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Activity for WheatWizard‭

Type On... Excerpt Status Date
Edit Post #288622 Post edited:
11 months ago
Edit Post #288622 Post undeleted 11 months ago
Edit Post #288622 Post deleted 11 months ago
Edit Post #288622 Initial revision 11 months ago
Question Are these reduced forms of the same thing?
Task You are going to take three strings as input $A$, $B$ and $X$. And your goal is to determine if there exists a third string $S$ such that both $A$ and $B$ can be formed by iteratively removing contiguous instances of $X$ in $S$. For example if $X = 10101$ then both $10$ and $01$ can be forme...
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11 months ago
Edit Post #288563 Post edited:
11 months ago
Edit Post #288563 Initial revision 11 months ago
Question Build a replacement ball in regex.
In this challenge you will take a number $n$ and a string $X$ of length $\geq n$, and produce a regular expression which matches all strings that are withing $n$ character substitutions of $X$. Specifically you will take $X$ and $n$ and ouptut all the ways to replace exactly $n$ characters with th...
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11 months ago
Edit Post #288555 Post edited:
11 months ago
Edit Post #288555 Initial revision 11 months ago
Answer A: Efficient censorship
Haskell + hgl, 14 bytes ```haskell xBl<fn<iw ```` Attempt This Online! Explanation `ss` gets all substrings of the input `fn` filters out the substrings that don't ... `iw` checks if the forbidden word is a contiguous substring `xBl` gets the largest result Reflection There...
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11 months ago
Comment Post #288548 Actually the leaderboard currently floors the fractional score so there's no use in making a dummy score. I've changed my suggestion to "update the leaderboard to support how people are scoring".
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11 months ago
Edit Post #288548 Post edited:
11 months ago
Comment Post #288548 In the last section I'm suggesting that if the leaderboard is not changed, we include a dummy count so the leaderboard scores it predictably. I'll try to reword it.
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11 months ago
Comment Post #288548 Maybe I am no expressing myself most clearly. I am saying that the in effect disalllowing and allowing fractional bytes are not tangibly different. I assume the leaderboard doesn't change because it illustrates this point most expressly.
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11 months ago
Edit Post #288548 Post edited:
11 months ago
Edit Post #288548 Initial revision 11 months ago
Answer A: Codidact Fractional Byte Consensus
I'm going to reiterate and build off ideas I laid out on this post on PPCG. First let's point out that at current the leader board does not support fractional scores. In this answer I am going to assume this is unchanged. That may prove to be false, in fact I think it is likely a false assumption,...
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11 months ago
Edit Post #288535 Initial revision 11 months ago
Question Efficient censorship
You are a low-level censor working for the Ministry of Media Accuracy. Part of your job is to make sure that certain words don't appear in publications. Every morning you get a fresh stack of next week's newspapers and its your job to comb through them and fix any of the words that were mistakenly i...
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11 months ago
Comment Post #288526 Thanks I fixed it. And it seems the new alignments are golfier since the fixed program comes out 2 bytes shorter.
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11 months ago
Edit Post #288526 Post edited:
Fixed alignment
11 months ago
Edit Post #288526 Post edited:
Improved score.
11 months ago
Edit Post #288526 Post edited:
11 months ago
Edit Post #288526 Initial revision 11 months ago
Answer A: Connect the corners without 4 in a row
Haskell + hgl, 134 bytes ```haskell k=cy"X.XX" x#1=[4,0,9,9]!x 2#y=8 3#y=[8,9,4,4]!y x#3=[0,3]!x #=0 x?y|(n,j)<-fvD 4$x%4#(y%4)=tk y$dr j$tk x<dr n<cy[dr2 k,k,cy".X",k] ```` Attempt This Online! I first set up a pretty dense background pattern which doesn't break any rules: ``` X...
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11 months ago
Edit Post #288516 Post edited:
11 months ago
Edit Post #288516 Initial revision 11 months ago
Question Calculate the Z-array
Task Given a list of numbers $X$ produce a second list of numbers $Y$ such that $Yi$ is the length of the longest common prefix of $X$ and $X$ with the first $i$ elements removed. For example if the input is ``` [1,2,2,1,1,2,1,2,2,1,2,1] ``` The output should be ``` [12,0,0,1,2,0,4,...
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11 months ago
Edit Post #288398 Post edited:
More examples.
11 months ago
Edit Post #288503 Initial revision 11 months ago
Question Count polyomino bisections
An polyomino is a non-empty connected subset of the square tiling consisting of squares joined along their edges. We will not require that polyominos be simply connected, that is they can have holes. A bisection of a polyomino $X$ is a pair of polyominos such that they can be joined together witho...
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11 months ago
Edit Post #288398 Post edited:
Holes.
11 months ago
Comment Post #288398 The current definition of polyomino doesn't disallow holes. I'll try to work that explicitly into the text.
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11 months ago
Edit Post #288398 Post edited:
11 months ago
Comment Post #288398 Ah I think you are misunderstanding, the you are dividing it into k-polyominos. There are no additional requirements on these polyominos. So ```text X XX XXXXX ``` can be subdivided into a T-tetramino and a O-tetramino. It doesn't matter that these are not the same 4-polyomino. You just ...
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11 months ago
Comment Post #288398 I'm not sure what you mean. There's no canonical way to select an enantiomorph, so yes it is possible for to mirror images to be inputs, if that's what you are asking. No part of this question involves determining if two polyominos are equal so it shouldn't matter whether you consider chiral pairs t...
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11 months ago
Comment Post #288398 Input a polyomino is intended to be flexible. I'd be certainly be willing to let you take a list of coordinates, and I believe if taking a list it is acceptable to also take its length. So that would be one way to take the input with the number of squares.
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11 months ago
Edit Post #288398 Initial revision 11 months ago
Question Determine if a polyomino is "prime"
An $n$-polyomino is a connected subset of the square tiling consisting of $n$ squares. We will not require that polyominos be simply connected, that is they can have holes. We will say a $n$-polyomino is prime if it cannot be disected into disjoint $k$-polyominos for any 1<$k$<$n$. For example th...
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11 months ago