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Challenges Determine whether an integer is square-free

Python3, 39 bytes lambda n:all(n%i**2for i in range(2,n)) Try it online! Makes a list comprehension from the numbers 2 through n of the remainder of the square, and then checks whether the lis...

posted 3y ago by dino‭  ·  edited 3y ago by dino‭

Answer
#12: Post edited by user avatar dino‭ · 2022-01-06T14:17:03Z (almost 3 years ago)
  • # [Python3](https://www.python.org/), 44 bytes
  • ```python
  • lambda n:all(n%i**2for i in range(2,n))
  • ```
  • [Try it online!](https://tio.run/##PYxBCsIwFET3PcVQkCSlC02DSqFXcC8qEjGxgfS3NHEhpWePLYgDw7zNvOET256qZNFck9fd46lBtfae08YVhbT9CAdHGDW9DJclCZGiCfFO7y6gwWW3LSFVCSWXqpX3lTr89njLVgOthv@rzrBkGB1FbvOJ5hoTO5vA4CwsJwHjgwE79WzORfoC "Python 3 – Try It Online")
  • Makes a list comprehension from the numbers `2` through `n` of the remainder of the square, and then checks whether the list contains `0`
  • -8 bytes thanks to [celtschk‭](https://codegolf.codidact.com/users/8056)
  • -5 bytes thanks to [Moshi](https://codegolf.codidact.com/users/53196)
  • # [Python3](https://www.python.org/), 39 bytes
  • ```python
  • lambda n:all(n%i**2for i in range(2,n))
  • ```
  • [Try it online!](https://tio.run/##PYxBCsIwFET3PcVQkCSlC02DSqFXcC8qEjGxgfS3NHEhpWePLYgDw7zNvOET256qZNFck9fd46lBtfae08YVhbT9CAdHGDW9DJclCZGiCfFO7y6gwWW3LSFVCSWXqpX3lTr89njLVgOthv@rzrBkGB1FbvOJ5hoTO5vA4CwsJwHjgwE79WzORfoC "Python 3 – Try It Online")
  • Makes a list comprehension from the numbers `2` through `n` of the remainder of the square, and then checks whether the list contains `0`
  • -8 bytes thanks to [celtschk‭](https://codegolf.codidact.com/users/8056)
  • -5 bytes thanks to [Moshi](https://codegolf.codidact.com/users/53196)
#11: Post edited by user avatar dino‭ · 2022-01-06T14:16:22Z (almost 3 years ago)
Implement suggested changes from Moshi
  • # [Python3](https://www.python.org/), 44 bytes
  • ```python
  • lambda n:not 0in[n%i**2 for i in range(2,n)]
  • ```
  • [Try it online!](https://tio.run/##PYzRCoIwGIXvfYqDEFPxwuaoEHyF7sMkFm010H@yrYsQn30pRAcO57s53/QJL0t11GivcZDj/SFBDdmAylBHO1MUHNo6GBiCk/RUGS8p72NQPtzoPXq06PZVCS5KCL5WbHyoxfG3pz7ZDLQZ/q8mwZrJGQqZTmdaGszsojyD0dAZ5VCDV2Bny5Y0j18 "Python 3 – Try It Online")
  • Makes a list comprehension from the numbers `2` through `n` of the remainder of the square, and then checks whether the list contains `0`
  • -8 bytes thanks to [celtschk‭](https://codegolf.codidact.com/users/8056)
  • # [Python3](https://www.python.org/), 44 bytes
  • ```python
  • lambda n:all(n%i**2for i in range(2,n))
  • ```
