Print the Great Numeric Pyramid
Print or return this exact text:
0
0 0
0 1 0
0 1 1 0
0 1 2 1 0
0 1 2 2 1 0
0 1 2 3 2 1 0
0 1 2 3 3 2 1 0
0 1 2 3 4 3 2 1 0
0 1 2 3 4 4 3 2 1 0
0 1 2 3 4 5 4 3 2 1 0
0 1 2 3 4 5 5 4 3 2 1 0
0 1 2 3 4 5 6 5 4 3 2 1 0
0 1 2 3 4 5 6 6 5 4 3 2 1 0
0 1 2 3 4 5 6 7 6 5 4 3 2 1 0
0 1 2 3 4 5 6 7 7 6 5 4 3 2 1 0
0 1 2 3 4 5 6 7 8 7 6 5 4 3 2 1 0
0 1 2 3 4 5 6 7 8 8 7 6 5 4 3 2 1 0
0 1 2 3 4 5 6 7 8 9 8 7 6 5 4 3 2 1 0
0 1 2 3 4 5 6 7 8 8 8 8 7 6 5 4 3 2 1 0
0 1 2 3 4 5 6 7 7 7 7 7 7 7 6 5 4 3 2 1 0
0 1 2 3 4 5 6 6 6 6 6 6 6 6 6 6 5 4 3 2 1 0
0 1 2 3 4 5 5 5 5 5 5 5 5 5 5 5 5 5 4 3 2 1 0
0 1 2 3 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 3 2 1 0
0 1 2 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 2 1 0
0 1 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 1 0
0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
The number represents the distance of the cell from the closest edge.
Trailing whitespace on each line is acceptable. A newline on the last line is optional.
[Python 2], 76 bytes …
5mo ago
Japt `-R`, 27 22 bytes …
5mo ago
[JavaScript (Node.js)], 137 13 …
5mo ago
Canvas, 19 bytes ‾－｛｛╷¹²－ …
5mo ago
4 answers
Python 2, 76 bytes
i=27
while~i:print' '*i+' '.join(`min(i,j,27-i-j)`for j in range(28-i));i-=1
Computes the digit in row i from the bottom, position j as min(i,j,27-i-j).
For comparison, a bad effect to compute the row numbers arithmetically, made harder by the presence of leading zeroes:
109 bytes
for i in range(28):print" "*(27-i)+" ".join(str(10**min(27-i,i/2)/9*(10**max(2*i-27,-~i/2)/9)*10).zfill(i+1))
0 comments
JavaScript (Node.js), 137 136 117 bytes
with(Math)f=n=>(m=(a,b)=>a?m(--a,b)+b(a):[])(28,y=>m(55,x=>x>26-y&x<y+28&(x^y)?min(abs(abs(27-x)-y)/2,27-y):' ')+`
`)
1 comment
Multiple well-golfed JavaScript answers on all the questions. I wonder who this is..
Japt -R, 27 22 bytes
27òÈn28 ÇmX27-X-ZøÃÔû
Lots of credit goes to xnor for finding the min(i,j,27-i-j) trick.
-5 bytes thanks to @Shaggy
4 comments
22 bytes but I'm sure it can be improved further. I wonder would just building the left-hand side and then palindromising work out shorter?
@shaggy Is it possible to palindromise the 78987 line? Wouldn't 9 get repeated, invalidating the answer?
@Corsaka, In Japt you can palindromise with or, by default, without repeating the middle character/element.
Ah, command for center padding, nice, thanks @Shaggy you learn something new every day
Canvas, 19 bytes
‾－｛｛╷¹²－ｍ‾－¹－ｍ］ ＊］／
‾-{{╷¹²-m‾-¹-m] *]/ Program, ascii-fied for monospacing
‾- push 28
{ ] for 1…28 (pushing counter & saving in ¹):
{ ] for 1…counter (pushing counter & saving in ²):
╷ decrement the counter
¹²- push ¹-²
m minimum of top 2; min(²-1, ¹-²)
‾-¹- push 28-¹
m minimum of top 2; min(²-1, ¹-², 28-¹)
* separate items with spaces
/ pad lines with spaces to form a space diagonal on the left
0 comments
0 comments