shortened import.
  • # Python, 113 bytes
  • ```python
  • from itertools import count,islice
  • f=lambda n:list(islice(filter(lambda k:k%sum(map(int,str(k)))==0,count(1)),n))
  • ```
  • * `itertools.count()` generates integer numbers starting from 1,
  • * `filter()` filters out the Niven numbers,
  • * `itertools.islice()` limits the result to `n` items,
  • * and `list()` collects the numbers in a list.
  • # Python, 101 bytes
  • ```python
  • from itertools import*
  • f=lambda n:list(islice(filter(lambda k:k%sum(map(int,str(k)))==0,count(1)),n))
  • ```
  • * `itertools.count()` generates integer numbers starting from 1,
  • * `filter()` filters out the Niven numbers,
  • * `itertools.islice()` limits the result to `n` items,
  • * and `list()` collects the numbers in a list.
#1: Initial revision by user avatar __blackjack__‭ · 2022-08-23T14:36:27Z (over 2 years ago)
# Python, 113 bytes

```python
from itertools import count,islice
f=lambda n:list(islice(filter(lambda k:k%sum(map(int,str(k)))==0,count(1)),n))
```

* `itertools.count()` generates integer numbers starting from 1,
* `filter()` filters out the Niven numbers,
* `itertools.islice()` limits the result to `n` items,
* and `list()` collects the numbers in a list.