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Ruby, 63 bytes ->n{(2..16).max_by{|x|n.digits(x).sum{45088003.digits(3)[_1]}}} Attempt This Online!
Answer
#1: Initial revision
by
steffan153
·
2022-09-30T03:10:31Z (about 2 years ago)
# [Ruby](https://www.ruby-lang.org/), 63 bytes
```ruby
->n{(2..16).max_by{|x|n.digits(x).sum{45088003.digits(3)[_1]}}}
````
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