  • [Try it online!](https://tio.run/##PYxBCsIwFET3PcVQkCSlC02DSqFXcC8qEjGxgfS3NHEhpWePLYgDw7zNvOET256qZNFck9fd46lBtfae08YVhbT9CAdHGDW9DJclCZGiCfFO7y6gwWW3LSFVCSWXqpX3lTr89njLVgOthv@rzrBkGB1FbvOJ5hoTO5vA4CwsJwHjgwE79WzORfoC "Python 3 – Try It Online")
  • Makes a list comprehension from the numbers `2` through `n` of the remainder of the square, and then checks whether the list contains `0`
  • -8 bytes thanks to [celtschk‭](https://codegolf.codidact.com/users/8056)
  • -5 bytes thanks to [Moshi](https://codegolf.codidact.com/users/53196)
#10: Post edited by user avatar dino‭ · 2022-01-05T22:06:45Z (almost 3 years ago)
  • # [Python3](https://www.python.org/), 45 bytes
  • ```python
  • lambda n:not 0in[n%(i*i) for i in range(2,n)]
  • ```
  • [Try it online!](https://tio.run/##PYzBCoJAGITvPsUQxO6GB9OlQvAVuodJGO3WD/qvuNshxGffFKKBYb7LfMMnvBwX0aK6xq7t748WXLILyIhr3krakYJ1IwjEGFt@GpmnrJoYjA83fvceFep9liLXKXS@VK98KPTxt6cmWQ28Gv6vMsGSYSQO0m4mnktM4mK8AFlYyQqm8wbi7MS8UfEL "Python 3 – Try It Online")
  • Makes a list comprehension from the numbers `2` through `n` of the remainder of the square, and then checks whether the list contains `0`
  • -8 bytes thanks to [celtschk‭](https://codegolf.codidact.com/users/8056)
  • # [Python3](https://www.python.org/), 44 bytes
  • ```python
  • lambda n:not 0in[n%i**2 for i in range(2,n)]
  • ```
  • [Try it online!](https://tio.run/##PYzRCoIwGIXvfYqDEFPxwuaoEHyF7sMkFm010H@yrYsQn30pRAcO57s53/QJL0t11GivcZDj/SFBDdmAylBHO1MUHNo6GBiCk/RUGS8p72NQPtzoPXq06PZVCS5KCL5WbHyoxfG3pz7ZDLQZ/q8mwZrJGQqZTmdaGszsojyD0dAZ5VCDV2Bny5Y0j18 "Python 3 – Try It Online")
  • Makes a list comprehension from the numbers `2` through `n` of the remainder of the square, and then checks whether the list contains `0`
  • -8 bytes thanks to [celtschk‭](https://codegolf.codidact.com/users/8056)
#9: Post edited by user avatar dino‭ · 2022-01-05T21:48:57Z (almost 3 years ago)
Implement suggested changes from celtschk
  • # [Python3](https://www.python.org/), 53 bytes
  • ```python
  • lambda n:not 1in[n%i==0==(n/i)%i for i in range(2,n)]
  • ```
  • [Try it online!](https://tio.run/##PYxNCsIwGET3PcUglCRQsD9BpZAruJdapGKigfZLaeJCSs8eWxAHhnmbeeMnvBxV0UBdY98N90cHqskFFJYaSq1SuVKc9lakFsZNsLCEqaOn5mVGoo1B@3Cj9@Ch0BR5hlJmkOVaufGhksffntpkM9Bm@L/qBGvGyVLgZjfTUmNmF@0ZrIHhJKB7r8HOji07Eb8 "Python 3 – Try It Online")
  • Makes a list comprehension of numbers from `2` to `n` of whether they factor into `n` twice, and then checks whether the list contains `True`
  • # [Python3](https://www.python.org/), 45 bytes
  • ```python
  • lambda n:not 0in[n%(i*i) for i in range(2,n)]
  • ```
  • [Try it online!](https://tio.run/##PYzBCoJAGITvPsUQxO6GB9OlQvAVuodJGO3WD/qvuNshxGffFKKBYb7LfMMnvBwX0aK6xq7t748WXLILyIhr3krakYJ1IwjEGFt@GpmnrJoYjA83fvceFep9liLXKXS@VK98KPTxt6cmWQ28Gv6vMsGSYSQO0m4mnktM4mK8AFlYyQqm8wbi7MS8UfEL "Python 3 – Try It Online")
