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The Context: I have officially deprecated SHA-2 and SHA-3. This decision stems from a critical security breach I witnessed: a virus that infected my system using forged digital signatures that wer...
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code-challenge
#5: Post edited
- **The Context:**
- I have officially deprecated SHA-2 and SHA-3. This decision stems from a critical security breach I witnessed: a virus that infected my system using forged digital signatures that were somehow validated as authentic by current standards. This proved that the 'trust' in existing hashing algorithms is compromised. Consequently, I have engineered Leviathan v3.1 Turbo to replace them with a system that doesn't just verify, but defends.
- **The Logic:**
- This algorithm uses a **Fractal Carry** system and a massive **10,000-digit Prime Constant** to ensure that even the slightest bit-flip in the input causes a catastrophic avalanche in the output.
- **The Task:**
- Simple. **Find a Collision.**
- Find two distinct inputs (strings or byte arrays) and such that:
- $$Leviathan(M_1) == Leviathan(M_2)$$
- Where $M_1 \neq M_2$
- **The Code:**
- The algorithm is fully **DETERMINISTIC**. No random salts. Pure math.
- **[Get the Source Code Here (OSF)](https://osf.io/8xb9h/files/aj92b)**
- **Why you will fail:**
- * The "Displaced Mutation Buffer" prevents linear collisions.
- * The output space is **1024 characters**. The Pigeonhole Principle is on my side, not yours.
- * The internal state evolves fractally, meaning depends non-linearly on .
Or maybe they’ll manage to break the algorithm!- **Rules**
- There will be a maximum of 3 winners. The first 3 to succeed will win, and they must present the algorithm or explain how their code works.
- **Prize:**
- The glory of breaking the first post-NIST hash algorithm.
- **"Good luck. You'll need more than a supercomputer; you'll need a new dimension."**
- **The Context:**
- I have officially deprecated SHA-2 and SHA-3. This decision stems from a critical security breach I witnessed: a virus that infected my system using forged digital signatures that were somehow validated as authentic by current standards. This proved that the 'trust' in existing hashing algorithms is compromised. Consequently, I have engineered Leviathan v3.1 Turbo to replace them with a system that doesn't just verify, but defends.
- **The Logic:**
- This algorithm uses a **Fractal Carry** system and a massive **10,000-digit Prime Constant** to ensure that even the slightest bit-flip in the input causes a catastrophic avalanche in the output.
- **The Task:**
- Simple. **Find a Collision.**
- Find two distinct inputs (strings or byte arrays) and such that:
- $$Leviathan(M_1) == Leviathan(M_2)$$
- Where $M_1 \neq M_2$
- **The Code:**
- The algorithm is fully **DETERMINISTIC**. No random salts. Pure math.
- **[Get the Source Code Here (OSF)](https://osf.io/8xb9h/files/aj92b)**
- **Why you will fail:**
- * The "Displaced Mutation Buffer" prevents linear collisions.
- * The output space is **1024 characters**. The Pigeonhole Principle is on my side, not yours.
- * The internal state evolves fractally, meaning depends non-linearly on .
- **Rules**
- There will be a maximum of 3 winners. The first 3 to succeed will win, and they must present the algorithm or explain how their code works.
- **Prize:**
- The glory of breaking the first post-NIST hash algorithm.
- **"Good luck. You'll need more than a supercomputer; you'll need a new dimension."**
#4: Post edited
- **The Context:**
- I have officially deprecated SHA-2 and SHA-3. This decision stems from a critical security breach I witnessed: a virus that infected my system using forged digital signatures that were somehow validated as authentic by current standards. This proved that the 'trust' in existing hashing algorithms is compromised. Consequently, I have engineered Leviathan v3.1 Turbo to replace them with a system that doesn't just verify, but defends.
- **The Logic:**
- This algorithm uses a **Fractal Carry** system and a massive **10,000-digit Prime Constant** to ensure that even the slightest bit-flip in the input causes a catastrophic avalanche in the output.
- **The Task:**
- Simple. **Find a Collision.**
- Find two distinct inputs (strings or byte arrays) and such that:
- $$Leviathan(M_1) == Leviathan(M_2)$$
- Where $M_1 \neq M_2$
- **The Code:**
- The algorithm is fully **DETERMINISTIC**. No random salts. Pure math.
- **[Get the Source Code Here (OSF)](https://osf.io/8xb9h/files/aj92b)**
- **Why you will fail:**
- * The "Displaced Mutation Buffer" prevents linear collisions.
- * The output space is **1024 characters**. The Pigeonhole Principle is on my side, not yours.
* The internal state evolves fractally, meaning depends non-linearly on .- **Rules**
- There will be a maximum of 3 winners. The first 3 to succeed will win, and they must present the algorithm or explain how their code works.
- **Prize:**
- The glory of breaking the first post-NIST hash algorithm.
- **"Good luck. You'll need more than a supercomputer; you'll need a new dimension."**
- **The Context:**
- I have officially deprecated SHA-2 and SHA-3. This decision stems from a critical security breach I witnessed: a virus that infected my system using forged digital signatures that were somehow validated as authentic by current standards. This proved that the 'trust' in existing hashing algorithms is compromised. Consequently, I have engineered Leviathan v3.1 Turbo to replace them with a system that doesn't just verify, but defends.
- **The Logic:**
- This algorithm uses a **Fractal Carry** system and a massive **10,000-digit Prime Constant** to ensure that even the slightest bit-flip in the input causes a catastrophic avalanche in the output.
