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#14: Post edited
Balanced quinary quasiquine
- Balanced quinary quasiquine [FINALIZED]
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
- <details>
- <summary>Quinary</summary>
- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
- </details>
- <details>
- <summary>Balanced quinary</summary>
- Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.
- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- </details>
- ## Input
- - The input will be an integer in balanced quinary
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- - The input may correspond to a value larger in magnitude (absolute value) than the number of characters in your source code
- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- - If the magnitude (absolute value) of $N$ is greater than the number of characters in your source code, the output consists of your entire source code
- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- - The output may include an optional trailing newline
- - If $N=0$ the output must be empty (apart from the optional trailing newline)
- ## Excluded trivial cases
- Using source code of length $3$ or fewer ***characters*** is defined to be a challenge-specific loophole, and is []()not a valid answer.
- <details>
- <summary>Detailed justification</summary>
- Source code with length $3$ characters or fewer meets the requirements trivially, without requiring an implementation of balanced quinary.
- In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.
- The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs, regardless of value. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).
- </details>
- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
- > Explanations in answers are optional, but I'm more likely to upvote answers that have one.[]()
- # Now posted: [Balanced quinary quasiquine](https://codegolf.codidact.com/posts/287173)
- ---
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
- <details>
- <summary>Quinary</summary>
- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
- </details>
- <details>
- <summary>Balanced quinary</summary>
- Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.
- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- </details>
- ## Input
- - The input will be an integer in balanced quinary
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- - The input may correspond to a value larger in magnitude (absolute value) than the number of characters in your source code
- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- - If the magnitude (absolute value) of $N$ is greater than the number of characters in your source code, the output consists of your entire source code
- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- - The output may include an optional trailing newline
- - If $N=0$ the output must be empty (apart from the optional trailing newline)
- ## Excluded trivial cases
- Using source code of length $3$ or fewer ***characters*** is defined to be a challenge-specific loophole, and is []()not a valid answer.
- <details>
- <summary>Detailed justification</summary>
- Source code with length $3$ characters or fewer meets the requirements trivially, without requiring an implementation of balanced quinary.
- In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.
- The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs, regardless of value. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).
- </details>
- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
- > Explanations in answers are optional, but I'm more likely to upvote answers that have one.[]()
#13: Post edited
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
- <details>
- <summary>Quinary</summary>
- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
- </details>
- <details>
- <summary>Balanced quinary</summary>
- Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.
- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- </details>
- ## Input
- - The input will be an integer in balanced quinary
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- - The input may correspond to a value larger in magnitude (absolute value) than the number of characters in your source code
- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- - If the magnitude (absolute value) of $N$ is greater than the number of characters in your source code, the output consists of your entire source code
- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- - The output may include an optional trailing newline
- - If $N=0$ the output must be empty (apart from the optional trailing newline)
- ## Excluded trivial cases
Using source code of length $3$ or fewer ***characters*** is defined to be a challenge-specific loophole, and not a valid answer.- <details>
- <summary>Detailed justification</summary>
- Source code with length $3$ characters or fewer meets the requirements trivially, without requiring an implementation of balanced quinary.
- In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.
- The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs, regardless of value. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).
- </details>
- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
> Explanations in answers are optional, but I'm more likely to upvote answers that have one.
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
- <details>
- <summary>Quinary</summary>
- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
- </details>
- <details>
- <summary>Balanced quinary</summary>
- Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.
- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- </details>
- ## Input
- - The input will be an integer in balanced quinary
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- - The input may correspond to a value larger in magnitude (absolute value) than the number of characters in your source code
- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- - If the magnitude (absolute value) of $N$ is greater than the number of characters in your source code, the output consists of your entire source code
- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- - The output may include an optional trailing newline
- - If $N=0$ the output must be empty (apart from the optional trailing newline)
- ## Excluded trivial cases
- Using source code of length $3$ or fewer ***characters*** is defined to be a challenge-specific loophole, and is []()not a valid answer.
- <details>
- <summary>Detailed justification</summary>
- Source code with length $3$ characters or fewer meets the requirements trivially, without requiring an implementation of balanced quinary.
- In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.
- The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs, regardless of value. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).
- </details>
- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
- > Explanations in answers are optional, but I'm more likely to upvote answers that have one.[]()
#12: Post edited
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
- <details>
- <summary>Quinary</summary>
- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
- </details>
- <details>
- <summary>Balanced quinary</summary>
- Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.
- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- </details>
- ## Input
- - The input will be an integer in balanced quinary
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- - The input may correspond to a value larger in magnitude (absolute value) than the number of characters in your source code
- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- - If the magnitude (absolute value) of $N$ is greater than the number of characters in your source code, the output consists of your entire source code
- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- If $N=0$ the output must be empty (with any permitted exceptions, such as allowing a trailing newline)- ## Excluded trivial cases
- Using source code of length $3$ or fewer ***characters*** is defined to be a challenge-specific loophole, and not a valid answer.
- <details>
- <summary>Detailed justification</summary>
- Source code with length $3$ characters or fewer meets the requirements trivially, without requiring an implementation of balanced quinary.
- In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.
- The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs, regardless of value. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).
- </details>
- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
- > Explanations in answers are optional, but I'm more likely to upvote answers that have one.
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
- <details>
- <summary>Quinary</summary>
- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
- </details>
- <details>
- <summary>Balanced quinary</summary>
- Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.
- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- </details>
- ## Input
- - The input will be an integer in balanced quinary
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- - The input may correspond to a value larger in magnitude (absolute value) than the number of characters in your source code
- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- - If the magnitude (absolute value) of $N$ is greater than the number of characters in your source code, the output consists of your entire source code
- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- - The output may include an optional trailing newline
- - If $N=0$ the output must be empty (apart from the optional trailing newline)
- ## Excluded trivial cases
- Using source code of length $3$ or fewer ***characters*** is defined to be a challenge-specific loophole, and not a valid answer.
- <details>
- <summary>Detailed justification</summary>
- Source code with length $3$ characters or fewer meets the requirements trivially, without requiring an implementation of balanced quinary.
- In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.
- The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs, regardless of value. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).
- </details>
- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
- > Explanations in answers are optional, but I'm more likely to upvote answers that have one.
#11: Post edited
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
- <details>
- <summary>Quinary</summary>
- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
- </details>
- <details>
- <summary>Balanced quinary</summary>
- Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.
- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- </details>
- ## Input
- - The input will be an integer in balanced quinary
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- The input may correspond to a value larger in magnitude than the number of characters in your source code- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- If $N$ (or $-N$) is greater than the number of characters in your source code, the output consists of your entire source code- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- - If $N=0$ the output must be empty (with any permitted exceptions, such as allowing a trailing newline)
- ## Excluded trivial cases
- Using source code of length $3$ or fewer ***characters*** is defined to be a challenge-specific loophole, and not a valid answer.
- <details>
- <summary>Detailed justification</summary>
- Source code with length $3$ characters or fewer meets the requirements trivially, without requiring an implementation of balanced quinary.
- In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.
- The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs, regardless of value. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).
- </details>
- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
- > Explanations in answers are optional, but I'm more likely to upvote answers that have one.
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
- <details>
- <summary>Quinary</summary>
- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
- </details>
- <details>
- <summary>Balanced quinary</summary>
- Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.
- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- </details>
- ## Input
- - The input will be an integer in balanced quinary
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- - The input may correspond to a value larger in magnitude (absolute value) than the number of characters in your source code
- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- - If the magnitude (absolute value) of $N$ is greater than the number of characters in your source code, the output consists of your entire source code
- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- - If $N=0$ the output must be empty (with any permitted exceptions, such as allowing a trailing newline)
- ## Excluded trivial cases
- Using source code of length $3$ or fewer ***characters*** is defined to be a challenge-specific loophole, and not a valid answer.
- <details>
- <summary>Detailed justification</summary>
- Source code with length $3$ characters or fewer meets the requirements trivially, without requiring an implementation of balanced quinary.
- In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.
- The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs, regardless of value. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).
- </details>
- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
- > Explanations in answers are optional, but I'm more likely to upvote answers that have one.
#10: Post edited
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
- <details>
- <summary>Quinary</summary>
- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
- </details>
- <details>
- <summary>Balanced quinary</summary>
- Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.
- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- </details>
- ## Input
- - The input will be an integer in balanced quinary
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- - The input may correspond to a value larger in magnitude than the number of characters in your source code
- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- - If $N$ (or $-N$) is greater than the number of characters in your source code, the output consists of your entire source code
- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- - If $N=0$ the output must be empty (with any permitted exceptions, such as allowing a trailing newline)
- ## Excluded trivial cases
- Using source code of length $3$ or fewer ***characters*** is defined to be a challenge-specific loophole, and not a valid answer.
- <details>
- <summary>Detailed justification</summary>
Source code with length $3$ characters or less meets the requirements trivially, without requiring an implementation of balanced quinary.- In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.