  • Makes a list comprehension from the numbers `2` through `n` of the remainder of the square, and then checks whether the list contains `0`
  • -8 bytes thanks to [celtschk‭](https://codegolf.codidact.com/users/8056)
#8: Post edited by user avatar dino‭ · 2022-01-05T17:22:09Z (almost 3 years ago)
  • # [Python3](https://www.python.org/), 53 bytes
  • ```python
  • lambda n:not 1in[n%i==0==(n/i)%i for i in range(2,n)]
  • ```
  • [Try it online!](https://tio.run/##PYtBCoMwFAX3nuIhiAkIVetKyBW6L1aKpUn9YH5ski6KeHarmw7Mbmb@xtHxeTPeWdghjiA7Ox8R3j4mBuq2TYN9PAdwyy6iIu44I6VKpQSfSGYE4zwIxPADv7SoC5b9FnWId/7YAIWuKgvUTYGm3m365Dj4OP5Vm2Bn9sRRmHThtcWSX3XIQQZGsISegkZ@cfmayu0H "Python 3 – Try It Online")
  • Makes a list comprehension of numbers from `2` to `n` of whether they factor into `n` twice, and then checks whether the list contains `True`
  • # [Python3](https://www.python.org/), 53 bytes
  • ```python
  • lambda n:not 1in[n%i==0==(n/i)%i for i in range(2,n)]
  • ```
  • [Try it online!](https://tio.run/##PYxNCsIwGET3PcUglCRQsD9BpZAruJdapGKigfZLaeJCSs8eWxAHhnmbeeMnvBxV0UBdY98N90cHqskFFJYaSq1SuVKc9lakFsZNsLCEqaOn5mVGoo1B@3Cj9@Ch0BR5hlJmkOVaufGhksffntpkM9Bm@L/qBGvGyVLgZjfTUmNmF@0ZrIHhJKB7r8HOji07Eb8 "Python 3 – Try It Online")
  • Makes a list comprehension of numbers from `2` to `n` of whether they factor into `n` twice, and then checks whether the list contains `True`
#7: Post edited by user avatar dino‭ · 2022-01-05T17:20:18Z (almost 3 years ago)
  • # [Python3](https://www.python.org/), 53 bytes
  • ```python
  • lambda n:not 1in[n%i==0==(n/i)%i for i in range(2,n)]
  • ```
  • [Try it online!](https://tio.run/##PYtBCoMwFAX3nuIhiAkIVetKyBW6L1aKpUn9YH5ski6KeHarmw7Mbmb@xtHxeTPeWdghjiA7Ox8R3j4mBuq2TYN9PAdwyy6iIu44I6VKpQSfSGYE4zwIxPADv7SoC5b9FnWId/7YAIWuKgvUTYGm3m365Dj4OP5Vm2Bn9sRRmHThtcWSX3XIQQZGsISegkZ@cfmayu0H "Python 3 – Try It Online")
  • Makes a list comprehension of numbers from `2` to `n` of whether they factor into `n` twice, and then checks whether the list contains `True`
  • ## Longer (more readable?) version (102 bytes)
  • ```python
  • def f(n):
  • for i in range(2,int(sqrt(n)+1)):
  • n=(n/i if n%i==0 else n)
  • if n%i==0:return 0
  • return 1
  • ```
  • [Try it online!](https://tio.run/##PY5BCsIwFET3PcUgSBIs2NauCrmCexGRgokN2J@apAspPXtMULr4MPx58Gb6hMHSKWpnR4x9GGDGyboA/3YhPpSG5iS6Ato6GBiC6@mpeFMaCjxDqT7UIiMgyemYIA3aGykrqJdXIJGq7dc5FWZHqAr8Ux2D8uFO8@ghca2rEk1bom3StbciiymLNyqrgMnlBXq30NphYRflWbbkuT8vO1u27kT8Ag "Python 3 – Try It Online")
  • Loops through 2 - the square root of the input number (rounded up) as `i`, and return `False` if `i` factors into the input number twice. If no instance of `i` factors twice into the input number then return `True`.
