dino‭

Python 3, 56 bytes lambda x:chr(65+f'{int(float(x[:3]))&~8:08b}'.find('0')) Try it online! Takes in the ip address as a string and returns the classification letter. Explanation: x[:...

posted 3y ago by dino‭  ·  edited 3y ago by dino‭

Python3, 39 bytes lambda n:all(n%i**2for i in range(2,n)) Try it online! Makes a list comprehension from the numbers 2 through n of the remainder of the square, and then checks whether the lis...

posted 3y ago by dino‭  ·  edited 3y ago by dino‭

Python 3, 35 bytes lambda x:[chr(ord(i)|32)for i in x] Try it online! Performs a list comprehension on the input string; for each character it: transforms it into the ASCII character code...

posted 2y ago by dino‭

Python 3, 43 bytes lambda x:sorted(x,key='tibdfghklpqyj'.find) Try it online! Sorts based on index in a sorted string. Inputs as a string and outputs as a list. -14 bytes by replacing .inde...

posted 2y ago by dino‭  ·  edited 2y ago by dino‭

Python 3, 108 bytes lambda p,s:"Hole in one:Albatross:Eagle:Birdie:Par:Bogey:Double bogey:Triple bogey".split(':')[s-1and s-p+4] Try it online!

posted 3y ago by dino‭

Python 3.8 (pre-release), 69 bytes def f(x,y={},z=[]): for i in x:y[i]=y.get(i,0)+1;z+=[y[i]] return z Try it online! Bonus: theoretical answer if python allowed named assignment with su...

posted 3y ago by dino‭  ·  edited 2y ago by dino‭

Python 3, 145 bytes lambda s:[dict({chr(i+c):chr((i+13)%26+c)for i in range(26)for c in(65,97)},**{chr(i+48):chr((i+5)%10+48)for i in range(10)}).get(c,c)for c in s] Try it online! Generates...

posted 2y ago by dino‭

Python 3, 108 bytes lambda p,s:s<2and"Hole in one"or"Par:Bogey:Double bogey:Triple bogey:Albatross:Eagle:Birdie".split(':')[s-p] Try it online! Very similar to my other solution, but hand...

posted 3y ago by dino‭

Python 3.8, 112 bytes def f(x):y=[i for i in range(2,x)if not[j for j in range(2,i)if i%j<1]];return[(q,x-q)for q in y if x-q in y][0] Try it online!

posted 3y ago by dino‭

Python 3.8, 73 bytes lambda x:[len(x.split()),len(x.replace('\n','')),len(''.join(x.split()))] Try it online!

posted 3y ago by dino‭