- The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs, regardless of value. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).
- </details>
- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
- > Explanations in answers are optional, but I'm more likely to upvote answers that have one.
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
- <details>
- <summary>Quinary</summary>
- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
- </details>
- <details>
- <summary>Balanced quinary</summary>
- Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.
- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- </details>
- ## Input
- - The input will be an integer in balanced quinary
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- - The input may correspond to a value larger in magnitude than the number of characters in your source code
- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- - If $N$ (or $-N$) is greater than the number of characters in your source code, the output consists of your entire source code
- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- - If $N=0$ the output must be empty (with any permitted exceptions, such as allowing a trailing newline)
- ## Excluded trivial cases
- Using source code of length $3$ or fewer ***characters*** is defined to be a challenge-specific loophole, and not a valid answer.
- <details>
- <summary>Detailed justification</summary>
- Source code with length $3$ characters or fewer meets the requirements trivially, without requiring an implementation of balanced quinary.
- In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.
- The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs, regardless of value. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).
- </details>
- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
- > Explanations in answers are optional, but I'm more likely to upvote answers that have one.
#9: Post edited
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
- <details>
- <summary>Quinary</summary>
- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
- </details>
- <details>
- <summary>Balanced quinary</summary>
Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is still worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- </details>
- ## Input
- - The input will be an integer in balanced quinary
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- - The input may correspond to a value larger in magnitude than the number of characters in your source code
- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- - If $N$ (or $-N$) is greater than the number of characters in your source code, the output consists of your entire source code
- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- - If $N=0$ the output must be empty (with any permitted exceptions, such as allowing a trailing newline)
- ## Excluded trivial cases
- Using source code of length $3$ or fewer ***characters*** is defined to be a challenge-specific loophole, and not a valid answer.
- <details>
- <summary>Detailed justification</summary>
- Source code with length $3$ characters or less meets the requirements trivially, without requiring an implementation of balanced quinary.
- In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.
- The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs, regardless of value. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).
- </details>
- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
- > Explanations in answers are optional, but I'm more likely to upvote answers that have one.
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
- <details>
- <summary>Quinary</summary>
- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
- </details>
- <details>
- <summary>Balanced quinary</summary>
- Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.
- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- </details>
- ## Input
- - The input will be an integer in balanced quinary
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- - The input may correspond to a value larger in magnitude than the number of characters in your source code
- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- - If $N$ (or $-N$) is greater than the number of characters in your source code, the output consists of your entire source code
- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- - If $N=0$ the output must be empty (with any permitted exceptions, such as allowing a trailing newline)
- ## Excluded trivial cases
- Using source code of length $3$ or fewer ***characters*** is defined to be a challenge-specific loophole, and not a valid answer.
- <details>
- <summary>Detailed justification</summary>
- Source code with length $3$ characters or less meets the requirements trivially, without requiring an implementation of balanced quinary.
- In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.
- The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs, regardless of value. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).
- </details>
- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
- > Explanations in answers are optional, but I'm more likely to upvote answers that have one.
#8: Post edited
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
### Quinary- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
### Balanced quinary- Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is still worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.
- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- ## Input
- - The input will be an integer in balanced quinary
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- - The input may correspond to a value larger in magnitude than the number of characters in your source code
- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- - If $N$ (or $-N$) is greater than the number of characters in your source code, the output consists of your entire source code
- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- - If $N=0$ the output must be empty (with any permitted exceptions, such as allowing a trailing newline)
- ## Excluded trivial cases
- Using source code of length $3$ or fewer ***characters*** is defined to be a challenge-specific loophole, and not a valid answer.
- <details>
- <summary>Detailed justification</summary>
- Source code with length $3$ characters or less meets the requirements trivially, without requiring an implementation of balanced quinary.
- In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.
- The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs, regardless of value. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).
- </details>
- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
- > Explanations in answers are optional, but I'm more likely to upvote answers that have one.
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
- <details>
- <summary>Quinary</summary>
- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
- </details>
- <details>
- <summary>Balanced quinary</summary>
- Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is still worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.
- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- </details>
- ## Input
- - The input will be an integer in balanced quinary
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- - The input may correspond to a value larger in magnitude than the number of characters in your source code
- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- - If $N$ (or $-N$) is greater than the number of characters in your source code, the output consists of your entire source code
- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- - If $N=0$ the output must be empty (with any permitted exceptions, such as allowing a trailing newline)
- ## Excluded trivial cases
- Using source code of length $3$ or fewer ***characters*** is defined to be a challenge-specific loophole, and not a valid answer.