  • # [Python3](https://www.python.org/), 53 bytes
  • ```python
  • lambda n:not 1in[n%i==0==(n/i)%i for i in range(2,n)]
  • ```
  • [Try it online!](https://tio.run/##PYtBCoMwFAX3nuIhiAkIVetKyBW6L1aKpUn9YH5ski6KeHarmw7Mbmb@xtHxeTPeWdghjiA7Ox8R3j4mBuq2TYN9PAdwyy6iIu44I6VKpQSfSGYE4zwIxPADv7SoC5b9FnWId/7YAIWuKgvUTYGm3m365Dj4OP5Vm2Bn9sRRmHThtcWSX3XIQQZGsISegkZ@cfmayu0H "Python 3 – Try It Online")
  • Makes a list comprehension of numbers from `2` to `n` of whether they factor into `n` twice, and then checks whether the list contains `True`
#6: Post edited by user avatar dino‭ · 2022-01-05T17:19:59Z (almost 3 years ago)
  • # [Python3](https://www.python.org/), 53 bytes
  • ```python
  • lambda n:not 1in[n%i==0==(n/i)%i for i in range(2,n)]
  • ```
  • [Try it online!](https://tio.run/##PYtBCoMwFAX3nuIhiAkIVetKyBW6L1aKpUn9YH5ski6KeHarmw7Mbmb@xtHxeTPeWdghjiA7Ox8R3j4mBuq2TYN9PAdwyy6iIu44I6VKpQSfSGYE4zwIxPADv7SoC5b9FnWId/7YAIWuKgvUTYGm3m365Dj4OP5Vm2Bn9sRRmHThtcWSX3XIQQZGsISegkZ@cfmayu0H "Python 3 – Try It Online")
  • Makes a list comprehension of numbers from `2` to `n` of whether they factor into `n` twice, and then checks whether the list contains `True`
  • ## More friendly version (102 bytes)
  • ```python
  • def f(n):
  • for i in range(2,int(sqrt(n)+1)):
  • n=(n/i if n%i==0 else n)
  • if n%i==0:return 0
  • return 1
  • ```
  • [Try it online!](https://tio.run/##PY5BCsIwFET3PcUgSBIs2NauCrmCexGRgokN2J@apAspPXtMULr4MPx58Gb6hMHSKWpnR4x9GGDGyboA/3YhPpSG5iS6Ato6GBiC6@mpeFMaCjxDqT7UIiMgyemYIA3aGykrqJdXIJGq7dc5FWZHqAr8Ux2D8uFO8@ghca2rEk1bom3StbciiymLNyqrgMnlBXq30NphYRflWbbkuT8vO1u27kT8Ag "Python 3 – Try It Online")
  • Loops through 2 - the square root of the input number (rounded up) as `i`, and return `False` if `i` factors into the input number twice. If no instance of `i` factors twice into the input number then return `True`.
  • # [Python3](https://www.python.org/), 53 bytes
  • ```python
  • lambda n:not 1in[n%i==0==(n/i)%i for i in range(2,n)]
  • ```
  • [Try it online!](https://tio.run/##PYtBCoMwFAX3nuIhiAkIVetKyBW6L1aKpUn9YH5ski6KeHarmw7Mbmb@xtHxeTPeWdghjiA7Ox8R3j4mBuq2TYN9PAdwyy6iIu44I6VKpQSfSGYE4zwIxPADv7SoC5b9FnWId/7YAIWuKgvUTYGm3m365Dj4OP5Vm2Bn9sRRmHThtcWSX3XIQQZGsISegkZ@cfmayu0H "Python 3 – Try It Online")
  • Makes a list comprehension of numbers from `2` to `n` of whether they factor into `n` twice, and then checks whether the list contains `True`
  • ## Longer (more readable?) version (102 bytes)
  • ```python
  • def f(n):
  • for i in range(2,int(sqrt(n)+1)):
  • n=(n/i if n%i==0 else n)
  • if n%i==0:return 0
  • return 1
  • ```
  • [Try it online!](https://tio.run/##PY5BCsIwFET3PcUgSBIs2NauCrmCexGRgokN2J@apAspPXtMULr4MPx58Gb6hMHSKWpnR4x9GGDGyboA/3YhPpSG5iS6Ato6GBiC6@mpeFMaCjxDqT7UIiMgyemYIA3aGykrqJdXIJGq7dc5FWZHqAr8Ux2D8uFO8@ghca2rEk1bom3StbciiymLNyqrgMnlBXq30NphYRflWbbkuT8vO1u27kT8Ag "Python 3 – Try It Online")
  • Loops through 2 - the square root of the input number (rounded up) as `i`, and return `False` if `i` factors into the input number twice. If no instance of `i` factors twice into the input number then return `True`.
