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Challenges

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Challenges Balanced quinary quasiquine

Vyxal D, 62 bytes `$f3uV4udV5β$I$:∇₍λ2|62∵Ẏ;ȯ$0<i`$f3uV4udV5β$I$:∇₍λ2|62∵Ẏ;ȯ$0<i Try it Online! Character map: 4 : -2 3 : -1 0 : 0 1 : 1 2 : 2 Nice, long and yummy quine. Explai...

posted 2y ago by lyxal‭

Answer
#1: Initial revision by user avatar lyxal‭ · 2022-10-18T04:18:00Z (about 2 years ago)
# [Vyxal](https://github.com/Vyxal/Vyxal) `D`, 62 bytes

```
`$f3uV4udV5β$I$:∇₍λ2|62∵Ẏ;ȯ$0<i`$f3uV4udV5β$I$:∇₍λ2|62∵Ẏ;ȯ$0<i
```
[Try it Online!](https://vyxal.pythonanywhere.com/#WyJEQSIsIiIsImAkZjN1VjR1ZFY1zrIkSSQ64oiH4oKNzrsyfDYy4oi14bqOO8ivJDA8aWAkZjN1VjR1ZFY1zrIkSSQ64oiH4oKNzrsyfDYy4oi14bqOO8ivJDA8aSIsIiIsIjBcbjNcbjFcbjRcbjJcbjMyXG4xNFxuMzFcbjMwXG4xMDAwXG4zMDAwXG4yMzAiXQ==)

Character map:

```
4 : -2
3 : -1
0 : 0
1 : 1
2 : 2
```

Nice, long and yummy quine.

## Explained

```
`$f3uV4udV5β$I$:∇₍λ2|62∵Ẏ;ȯ$0<i`            
```

Push the string `"$f3uV4udV5β$I$:∇₍λ2|62∵Ẏ;ȯ$0<i"` to the stack. This is the "data" of the quine. Now onto the code part:

```
$f3uV4udV5β
$f          # Push a list of digits of the input in front of that string
  3uV       # Replace all 3s with -1
     4udV   # And replace all 4s with -2
         5β # And convert that to base 5. Vyxal is smart enough to know how to handle negative digits in the list.
```

The above does the balanced quinary conversion.

```
$I$:∇
$I     # Swap the top two stack items to make the stack [quinary number, data string", and quine cheese the string (surround it in backticks and append it to itself)
  $:∇ # Swap the top two stack items to make the stack [string, number], duplicate the number and then rotate the stack so it becomes [number, string, number] - this will be used to determine which end to get characters from
```

```
₍λ2|62∵Ẏ;ȯ
₍          # Apply the next two things to the same stack:
 λ2|62∵Ẏ;  #   string[0:min(62, number)]
         ȯ #   string[number:]
```

This gets `number` characters from both the start and end of the string, because there's no built-in to conditionally get either start or end. Also, the lambda is needed to avoid modular indexing with `Ẏ`. The stack will now be `[number, [string[0:min(62, number)], string[number:]]`.

```
$0<i
$      # Make the number the top of the stack again
 0<    # is it negative?
   i   # index that into the [string[0:min(62, number)], string[number:] list - if number is negative, it'll get string[number:]. Otherwise, it'll get string[0:min(62, number)]
```