Post History
Dyalog APL, 21 bytes {≢⍸6=(≢∪)¨⍳⍵/6}÷(6∘*) Bruteforce solution :) ⍳⍵/6 n-dimensional array of all possibilities of rolling $n$ dice, each element is a vector of the dice values ≢ count the ...
Answer
#2: Post edited
by
RubenVerg
·
2023-07-09T09:55:51Z (over 1 year ago)
-1 byte
# Dyalog APL, 22 bytes- ```apl
{+/6=(≢∪)¨,⍳⍵/6}÷(6∘*)- ```
- Bruteforce solution :)
* `,⍳⍵/6` of all possibilities of rolling $n$ dice, as a list of lists* `+/` count the elements where- * `(≢∪)¨` the length of the unique elements
- * `6=` is equal to 6
- * `÷` and divide by
- * `6∘*` 6 to the power of $n$
- # Dyalog APL, 21 bytes
- ```apl
- {≢⍸6=(≢∪)¨⍳⍵/6}÷(6∘*)
- ```
- Bruteforce solution :)
- * `⍳⍵/6` n-dimensional array of all possibilities of rolling $n$ dice, each element is a vector of the dice values
- * `≢` count the elements
- * `⍸` where it is true that
- * `(≢∪)¨` the length of the unique elements
- * `6=` is equal to 6
- * `÷` and divide by
- * `6∘*` 6 to the power of $n$
#1: Initial revision
by
RubenVerg
·
2023-07-08T15:38:14Z (over 1 year ago)
# Dyalog APL, 22 bytes
```apl
{+/6=(≢∪)¨,⍳⍵/6}÷(6∘*)
```
Bruteforce solution :)
* `,⍳⍵/6` of all possibilities of rolling $n$ dice, as a list of lists
* `+/` count the elements where
* `(≢∪)¨` the length of the unique elements
* `6=` is equal to 6
* `÷` and divide by
* `6∘*` 6 to the power of $n$