#5: Post edited by user avatar dino‭ · 2022-01-05T17:14:22Z (almost 3 years ago)
  • # [Python3](https://www.python.org/), 53 bytes
  • ```python
  • lambda n:not 1in[n%i==0==(n/i)%i for i in range(2,n)]
  • ```
  • [Try it online!](https://tio.run/##PYvBCsIwGIPve4ogSFsY6OZOg72Cd5lDKmtdYf0723qQsWev68VASAL5lm@cHF2S9s7CyjjB2MX5iPD2sdDo7mmW9jlKUEsuojLU56SjgaQRuXM6GbFv7TwMDMFLeilelySGFFWID/rYgA59dS5RNyWaenczFJmgTPxfbYFdizcUuT6stLVY2U0FBqOhOQmoOSiwq2PbQaQf "Python 3 – Try It Online")
  • Makes a list comprehension of numbers from `2` to `n` of whether they factor into `n` twice, and then checks whether the list contains `True`
  • ## More friendly version (102 bytes)
  • ```python
  • def f(n):
  • for i in range(2,int(sqrt(n)+1)):
  • n=(n/i if n%i==0 else n)
  • if n%i==0:return 0
  • return 1
  • ```
  • [Try it online!](https://tio.run/##PY5BCsIwFET3PcUgSBIs2NauCrmCexGRgokN2J@apAspPXtMULr4MPx58Gb6hMHSKWpnR4x9GGDGyboA/3YhPpSG5iS6Ato6GBiC6@mpeFMaCjxDqT7UIiMgyemYIA3aGykrqJdXIJGq7dc5FWZHqAr8Ux2D8uFO8@ghca2rEk1bom3StbciiymLNyqrgMnlBXq30NphYRflWbbkuT8vO1u27kT8Ag "Python 3 – Try It Online")
  • Loops through 2 - the square root of the input number (rounded up) as `i`, and return `False` if `i` factors into the input number twice. If no instance of `i` factors twice into the input number then return `True`.
  • # [Python3](https://www.python.org/), 53 bytes
  • ```python
  • lambda n:not 1in[n%i==0==(n/i)%i for i in range(2,n)]
  • ```
  • [Try it online!](https://tio.run/##PYtBCoMwFAX3nuIhiAkIVetKyBW6L1aKpUn9YH5ski6KeHarmw7Mbmb@xtHxeTPeWdghjiA7Ox8R3j4mBuq2TYN9PAdwyy6iIu44I6VKpQSfSGYE4zwIxPADv7SoC5b9FnWId/7YAIWuKgvUTYGm3m365Dj4OP5Vm2Bn9sRRmHThtcWSX3XIQQZGsISegkZ@cfmayu0H "Python 3 – Try It Online")
  • Makes a list comprehension of numbers from `2` to `n` of whether they factor into `n` twice, and then checks whether the list contains `True`
  • ## More friendly version (102 bytes)
  • ```python
  • def f(n):
  • for i in range(2,int(sqrt(n)+1)):
  • n=(n/i if n%i==0 else n)
  • if n%i==0:return 0
  • return 1
  • ```
  • [Try it online!](https://tio.run/##PY5BCsIwFET3PcUgSBIs2NauCrmCexGRgokN2J@apAspPXtMULr4MPx58Gb6hMHSKWpnR4x9GGDGyboA/3YhPpSG5iS6Ato6GBiC6@mpeFMaCjxDqT7UIiMgyemYIA3aGykrqJdXIJGq7dc5FWZHqAr8Ux2D8uFO8@ghca2rEk1bom3StbciiymLNyqrgMnlBXq30NphYRflWbbkuT8vO1u27kT8Ag "Python 3 – Try It Online")
  • Loops through 2 - the square root of the input number (rounded up) as `i`, and return `False` if `i` factors into the input number twice. If no instance of `i` factors twice into the input number then return `True`.
