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Activity for WheatWizard‭

Type On... Excerpt Status Date
Comment Post #290027 Fixed. Not sure what the point of sandboxing is on a site which only has 3-4 active users.
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7 months ago
Comment Post #289852 It's the first. I clarified it. Thanks.
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8 months ago
Comment Post #289679 1. With a normal form of output (e.g. 1 and 0) the set of problems that can be solved is the set of computable decision problems. With halting/non-halting output, the set of problems that can be solved is the set of limit computable decision problems. This includes famously non-computable problems ...
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8 months ago
Comment Post #289679 I'm in opposition to this for two reasons. 1. it is not a trivial change in IO, it is a very fundamental change in what can and can't be done. 2. It is not modular, programs written this way can only be combined as part of larger programs in limited ways.
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8 months ago
Comment Post #288535 You don't get to assume a maximum on these values.
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10 months ago
Comment Post #288943 The result can be exactly $-1, 0, 1$ if no other residue is one of those three residues (and each of those three occurs at least once). For example look at the example 6. 6 is 0 mod 2, 0 mod 3, 1 mod 5, -1 mod 7. The value 0 occurs twice, this is how you only have 3 values for high $n$.
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10 months ago
Comment Post #288943 No, the set needs to be exactly equal to, not just a subset of.
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11 months ago
Comment Post #288885 Ah thanks. I blame me missing that on the fact I was expecting to see a numeral.
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11 months ago
Comment Post #288885 You should probably mention that dice have 6 faces, currently it has to be intuited from test cases.
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11 months ago
Comment Post #283305 Haskell + [hgl](https://gitlab.com/wheatwizard/haskell-golfing-library), 2 bytes: `lq`
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11 months ago
Comment Post #288683 That big O notation simplifies to $O(n^2)$.
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11 months ago
Comment Post #288548 Ok, I should have seen that. I'm going to suggest adding a rounded up dummy score for the time being, and then to fix the leaderboard. I'll edit my answer in a bit.
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11 months ago
Comment Post #288548 Actually the leaderboard currently floors the fractional score so there's no use in making a dummy score. I've changed my suggestion to "update the leaderboard to support how people are scoring".
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11 months ago
Comment Post #288548 In the last section I'm suggesting that if the leaderboard is not changed, we include a dummy count so the leaderboard scores it predictably. I'll try to reword it.
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11 months ago
Comment Post #288548 Maybe I am no expressing myself most clearly. I am saying that the in effect disalllowing and allowing fractional bytes are not tangibly different. I assume the leaderboard doesn't change because it illustrates this point most expressly.
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11 months ago
Comment Post #288526 Thanks I fixed it. And it seems the new alignments are golfier since the fixed program comes out 2 bytes shorter.
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11 months ago
Comment Post #288398 The current definition of polyomino doesn't disallow holes. I'll try to work that explicitly into the text.
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11 months ago
Comment Post #288398 Ah I think you are misunderstanding, the you are dividing it into k-polyominos. There are no additional requirements on these polyominos. So ```text X XX XXXXX ``` can be subdivided into a T-tetramino and a O-tetramino. It doesn't matter that these are not the same 4-polyomino. You just ...
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11 months ago
Comment Post #288398 I'm not sure what you mean. There's no canonical way to select an enantiomorph, so yes it is possible for to mirror images to be inputs, if that's what you are asking. No part of this question involves determining if two polyominos are equal so it shouldn't matter whether you consider chiral pairs t...
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11 months ago
Comment Post #288398 Input a polyomino is intended to be flexible. I'd be certainly be willing to let you take a list of coordinates, and I believe if taking a list it is acceptable to also take its length. So that would be one way to take the input with the number of squares.
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11 months ago