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Haskell, 62 bytes (\n->(scanl(*)1$cycle[5,2])!!(length$takeWhile(/=n)"IVXLCDM")) No import needed. It just uses standard Prelude functions. scanl(*)1$cycle[5,2] will give you the infinit...

posted 1y ago by Arpad Horvath‭  ·  edited 1y ago by Arpad Horvath‭

Answer
#5: Post edited by user avatar Arpad Horvath‭ · 2023-10-26T05:50:13Z (about 1 year ago)
  • # Haskell, 56 bytes
  • ```
  • (scanl(*)1$cycle[5,2])!!(length$takeWhile(/=n)"IVXLCDM")
  • ```
  • No import needed.
  • ```
  • scanl(*)1$cycle[5,2]
  • ```
  • will give you the infinite list of [1,5,10,50...]. With
  • ```
  • length$takeWhile(/=n)"IVXLCDM"
  • ```
  • you will get the index of the element you would like to look up.
  • If you set
  • ```haskell
  • n='V'
  • ```
  • the length part will be 1, and the index 1 means the 2nd element, so you'll get 5.
  • # Haskell, 62 bytes
  • ```
  • (\n->(scanl(*)1$cycle[5,2])!!(length$takeWhile(/=n)"IVXLCDM"))
  • ```
  • No import needed. It just uses standard Prelude functions.
  • ```
  • scanl(*)1$cycle[5,2]
  • ```
  • will give you the infinite list of [1,5,10,50...]. With
  • ```
  • length$takeWhile(/=n)"IVXLCDM"
  • ```
  • you will get the index of the element you would like to look up.
  • If you set
  • ```haskell
  • n='V'
  • ```
  • the length part will be 1, and the index 1 means the 2nd element, so you'll get 5.
#4: Post edited by user avatar Arpad Horvath‭ · 2023-10-25T15:44:54Z (about 1 year ago)
  • # Haskell, 56 bytes
  • ```
  • (scanl(*)1$cycle[5,2])!!(length$takeWhile(/=n)"IVXLCDM")
  • ```
  • ```
  • scanl(*)1$cycle[5,2]
  • ```
  • will give you the infinite list of [1,5,10,50...]. With
  • ```
  • length$takeWhile(/=n)"IVXLCDM"
  • ```
  • you will get the index of the element you would like to look up.
  • If you set
  • ```haskell
  • n='V'
  • ```
  • the length part will be 1, and the index 1 means the 2nd element, so you'll get 5.
  • # Haskell, 56 bytes
  • ```
  • (scanl(*)1$cycle[5,2])!!(length$takeWhile(/=n)"IVXLCDM")
  • ```
  • No import needed.
  • ```
  • scanl(*)1$cycle[5,2]
  • ```
  • will give you the infinite list of [1,5,10,50...]. With
  • ```
  • length$takeWhile(/=n)"IVXLCDM"
  • ```
  • you will get the index of the element you would like to look up.
  • If you set
  • ```haskell
  • n='V'
  • ```
  • the length part will be 1, and the index 1 means the 2nd element, so you'll get 5.
#3: Post edited by user avatar Arpad Horvath‭ · 2023-10-25T15:19:00Z (about 1 year ago)
  • # Haskell, 56 bytes
  • ```haskell
  • (scanl(*)1$cycle[5,2])!!(length$takeWhile(/=n)"IVXLCDM")
  • ```
  • If you set
  • ```haskell
  • n='V'
  • ```
  • you'll get 5.
  • # Haskell, 56 bytes
  • ```
  • (scanl(*)1$cycle[5,2])!!(length$takeWhile(/=n)"IVXLCDM")
  • ```
  • ```
  • scanl(*)1$cycle[5,2]
  • ```
  • will give you the infinite list of [1,5,10,50...]. With
  • ```
  • length$takeWhile(/=n)"IVXLCDM"
  • ```
  • you will get the index of the element you would like to look up.
  • If you set
  • ```haskell
  • n='V'
  • ```
  • the length part will be 1, and the index 1 means the 2nd element, so you'll get 5.
#2: Post edited by user avatar Arpad Horvath‭ · 2023-10-25T15:14:07Z (about 1 year ago)
  • # Haskell, 56 bytes
  • ```haskell
  • (scanl(*)1$cycle[5,2])!!(length$takeWhile(/=n)"IVXLCDM")
  • ```
  • # Haskell, 56 bytes
  • ```haskell
  • (scanl(*)1$cycle[5,2])!!(length$takeWhile(/=n)"IVXLCDM")
  • ```
  • If you set
  • ```haskell
  • n='V'
  • ```
  • you'll get 5.
#1: Initial revision by user avatar Arpad Horvath‭ · 2023-10-25T15:11:18Z (about 1 year ago)
# Haskell, 56 bytes

```haskell
(scanl(*)1$cycle[5,2])!!(length$takeWhile(/=n)"IVXLCDM")
```