#4: Post edited by user avatar dino‭ · 2022-01-05T17:13:56Z (almost 3 years ago)
  • # [Python3](https://www.python.org/), 59 bytes
  • ```python
  • lambda n:not 1in[n%i==0 and (n/i)%i==0 for i in range(2,n)]
  • ```
  • [Try it online!](https://tio.run/##PYvBCsIwGIPve4ogSFsY6OZOg72Cd5lDKmtdYf0723qQsWev68VASAL5lm@cHF2S9s7CyjjB2MX5iPD2sdDo7mmW9jlKUEsuojLU56SjgaQRuXM6GbFv7TwMDMFLeilelySGFFWID/rYgA59dS5RNyWaenczFJmgTPxfbYFdizcUuT6stLVY2U0FBqOhOQmoOSiwq2PbQaQf "Python 3 – Try It Online")
  • Makes a list comprehension of numbers from `2` to `n` of whether they factor into `n` twice, and then checks whether the list contains `True`
  • ## More friendly version (102 bytes)
  • ```python
  • def f(n):
  • for i in range(2,int(sqrt(n)+1)):
  • n=(n/i if n%i==0 else n)
  • if n%i==0:return 0
  • return 1
  • ```
  • [Try it online!](https://tio.run/##PY5BCsIwFET3PcUgSBIs2NauCrmCexGRgokN2J@apAspPXtMULr4MPx58Gb6hMHSKWpnR4x9GGDGyboA/3YhPpSG5iS6Ato6GBiC6@mpeFMaCjxDqT7UIiMgyemYIA3aGykrqJdXIJGq7dc5FWZHqAr8Ux2D8uFO8@ghca2rEk1bom3StbciiymLNyqrgMnlBXq30NphYRflWbbkuT8vO1u27kT8Ag "Python 3 – Try It Online")
  • Loops through 2 - the square root of the input number (rounded up) as `i`, and return `False` if `i` factors into the input number twice. If no instance of `i` factors twice into the input number then return `True`.
  • # [Python3](https://www.python.org/), 53 bytes
  • ```python
  • lambda n:not 1in[n%i==0==(n/i)%i for i in range(2,n)]
  • ```
  • [Try it online!](https://tio.run/##PYvBCsIwGIPve4ogSFsY6OZOg72Cd5lDKmtdYf0723qQsWev68VASAL5lm@cHF2S9s7CyjjB2MX5iPD2sdDo7mmW9jlKUEsuojLU56SjgaQRuXM6GbFv7TwMDMFLeilelySGFFWID/rYgA59dS5RNyWaenczFJmgTPxfbYFdizcUuT6stLVY2U0FBqOhOQmoOSiwq2PbQaQf "Python 3 – Try It Online")
  • Makes a list comprehension of numbers from `2` to `n` of whether they factor into `n` twice, and then checks whether the list contains `True`
  • ## More friendly version (102 bytes)
  • ```python
  • def f(n):
  • for i in range(2,int(sqrt(n)+1)):
  • n=(n/i if n%i==0 else n)
  • if n%i==0:return 0
  • return 1
  • ```
  • [Try it online!](https://tio.run/##PY5BCsIwFET3PcUgSBIs2NauCrmCexGRgokN2J@apAspPXtMULr4MPx58Gb6hMHSKWpnR4x9GGDGyboA/3YhPpSG5iS6Ato6GBiC6@mpeFMaCjxDqT7UIiMgyemYIA3aGykrqJdXIJGq7dc5FWZHqAr8Ux2D8uFO8@ghca2rEk1bom3StbciiymLNyqrgMnlBXq30NphYRflWbbkuT8vO1u27kT8Ag "Python 3 – Try It Online")
  • Loops through 2 - the square root of the input number (rounded up) as `i`, and return `False` if `i` factors into the input number twice. If no instance of `i` factors twice into the input number then return `True`.
