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Activity for orthoplex‭

Type On... Excerpt Status Date
Comment Post #285929 You can eliminate the plus sign via `a+b` → `a-(-b)`.
(more)
almost 2 years ago
Comment Post #286668 You can eliminate the init-loop by or-ing the lookup with 0. Using `pairs` also seems a bit overkill since you're not using `k` anywhere. `function(t)r={}for i=1,#t do r[t[i]]=1+(r[t[i]]or 0)end return r end`
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almost 2 years ago
Comment Post #286637 Actually, `set(x)` → `x` works just fine in this case. I also found a set-of-pairs solution that is equally as long: `lambda x:{*zip(x,map(x.count,x))}`
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almost 2 years ago
Edit Post #286541 Initial revision almost 2 years ago
Answer A: From the smallest seed
HQ9+, 2 bytes Two quines. QQ
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almost 2 years ago
Edit Post #286283 Post edited:
about 2 years ago
Edit Post #286356 Initial revision about 2 years ago
Answer A: Create a range grid
[Python 2], 46 bytes lambda m,n:[range(n,n+n)for in range(m)] Try it online!
(more)
about 2 years ago
Edit Post #286355 Initial revision about 2 years ago
Answer A: Create a range grid
[Python 3], 49 bytes lambda m,n:[[range(n,n+n)]for in range(m)] Try it online!
(more)
about 2 years ago
Comment Post #286311 At first, I thought you were cheesing the test cases, but you're right, -1 is the only negative number you can possibly get. Clever! The penultimate line should then be ```lua _=(_==256or _<0)and 0or _ ```
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about 2 years ago
Comment Post #286311 Tables to the rescue ^^ ```lua _=0 for c in s:gmatch'.'do _=({d=_-1,i=_+1;s=_*_})[c]or print(_)or _ _=({[256]=0,[-1]=0})[_]or _ end ```
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about 2 years ago
Comment Post #286301 How about we use our own function to shorten the for-loop even more? This should also relieve your discomfort with not calling `f`. ```lua local function f()goto l::l::return end for _ in f do end if true and false then elseif""then else end repeat until""or not nil while""do break end ```
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about 2 years ago
Comment Post #286301 Oh oops, you're right, I completely overlooked `in`. Still, the for-loop could be shortened to something sneaky like ```lua for x in print do end ```
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about 2 years ago
Comment Post #286301 You can shorten your for-loop and save a few spaces on the numerical constants. Also, I don't think the rules require you to call your function in the end. ```lua local function f()if true then for v=0,0 do while false do break end repeat until""and""or not nil end elseif""then else end goto l::l::...
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about 2 years ago
Comment Post #286300 You can shorten your loop by using goto. As a bonus, this makes your code look even more cryptic (: ```lua _=''::_::_=_..'*'print(_)goto _ ```
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about 2 years ago
Comment Post #286295 oh sweet, we have a 35 then ^^ ```haskell main=mapM putStrLn$iterate('*':)"*" ```
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about 2 years ago
Comment Post #286295 Neat solution, but that import is quite expensive. Maybe try something like ```haskell x="*":map('*':)x main=mapM putStrLn x ```
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about 2 years ago
Edit Post #286294 Initial revision about 2 years ago
Answer A: Looping counter
[Ruby], 18 bytes loop{$><<$/=?+$/} Try it online!
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about 2 years ago
Edit Post #286286 Initial revision about 2 years ago
Answer A: Looping counter
[brainfuck], 31 bytes ++++++++++[[>]>-[---]] Try it online!
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about 2 years ago
Edit Post #286285 Initial revision about 2 years ago
Answer A: Looping counter
[><>], 10 bytes 1:naoa1+! Try it online!
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about 2 years ago
Edit Post #286284 Initial revision about 2 years ago
Answer A: Looping counter
[dc], 13 bytes [r1+pArdx]dx Try it online!
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about 2 years ago
Edit Post #286283 Initial revision about 2 years ago
Answer A: Looping counter
[Bash], 17 bytes echo x$1;./$0 x$1 Try it online! Thanks to celtschk‭ for spotting my mistake :)
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about 2 years ago
Edit Post #286282 Initial revision about 2 years ago
Answer A: Looping counter
[Python 2], 26 bytes =1 while 1:=10;print- Try it online!
(more)
about 2 years ago
Edit Post #286281 Initial revision about 2 years ago
Answer A: Looping counter
[Python 3], 28 bytes ="" while 1:+="";print() Try it online!
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about 2 years ago
Edit Post #285932 Initial revision about 2 years ago
Answer A: It's Hip to be Square
[dc], 9 bytes ?dvd-^p Try it online! Comparisons are expensive in dc, so you have to get a bit creative. I came up with $0^{n-\lfloor\sqrt{n}\rfloor^2}$.
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about 2 years ago
Edit Post #285931 Initial revision about 2 years ago
Answer A: Make my value binary
[dc], 4 bytes 2o?p Try it online!
(more)
about 2 years ago
Comment Post #285903 `%#_ _` has 4 unique bytes, no?
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about 2 years ago
Edit Post #285886 Initial revision about 2 years ago
Answer A: Can you give me half?
dc, 3 unique bytes, 138 bytes This challenge is pretty easy if you aim for just 4 unique bytes. For example, you could push the stack depth repeatedly to get ascending integers, set the precision to something positive, divide and then print. ```dc zzzzk/p ``` And surely it can't go any lower, ...
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about 2 years ago