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Python 3.8, 117 bytes def f(l): r,s,t=0,0,0 while s<len(l):_,s,t,r=[t:=max(t,(s+i+h)*(h>i))for i,h in enumerate(l[s:])],t,0,r+1 return r Try it online! The idea is to find the le...
Answer
#2: Post edited
by
justhalf
·
2023-11-23T06:26:48Z (6 months ago)
Update header
# [Python 3.8 (pre-release)], 117 bytes- <!-- language-all: lang-python -->
- def f(l):
- r,s,t=0,0,0
- while s<len(l):_,s,t,r=[t:=max(t,(s+i+h)*(h>i))for i,h in enumerate(l[s:])],t,0,r+1
- return r
- [Try it online!][TIO-lp9oxfzp]
- The idea is to find the left-most uncovered spot, find the umbrella that cover as many spots to the right as possible. Repeat until no more uncovered spot.
- I'm sure this can be golfed further.
[Python 3.8 (pre-release)]: https://docs.python.org/3.8/- [TIO-lp9oxfzp]: https://tio.run/##bY3NCsIwEITvfYocE7uH/lm0WF@kFCmYkECblk2K@vQxqVWoyrDLMh@zMz2sHHV@mNC5KxdE0J5VEUEwYOsEvCJyk6rnxJx6rgO9BAZYN7aqh@5OLVATq1iyHZVnxZgYkSiQRGnC9Txw7CynfWOqlrU@mADGqW/gdkZN0E2otKWCNkfIIIXc7yJcLWPRh6Ww0YaFVLFOyG/p/uUtE1R@/c2Wxt@2f375dldlnron "Python 3.8 (pre-release) – Try It Online"
- # [Python 3.8], 117 bytes
- <!-- language-all: lang-python -->
- def f(l):
- r,s,t=0,0,0
- while s<len(l):_,s,t,r=[t:=max(t,(s+i+h)*(h>i))for i,h in enumerate(l[s:])],t,0,r+1
- return r
- [Try it online!][TIO-lp9oxfzp]
- The idea is to find the left-most uncovered spot, find the umbrella that cover as many spots to the right as possible. Repeat until no more uncovered spot.
- I'm sure this can be golfed further.
- [Python 3.8]: https://docs.python.org/3.8/
- [TIO-lp9oxfzp]: https://tio.run/##bY3NCsIwEITvfYocE7uH/lm0WF@kFCmYkECblk2K@vQxqVWoyrDLMh@zMz2sHHV@mNC5KxdE0J5VEUEwYOsEvCJyk6rnxJx6rgO9BAZYN7aqh@5OLVATq1iyHZVnxZgYkSiQRGnC9Txw7CynfWOqlrU@mADGqW/gdkZN0E2otKWCNkfIIIXc7yJcLWPRh6Ww0YaFVLFOyG/p/uUtE1R@/c2Wxt@2f375dldlnron "Python 3.8 (pre-release) – Try It Online"
#1: Initial revision
by
justhalf
·
2023-11-22T11:39:17Z (6 months ago)
# [Python 3.8 (pre-release)], 117 bytes
<!-- language-all: lang-python -->
def f(l):
r,s,t=0,0,0
while s<len(l):_,s,t,r=[t:=max(t,(s+i+h)*(h>i))for i,h in enumerate(l[s:])],t,0,r+1
return r
[Try it online!][TIO-lp9oxfzp]
The idea is to find the left-most uncovered spot, find the umbrella that cover as many spots to the right as possible. Repeat until no more uncovered spot.
I'm sure this can be golfed further.
[Python 3.8 (pre-release)]: https://docs.python.org/3.8/
[TIO-lp9oxfzp]: https://tio.run/##bY3NCsIwEITvfYocE7uH/lm0WF@kFCmYkECblk2K@vQxqVWoyrDLMh@zMz2sHHV@mNC5KxdE0J5VEUEwYOsEvCJyk6rnxJx6rgO9BAZYN7aqh@5OLVATq1iyHZVnxZgYkSiQRGnC9Txw7CynfWOqlrU@mADGqW/gdkZN0E2otKWCNkfIIIXc7yJcLWPRh6Ww0YaFVLFOyG/p/uUtE1R@/c2Wxt@2f375dldlnron "Python 3.8 (pre-release) – Try It Online"