#3: Post edited by user avatar dino‭ · 2022-01-05T17:12:38Z (almost 3 years ago)
  • # [Python3](https://www.python.org/), 61 bytes
  • ```python
  • lambda n:not 1in[not n%i and not (n/i)%i for i in range(2,n)]
  • ```
  • [Try it online!](https://tio.run/##PYvBCsIwGIPve4ogSFsY6OZOg72Cd5lDKmtdYf0723qQsWev68VASAL5lm@cHF2S9s7CyjjB2MX5iPD2sdDo7mmW9jlKUEsuojLU56SjgaQRuXM6GbFv7TwMDMFLeilelySGFFWID/rYgA59dS5RNyWaenczFJmgTPxfbYFdizcUuT6stLVY2U0FBqOhOQmoOSiwq2PbQaQf "Python 3 – Try It Online")
  • Makes a list comprehension of numbers from `2` to `n` of whether they factor into `n` twice, and then checks whether the list contains `True`
  • ## More friendly version (102 bytes)
  • ```python
  • def f(n):
  • for i in range(2,int(sqrt(n)+1)):
  • n=(n/i if n%i==0 else n)
  • if n%i==0:return 0
  • return 1
  • ```
  • [Try it online!](https://tio.run/##PY5BCsIwFET3PcUgSBIs2NauCrmCexGRgokN2J@apAspPXtMULr4MPx58Gb6hMHSKWpnR4x9GGDGyboA/3YhPpSG5iS6Ato6GBiC6@mpeFMaCjxDqT7UIiMgyemYIA3aGykrqJdXIJGq7dc5FWZHqAr8Ux2D8uFO8@ghca2rEk1bom3StbciiymLNyqrgMnlBXq30NphYRflWbbkuT8vO1u27kT8Ag "Python 3 – Try It Online")
  • Loops through 2 - the square root of the input number (rounded up) as `i`, and return `False` if `i` factors into the input number twice. If no instance of `i` factors twice into the input number then return `True`.
  • # [Python3](https://www.python.org/), 59 bytes
  • ```python
  • lambda n:not 1in[n%i==0 and (n/i)%i==0 for i in range(2,n)]
  • ```
  • [Try it online!](https://tio.run/##PYvBCsIwGIPve4ogSFsY6OZOg72Cd5lDKmtdYf0723qQsWev68VASAL5lm@cHF2S9s7CyjjB2MX5iPD2sdDo7mmW9jlKUEsuojLU56SjgaQRuXM6GbFv7TwMDMFLeilelySGFFWID/rYgA59dS5RNyWaenczFJmgTPxfbYFdizcUuT6stLVY2U0FBqOhOQmoOSiwq2PbQaQf "Python 3 – Try It Online")
  • Makes a list comprehension of numbers from `2` to `n` of whether they factor into `n` twice, and then checks whether the list contains `True`
  • ## More friendly version (102 bytes)
  • ```python
  • def f(n):
  • for i in range(2,int(sqrt(n)+1)):
  • n=(n/i if n%i==0 else n)
  • if n%i==0:return 0
  • return 1
  • ```
  • [Try it online!](https://tio.run/##PY5BCsIwFET3PcUgSBIs2NauCrmCexGRgokN2J@apAspPXtMULr4MPx58Gb6hMHSKWpnR4x9GGDGyboA/3YhPpSG5iS6Ato6GBiC6@mpeFMaCjxDqT7UIiMgyemYIA3aGykrqJdXIJGq7dc5FWZHqAr8Ux2D8uFO8@ghca2rEk1bom3StbciiymLNyqrgMnlBXq30NphYRflWbbkuT8vO1u27kT8Ag "Python 3 – Try It Online")
  • Loops through 2 - the square root of the input number (rounded up) as `i`, and return `False` if `i` factors into the input number twice. If no instance of `i` factors twice into the input number then return `True`.