- **The Task:**
- Simple. **Find a Collision.**
- Find two distinct inputs (strings or byte arrays) and such that:
- $$Leviathan(M_1) == Leviathan(M_2)$$
- Where $M_1 \neq M_2$
- **The Code:**
- The algorithm is fully **DETERMINISTIC**. No random salts. Pure math.
- **[Get the Source Code Here (OSF)](https://osf.io/8xb9h/files/aj92b)**
- **Why you will fail:**
- * The "Displaced Mutation Buffer" prevents linear collisions.
- * The output space is **1024 characters**. The Pigeonhole Principle is on my side, not yours.
- * The internal state evolves fractally, meaning depends non-linearly on .
- Or maybe they’ll manage to break the algorithm!
- **Rules**
- There will be a maximum of 3 winners. The first 3 to succeed will win, and they must present the algorithm or explain how their code works.
- **Prize:**
- The glory of breaking the first post-NIST hash algorithm.
- **"Good luck. You'll need more than a supercomputer; you'll need a new dimension."**
#3: Post edited
- **The Context:**
- I have officially deprecated SHA-2 and SHA-3. This decision stems from a critical security breach I witnessed: a virus that infected my system using forged digital signatures that were somehow validated as authentic by current standards. This proved that the 'trust' in existing hashing algorithms is compromised. Consequently, I have engineered Leviathan v3.1 Turbo to replace them with a system that doesn't just verify, but defends.
- **The Logic:**
- This algorithm uses a **Fractal Carry** system and a massive **10,000-digit Prime Constant** to ensure that even the slightest bit-flip in the input causes a catastrophic avalanche in the output.
- **The Task:**
- Simple. **Find a Collision.**
- Find two distinct inputs (strings or byte arrays) and such that:
- $$Leviathan(M_1) == Leviathan(M_2)$$
- Where $M_1 \neq M_2$
- **The Code:**
- The algorithm is fully **DETERMINISTIC**. No random salts. Pure math.
- **[Get the Source Code Here (OSF)](https://osf.io/8xb9h/files/aj92b)**
- **Why you will fail:**
- * The "Displaced Mutation Buffer" prevents linear collisions.
- * The output space is **1024 characters**. The Pigeonhole Principle is on my side, not yours.
- * The internal state evolves fractally, meaning depends non-linearly on .
- **Prize:**
- The glory of breaking the first post-NIST hash algorithm.
- **"Good luck. You'll need more than a supercomputer; you'll need a new dimension."**
- **The Context:**
- I have officially deprecated SHA-2 and SHA-3. This decision stems from a critical security breach I witnessed: a virus that infected my system using forged digital signatures that were somehow validated as authentic by current standards. This proved that the 'trust' in existing hashing algorithms is compromised. Consequently, I have engineered Leviathan v3.1 Turbo to replace them with a system that doesn't just verify, but defends.
- **The Logic:**
- This algorithm uses a **Fractal Carry** system and a massive **10,000-digit Prime Constant** to ensure that even the slightest bit-flip in the input causes a catastrophic avalanche in the output.
- **The Task:**
- Simple. **Find a Collision.**
- Find two distinct inputs (strings or byte arrays) and such that:
- $$Leviathan(M_1) == Leviathan(M_2)$$
- Where $M_1 \neq M_2$
- **The Code:**
- The algorithm is fully **DETERMINISTIC**. No random salts. Pure math.
- **[Get the Source Code Here (OSF)](https://osf.io/8xb9h/files/aj92b)**
- **Why you will fail:**
- * The "Displaced Mutation Buffer" prevents linear collisions.
- * The output space is **1024 characters**. The Pigeonhole Principle is on my side, not yours.
- * The internal state evolves fractally, meaning depends non-linearly on .
- **Rules**
- There will be a maximum of 3 winners. The first 3 to succeed will win, and they must present the algorithm or explain how their code works.
- **Prize:**
- The glory of breaking the first post-NIST hash algorithm.
- **"Good luck. You'll need more than a supercomputer; you'll need a new dimension."**
#1: Initial revision
💥 CHALLENGE: Find a Collision in Leviathan v3.1 (Deterministic)
**The Context:** I have officially deprecated SHA-2 and SHA-3. This decision stems from a critical security breach I witnessed: a virus that infected my system using forged digital signatures that were somehow validated as authentic by current standards. This proved that the 'trust' in existing hashing algorithms is compromised. Consequently, I have engineered Leviathan v3.1 Turbo to replace them with a system that doesn't just verify, but defends. **The Logic:** This algorithm uses a **Fractal Carry** system and a massive **10,000-digit Prime Constant** to ensure that even the slightest bit-flip in the input causes a catastrophic avalanche in the output. **The Task:** Simple. **Find a Collision.** Find two distinct inputs (strings or byte arrays) and such that: $$Leviathan(M_1) == Leviathan(M_2)$$ Where $M_1 \neq M_2$ **The Code:** The algorithm is fully **DETERMINISTIC**. No random salts. Pure math. **[Get the Source Code Here (OSF)](https://osf.io/8xb9h/files/aj92b)** **Why you will fail:** * The "Displaced Mutation Buffer" prevents linear collisions. * The output space is **1024 characters**. The Pigeonhole Principle is on my side, not yours. * The internal state evolves fractally, meaning depends non-linearly on . **Prize:** The glory of breaking the first post-NIST hash algorithm. **"Good luck. You'll need more than a supercomputer; you'll need a new dimension."**