- <details>
- <summary>Detailed justification</summary>
- Source code with length $3$ characters or less meets the requirements trivially, without requiring an implementation of balanced quinary.
- In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.
- The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs, regardless of value. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).
- </details>
- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
- > Explanations in answers are optional, but I'm more likely to upvote answers that have one.
#7: Post edited
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
- ### Quinary
- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
- ### Balanced quinary
- Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is still worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.
- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- ## Input
- - The input will be an integer in balanced quinary
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- - The input may correspond to a value larger in magnitude than the number of characters in your source code
- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- - If $N$ (or $-N$) is greater than the number of characters in your source code, the output consists of your entire source code
- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- - If $N=0$ the output must be empty (with any permitted exceptions, such as allowing a trailing newline)
- ## Excluded trivial cases
In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).Source code with length $3$ characters or less meets the requirements trivially, without requiring an implementation of balanced quinary. Using source code of length $3$ or fewer *characters* is therefore defined to be a challenge-specific loophole, and not a valid answer.- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
- > Explanations in answers are optional, but I'm more likely to upvote answers that have one.
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
- ### Quinary
- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
- ### Balanced quinary
- Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is still worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.
- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- ## Input
- - The input will be an integer in balanced quinary
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- - The input may correspond to a value larger in magnitude than the number of characters in your source code
- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- - If $N$ (or $-N$) is greater than the number of characters in your source code, the output consists of your entire source code
- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- - If $N=0$ the output must be empty (with any permitted exceptions, such as allowing a trailing newline)
- ## Excluded trivial cases
- Using source code of length $3$ or fewer ***characters*** is defined to be a challenge-specific loophole, and not a valid answer.
- <details>
- <summary>Detailed justification</summary>
- Source code with length $3$ characters or less meets the requirements trivially, without requiring an implementation of balanced quinary.
- In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.
- The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs, regardless of value. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).
- </details>
- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
- > Explanations in answers are optional, but I'm more likely to upvote answers that have one.
#6: Post edited
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
- ### Quinary
- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
- ### Balanced quinary
- Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is still worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.
- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- ## Input
- - The input will be an integer in balanced quinary
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- - The input may correspond to a value larger in magnitude than the number of characters in your source code
- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- - If $N$ (or $-N$) is greater than the number of characters in your source code, the output consists of your entire source code
- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- - If $N=0$ the output must be empty (with any permitted exceptions, such as allowing a trailing newline)
- ## Excluded trivial cases
- In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.
- The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).
Source code with length $3$ or less meets the requirements trivially, without requiring an implementation of balanced quinary. Using source code of length $3$ or fewer *characters* is a challenge-specific loophole, and not a valid answer.- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
- > Explanations in answers are optional, but I'm more likely to upvote answers that have one.
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
- ### Quinary
- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
- ### Balanced quinary
- Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is still worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.
- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- ## Input
- - The input will be an integer in balanced quinary
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- - The input may correspond to a value larger in magnitude than the number of characters in your source code
- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- - If $N$ (or $-N$) is greater than the number of characters in your source code, the output consists of your entire source code
- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- - If $N=0$ the output must be empty (with any permitted exceptions, such as allowing a trailing newline)
- ## Excluded trivial cases
- In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.
- The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).
- Source code with length $3$ characters or less meets the requirements trivially, without requiring an implementation of balanced quinary. Using source code of length $3$ or fewer *characters* is therefore defined to be a challenge-specific loophole, and not a valid answer.
- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
- > Explanations in answers are optional, but I'm more likely to upvote answers that have one.
#5: Post edited
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
- ### Quinary
- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
- ### Balanced quinary
- Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is still worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.
- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- ## Input
- - The input will be an integer in balanced quinary
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- The input may correspond to a value larger in magnitude than the length of your source code- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- - If $N$ (or $-N$) is greater than the number of characters in your source code, the output consists of your entire source code
- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- - If $N=0$ the output must be empty (with any permitted exceptions, such as allowing a trailing newline)
- ## Excluded trivial cases
- In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.
- The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).
- Source code with length $3$ or less meets the requirements trivially, without requiring an implementation of balanced quinary. Using source code of length $3$ or fewer *characters* is a challenge-specific loophole, and not a valid answer.
- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
- > Explanations in answers are optional, but I'm more likely to upvote answers that have one.
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
- ### Quinary
- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
- ### Balanced quinary
- Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is still worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.
- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- ## Input
- - The input will be an integer in balanced quinary
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- - The input may correspond to a value larger in magnitude than the number of characters in your source code
- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- - If $N$ (or $-N$) is greater than the number of characters in your source code, the output consists of your entire source code
- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- - If $N=0$ the output must be empty (with any permitted exceptions, such as allowing a trailing newline)
- ## Excluded trivial cases
- In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.
- The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).
- Source code with length $3$ or less meets the requirements trivially, without requiring an implementation of balanced quinary. Using source code of length $3$ or fewer *characters* is a challenge-specific loophole, and not a valid answer.
- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
- > Explanations in answers are optional, but I'm more likely to upvote answers that have one.
#4: Post edited
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
- ### Quinary
- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
- ### Balanced quinary
- Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is still worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.
- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- ## Input
- - The input will be an integer in balanced quinary
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- - The input may correspond to a value larger in magnitude than the length of your source code
- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- If $N$ (or $-N$) is greater than the length of your source code, the output consists of your entire source code- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- - If $N=0$ the output must be empty (with any permitted exceptions, such as allowing a trailing newline)
- ## Excluded trivial cases
- In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.
- The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).
- Source code with length $3$ or less meets the requirements trivially, without requiring an implementation of balanced quinary. Using source code of length $3$ or fewer *characters* is a challenge-specific loophole, and not a valid answer.
- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
- > Explanations in answers are optional, but I'm more likely to upvote answers that have one.
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
- ### Quinary
- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
- ### Balanced quinary
- Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is still worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.
- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- ## Input
- - The input will be an integer in balanced quinary
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- - The input may correspond to a value larger in magnitude than the length of your source code
- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- - If $N$ (or $-N$) is greater than the number of characters in your source code, the output consists of your entire source code
- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- - If $N=0$ the output must be empty (with any permitted exceptions, such as allowing a trailing newline)
- ## Excluded trivial cases
- In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.
- The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).
- Source code with length $3$ or less meets the requirements trivially, without requiring an implementation of balanced quinary. Using source code of length $3$ or fewer *characters* is a challenge-specific loophole, and not a valid answer.
- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
- > Explanations in answers are optional, but I'm more likely to upvote answers that have one.
#3: Post edited
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
- ### Quinary
- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
- ### Balanced quinary
- Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is still worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.
- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- ## Input
- - The input will be an integer in balanced quinary
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- - The input may correspond to a value larger in magnitude than the length of your source code
- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- - If $N$ (or $-N$) is greater than the length of your source code, the output consists of your entire source code
- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- - If $N=0$ the output must be empty (with any permitted exceptions, such as allowing a trailing newline)
- ## Excluded trivial cases
- In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.
- The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).
Source code with length $3$ or less meets the requirements trivially, without requiring an implementation of balanced quinary. Using source code of length $3$ or fewer *characters* is a challenge-specific loophole.- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
- > Explanations in answers are optional, but I'm more likely to upvote answers that have one.
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
- ### Quinary
- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
- ### Balanced quinary
- Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is still worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.
- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- ## Input
- - The input will be an integer in balanced quinary
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- - The input may correspond to a value larger in magnitude than the length of your source code
- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- - If $N$ (or $-N$) is greater than the length of your source code, the output consists of your entire source code
- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- - If $N=0$ the output must be empty (with any permitted exceptions, such as allowing a trailing newline)
- ## Excluded trivial cases
- In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.
- The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).
- Source code with length $3$ or less meets the requirements trivially, without requiring an implementation of balanced quinary. Using source code of length $3$ or fewer *characters* is a challenge-specific loophole, and not a valid answer.
- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
- > Explanations in answers are optional, but I'm more likely to upvote answers that have one.
#2: Post edited
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
- ### Quinary
- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
- ### Balanced quinary
- Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is still worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.
- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- ## Input
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- - The input may correspond to a value larger in magnitude than the length of your source code
- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- - If $N$ (or $-N$) is greater than the length of your source code, the output consists of your entire source code
- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- - If $N=0$ the output must be empty (with any permitted exceptions, such as allowing a trailing newline)
- ## Excluded trivial cases
- In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.
- The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).
- Source code with length $3$ or less meets the requirements trivially, without requiring an implementation of balanced quinary. Using source code of length $3$ or fewer *characters* is a challenge-specific loophole.
- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
- > Explanations in answers are optional, but I'm more likely to upvote answers that have one.
- Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative.
- ## Terminology
- ### Quinary
- Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value.