#2: Post edited by user avatar dino‭ · 2022-01-05T17:11:13Z (almost 3 years ago)
  • # [Python3](https://www.python.org/), 102 bytes
  • ```python
  • def f(n):
  • for i in range(2,int(sqrt(n)+1)):
  • n=(n/i if n%i==0 else n)
  • if n%i==0:return 0
  • return 1
  • ```
  • [Try it online!](https://tio.run/##PY5BCsIwFET3PcUgSBIs2NauCrmCexGRgokN2J@apAspPXtMULr4MPx58Gb6hMHSKWpnR4x9GGDGyboA/3YhPpSG5iS6Ato6GBiC6@mpeFMaCjxDqT7UIiMgyemYIA3aGykrqJdXIJGq7dc5FWZHqAr8Ux2D8uFO8@ghca2rEk1bom3StbciiymLNyqrgMnlBXq30NphYRflWbbkuT8vO1u27kT8Ag "Python 3 – Try It Online")
  • Loops through 2 - the square root of the input number (rounded up) as `i`, and return `False` if `i` factors into the input number twice. If no instance of `i` factors twice into the input number then return `True`.
  • # [Python3](https://www.python.org/), 61 bytes
  • ```python
  • lambda n:not 1in[not n%i and not (n/i)%i for i in range(2,n)]
  • ```
  • [Try it online!](https://tio.run/##PYvBCsIwGIPve4ogSFsY6OZOg72Cd5lDKmtdYf0723qQsWev68VASAL5lm@cHF2S9s7CyjjB2MX5iPD2sdDo7mmW9jlKUEsuojLU56SjgaQRuXM6GbFv7TwMDMFLeilelySGFFWID/rYgA59dS5RNyWaenczFJmgTPxfbYFdizcUuT6stLVY2U0FBqOhOQmoOSiwq2PbQaQf "Python 3 – Try It Online")
  • Makes a list comprehension of numbers from `2` to `n` of whether they factor into `n` twice, and then checks whether the list contains `True`
  • ## More friendly version (102 bytes)
  • ```python
  • def f(n):
  • for i in range(2,int(sqrt(n)+1)):
  • n=(n/i if n%i==0 else n)
  • if n%i==0:return 0
  • return 1
  • ```
  • [Try it online!](https://tio.run/##PY5BCsIwFET3PcUgSBIs2NauCrmCexGRgokN2J@apAspPXtMULr4MPx58Gb6hMHSKWpnR4x9GGDGyboA/3YhPpSG5iS6Ato6GBiC6@mpeFMaCjxDqT7UIiMgyemYIA3aGykrqJdXIJGq7dc5FWZHqAr8Ux2D8uFO8@ghca2rEk1bom3StbciiymLNyqrgMnlBXq30NphYRflWbbkuT8vO1u27kT8Ag "Python 3 – Try It Online")
  • Loops through 2 - the square root of the input number (rounded up) as `i`, and return `False` if `i` factors into the input number twice. If no instance of `i` factors twice into the input number then return `True`.
#1: Initial revision by user avatar dino‭ · 2022-01-05T16:52:33Z (almost 3 years ago) 
# [Python3](https://www.python.org/), 102 bytes
```python
def f(n):
 for i in range(2,int(sqrt(n)+1)):
  n=(n/i if n%i==0 else n)
  if n%i==0:return 0
 return 1
```
[Try it online!](https://tio.run/##PY5BCsIwFET3PcUgSBIs2NauCrmCexGRgokN2J@apAspPXtMULr4MPx58Gb6hMHSKWpnR4x9GGDGyboA/3YhPpSG5iS6Ato6GBiC6@mpeFMaCjxDqT7UIiMgyemYIA3aGykrqJdXIJGq7dc5FWZHqAr8Ux2D8uFO8@ghca2rEk1bom3StbciiymLNyqrgMnlBXq30NphYRflWbbkuT8vO1u27kT8Ag "Python 3 – Try It Online")

Loops through 2 - the square root of the input number (rounded up) as `i`, and return `False` if `i` factors into the input number twice. If no instance of `i` factors twice into the input number then return `True`.