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C, 30 + 1-4 byte f(m){f(printf("%0*i\n",m,0));} Has this limitations: counter stops working at INT_MAX or at stack overflow. Needs a input value to indicate on which line we start. 0 starts...
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#4: Post edited
by
H_H
·
2023-09-08T15:07:09Z (8 months ago)
## C, 30 bytes + 1-4 byte- f(m){f(printf("%0*i\n",m,0));}
- Has this limitations:
- - counter stops working at `INT_MAX` or at stack overflow.
- - Needs a input value to indicate on which line we start. `0` starts on the line with one character.
- - It uses `0` and not `*` as output character
Because of the additional input number, i added the + 1 byte in the title. If you call the program, you need to write `f(0)`, this is why the +4 bytes in the title.### Fully working program, 36 bytes:- main(m){main(printf("%0*i\n",m,0));}
- ## C, 30 + 1-4 byte
- f(m){f(printf("%0*i\n",m,0));}
- Has this limitations:
- - counter stops working at `INT_MAX` or at stack overflow.
- - Needs a input value to indicate on which line we start. `0` starts on the line with one character.
- - It uses `0` and not `*` as output character
- Because of the additional input number, i added the + 1 in the title. If you call the program, you need to write `f(0)`, this is why the +4 in the title.
- ### Fully working program, 36 byte:
- main(m){main(printf("%0*i\n",m,0));}
#3: Post edited
by
H_H
·
2023-09-04T16:39:09Z (8 months ago)
- ## C, 30 bytes + 1-4 byte
`f(m){f(printf("%0*i",m,0));}`- Has this limitations:
- - counter stops working at `INT_MAX` or at stack overflow.
- - Needs a input value to indicate on which line we start. `0` starts on the line with one character.
- - It uses `0` and not `*` as output character
- Because of the additional input number, i added the + 1 byte in the title. If you call the program, you need to write `f(0)`, this is why the +4 bytes in the title.
- ### Fully working program, 36 bytes:
`main(m){main(printf("%0*i",m,0));}`
- ## C, 30 bytes + 1-4 byte
- f(m){f(printf("%0*i
- ",m,0));}
- Has this limitations:
- - counter stops working at `INT_MAX` or at stack overflow.
- - Needs a input value to indicate on which line we start. `0` starts on the line with one character.
- - It uses `0` and not `*` as output character
- Because of the additional input number, i added the + 1 byte in the title. If you call the program, you need to write `f(0)`, this is why the +4 bytes in the title.
- ### Fully working program, 36 bytes:
- main(m){main(printf("%0*i
- ",m,0));}
#2: Post edited
by
H_H
·
2023-08-30T14:17:07Z (8 months ago)
- ## C, 30 bytes + 1-4 byte
- `f(m){f(printf("%0*i\n",m,0));}`
- Has this limitations:
- counter stops working at `INT_MAX`, maybe a bit sooner.- - Needs a input value to indicate on which line we start. `0` starts on the line with one character.
- - It uses `0` and not `*` as output character
- Because of the additional input number, i added the + 1 byte in the title. If you call the program, you need to write `f(0)`, this is why the +4 bytes in the title.
- ### Fully working program, 36 bytes:
- `main(m){main(printf("%0*i\n",m,0));}`
- ## C, 30 bytes + 1-4 byte
- `f(m){f(printf("%0*i\n",m,0));}`
- Has this limitations:
- - counter stops working at `INT_MAX` or at stack overflow.
- - Needs a input value to indicate on which line we start. `0` starts on the line with one character.
- - It uses `0` and not `*` as output character
- Because of the additional input number, i added the + 1 byte in the title. If you call the program, you need to write `f(0)`, this is why the +4 bytes in the title.
- ### Fully working program, 36 bytes:
- `main(m){main(printf("%0*i\n",m,0));}`
#1: Initial revision
by
H_H
·
2023-08-30T14:15:02Z (8 months ago)
## C, 30 bytes + 1-4 byte
`f(m){f(printf("%0*i\n",m,0));}`
Has this limitations:
- counter stops working at `INT_MAX`, maybe a bit sooner.
- Needs a input value to indicate on which line we start. `0` starts on the line with one character.
- It uses `0` and not `*` as output character
Because of the additional input number, i added the + 1 byte in the title. If you call the program, you need to write `f(0)`, this is why the +4 bytes in the title.
### Fully working program, 36 bytes:
`main(m){main(printf("%0*i\n",m,0));}`