- For example, the quinary number $1234$ converts to decimal like this:
- $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$
- $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$
- $$125+50+15+4$$
- $$194$$
- ### Balanced quinary
- Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is still worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol.
- For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$.
- For example, the balanced quinary number $YZ12$ converts to decimal like this:
- $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$
- $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$
- $$-250-25+5+2$$
- $$-268$$
- ## Input
- - The input will be an integer in balanced quinary
- - You may choose any $5$ characters to represent the $5$ digits of balanced quinary
- - The input will never have leading zeroes
- - The input may correspond to a value larger in magnitude than the length of your source code
- ## Output
- For input that evaluates to $N$:
- - If $N$ is positive, the output is the first $N$ characters of your source code
- - If $N$ is negative, the output is the last $-N$ characters of your source code
- - If $N$ (or $-N$) is greater than the length of your source code, the output consists of your entire source code
- - The required characters of your source code must be output in order
- - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order.
- If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE`
- - If $N=0$ the output must be empty (with any permitted exceptions, such as allowing a trailing newline)
- ## Excluded trivial cases
- In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits.
- The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes).
- Source code with length $3$ or less meets the requirements trivially, without requiring an implementation of balanced quinary. Using source code of length $3$ or fewer *characters* is a challenge-specific loophole.
- ## Scoring
- This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better.
- *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.*
- > Explanations in answers are optional, but I'm more likely to upvote answers that have one.
#1: Initial revision
Balanced quinary quasiquine
Give an integer $N$ in balanced quinary, output the first $N$ characters of your source code if $N$ is positive, or the last $-N$ characters of your source code if $N$ is negative. ## Terminology ### Quinary Standard quinary (base $5$) has digits $0, 1, 2, 3, 4$. In a quinary number a digit $n$ places from the right is worth $5^n$ times that digit's individual value. For example, the quinary number $1234$ converts to decimal like this: $$(1\times5^3)+(2\times5^2)+(3\times5^1)+(4\times5^0)$$ $$(1\times125)+(2\times25)+(3\times5)+(4\times1)$$ $$125+50+15+4$$ $$194$$ ### Balanced quinary Balanced quinary works exactly the same as standard quinary, except it uses digits worth $-2,-1,0,1,2$. In a balanced quinary number a digit $n$ places from the right is still worth $5^n$ times that digit's individual value, just like in standard quinary. This allows balanced quinary to express all positive and negative integers without the need for a leading minus sign / negation symbol. For the following example we will use $Y$ to represent $-2$ and $Z$ to represent $-1$, so our digits are $Y,Z,0,1,2$. For example, the balanced quinary number $YZ12$ converts to decimal like this: $$(Y\times5^3)+(Z\times5^2)+(1\times5^1)+(2\times5^0)$$ $$(-2\times125)+(-1\times25)+(1\times5)+(2\times1)$$ $$-250-25+5+2$$ $$-268$$ ## Input - You may choose any $5$ characters to represent the $5$ digits of balanced quinary - The input will never have leading zeroes - The input may correspond to a value larger in magnitude than the length of your source code ## Output For input that evaluates to $N$: - If $N$ is positive, the output is the first $N$ characters of your source code - If $N$ is negative, the output is the last $-N$ characters of your source code - If $N$ (or $-N$) is greater than the length of your source code, the output consists of your entire source code - The required characters of your source code must be output in order - Specifically, if $N$ is negative, the last $-N$ characters must not be in reversed order. If your source code is `QUINTESSENTIAL` the last $9$ characters are `ESSENTIAL`, not `LAITNESSE` - If $N=0$ the output must be empty (with any permitted exceptions, such as allowing a trailing newline) ## Excluded trivial cases In order to demonstrate that it is correctly interpreting the balanced quinary base system (not just the individual digits), your code must have at least $2$ different outputs for inputs with $2$ digits. The smallest magnitude of a $2$ digit balanced quinary number is $3$. This means that source code of $3$ or fewer characters would lead to the full source code being output for all $2$ digit inputs. The shortest source code length that can lead to different outputs for different $2$ digit inputs is therefore length $4$ ($4$ characters - even in cases where that means more than $4$ bytes). Source code with length $3$ or less meets the requirements trivially, without requiring an implementation of balanced quinary. Using source code of length $3$ or fewer *characters* is a challenge-specific loophole. ## Scoring This is a code golf challenge. Your score is the length of your source code in bytes. Lower is better. *Note that your score is in bytes, but the required length of output is measured in characters, in case the two are not equivalent for your chosen language.* > Explanations in answers are optional, but I'm more likely to upvote answers that have one.